让我们把你的优秀和最喜欢的扩展方法列一个列表。
要求是必须发布完整的代码,以及如何使用它的示例和解释。
基于对这个主题的高度兴趣,我在Codeplex上建立了一个名为extensionoverflow的开源项目。
请将您的回答标记为接受,以便将代码放入Codeplex项目。
请张贴完整的源代码,而不是一个链接。
Codeplex上新闻:
24.08.2010 Codeplex页面现在在这里:http://extensionoverflow.codeplex.com/
11.11.2008 XmlSerialize / XmlDeserialize现在是实现和单元测试。
11.11.2008仍有发展空间。;-)现在就加入!
11.11.2008第三位贡献者加入了ExtensionOverflow,欢迎加入BKristensen
11.11.2008 FormatWith现在是实现和单元测试。
09.11.2008第二个贡献者加入ExtensionOverflow。欢迎来到chakrit。
我们需要更多的开发人员。: -)
09.11.2008 ThrowIfArgumentIsNull现已在Codeplex上实现和单元测试。
有时使用自定义分隔符在列表中选中的元素上写出字符串是很方便的。
例如,如果你有一个List<Person>并且想要用逗号分隔姓氏,你可以这样做。
string result = string.Empty;
foreach (var person in personList) {
result += person.LastName + ", ";
}
result = result.Substring(0, result.Length - 2);
return result;
或者你可以使用这个方便的扩展方法
public static string Join<T>(this IEnumerable<T> collection, Func<T, string> func, string separator)
{
return String.Join(separator, collection.Select(func).ToArray());
}
像这样使用它
personList.Join(x => x.LastName, ", ");
这将产生相同的结果,在本例中是由逗号分隔的姓氏列表。
字符串。As<T>,可用于将字符串值转换为某种类型(主要用于支持IConvertable的原语和类型)。工作伟大的空类型,甚至枚举!
public static partial class StringExtensions
{
/// <summary>
/// Converts the string to the specified type, using the default value configured for the type.
/// </summary>
/// <typeparam name="T">Type the string will be converted to. The type must implement IConvertable.</typeparam>
/// <param name="original">The original string.</param>
/// <returns>The converted value.</returns>
public static T As<T>(this String original)
{
return As(original, CultureInfo.CurrentCulture,
default(T));
}
/// <summary>
/// Converts the string to the specified type, using the default value configured for the type.
/// </summary>
/// <typeparam name="T">Type the string will be converted to.</typeparam>
/// <param name="original">The original string.</param>
/// <param name="defaultValue">The default value to use in case the original string is null or empty, or can't be converted.</param>
/// <returns>The converted value.</returns>
public static T As<T>(this String original, T defaultValue)
{
return As(original, CultureInfo.CurrentCulture, defaultValue);
}
/// <summary>
/// Converts the string to the specified type, using the default value configured for the type.
/// </summary>
/// <typeparam name="T">Type the string will be converted to.</typeparam>
/// <param name="original">The original string.</param>
/// <param name="provider">Format provider used during the type conversion.</param>
/// <returns>The converted value.</returns>
public static T As<T>(this String original, IFormatProvider provider)
{
return As(original, provider, default(T));
}
/// <summary>
/// Converts the string to the specified type.
/// </summary>
/// <typeparam name="T">Type the string will be converted to.</typeparam>
/// <param name="original">The original string.</param>
/// <param name="provider">Format provider used during the type conversion.</param>
/// <param name="defaultValue">The default value to use in case the original string is null or empty, or can't be converted.</param>
/// <returns>The converted value.</returns>
/// <remarks>
/// If an error occurs while converting the specified value to the requested type, the exception is caught and the default is returned. It is strongly recommended you
/// do NOT use this method if it is important that conversion failures are not swallowed up.
///
/// This method is intended to be used to convert string values to primatives, not for parsing, converting, or deserializing complex types.
/// </remarks>
public static T As<T>(this String original, IFormatProvider provider,
T defaultValue)
{
T result;
Type type = typeof (T);
if (String.IsNullOrEmpty(original)) result = defaultValue;
else
{
// need to get the underlying type if T is Nullable<>.
if (type.IsNullableType())
{
type = Nullable.GetUnderlyingType(type);
}
try
{
// ChangeType doesn't work properly on Enums
result = type.IsEnum
? (T) Enum.Parse(type, original, true)
: (T) Convert.ChangeType(original, type, provider);
}
catch // HACK: what can we do to minimize or avoid raising exceptions as part of normal operation? custom string parsing (regex?) for well-known types? it would be best to know if you can convert to the desired type before you attempt to do so.
{
result = defaultValue;
}
}
return result;
}
}
这依赖于Type的另一个简单扩展:
/// <summary>
/// Extension methods for <see cref="Type"/>.
/// </summary>
public static class TypeExtensions
{
/// <summary>
/// Returns whether or not the specified type is <see cref="Nullable{T}"/>.
/// </summary>
/// <param name="type">A <see cref="Type"/>.</param>
/// <returns>True if the specified type is <see cref="Nullable{T}"/>; otherwise, false.</returns>
/// <remarks>Use <see cref="Nullable.GetUnderlyingType"/> to access the underlying type.</remarks>
public static bool IsNullableType(this Type type)
{
if (type == null) throw new ArgumentNullException("type");
return type.IsGenericType && type.GetGenericTypeDefinition().Equals(typeof (Nullable<>));
}
}
用法:
var someInt = "1".As<int>();
var someIntDefault = "bad value".As(1); // "bad value" won't convert, so the default value 1 is returned.
var someEnum = "Sunday".As<DayOfWeek>();
someEnum = "0".As<DayOfWeek>(); // returns Sunday
var someNullableEnum = "".As<DayOfWeek?>(null); // returns a null value since "" can't be converted
public static class EnumerableExtensions
{
[Pure]
public static U MapReduce<T, U>(this IEnumerable<T> enumerable, Func<T, U> map, Func<U, U, U> reduce)
{
CodeContract.RequiresAlways(enumerable != null);
CodeContract.RequiresAlways(enumerable.Skip(1).Any());
CodeContract.RequiresAlways(map != null);
CodeContract.RequiresAlways(reduce != null);
return enumerable.AsParallel().Select(map).Aggregate(reduce);
}
[Pure]
public static U MapReduce<T, U>(this IList<T> list, Func<T, U> map, Func<U, U, U> reduce)
{
CodeContract.RequiresAlways(list != null);
CodeContract.RequiresAlways(list.Count >= 2);
CodeContract.RequiresAlways(map != null);
CodeContract.RequiresAlways(reduce != null);
U result = map(list[0]);
for (int i = 1; i < list.Count; i++)
{
result = reduce(result,map(list[i]));
}
return result;
}
//Parallel version; creates garbage
[Pure]
public static U MapReduce<T, U>(this IList<T> list, Func<T, U> map, Func<U, U, U> reduce)
{
CodeContract.RequiresAlways(list != null);
CodeContract.RequiresAlways(list.Skip(1).Any());
CodeContract.RequiresAlways(map != null);
CodeContract.RequiresAlways(reduce != null);
U[] mapped = new U[list.Count];
Parallel.For(0, mapped.Length, i =>
{
mapped[i] = map(list[i]);
});
U result = mapped[0];
for (int i = 1; i < list.Count; i++)
{
result = reduce(result, mapped[i]);
}
return result;
}
}
这个很有用:
public static IEnumerable<TResult> Zip<TFirst, TSecond, TResult>(this IEnumerable<TFirst> first, IEnumerable<TSecond> second, Func<TFirst, TSecond, TResult> selector)
{
if (first == null)
throw new ArgumentNullException("first");
if (second == null)
throw new ArgumentNullException("second");
if (selector == null)
throw new ArgumentNullException("selector");
using (var enum1 = first.GetEnumerator())
using (var enum2 = second.GetEnumerator())
{
while (enum1.MoveNext() && enum2.MoveNext())
{
yield return selector(enum1.Current, enum2.Current);
}
}
}
它在。net 4.0中被添加到Enumerable类中,但是在3.5中使用它很方便。
例子:
var names = new[] { "Joe", "Jane", "Jack", "John" };
var ages = new[] { 42, 22, 18, 33 };
var persons = names.Zip(ages, (n, a) => new { Name = n, Age = a });
foreach (var p in persons)
{
Console.WriteLine("{0} is {1} years old", p.Name, p.Age);
}
我喜欢下面这些方法来处理带有Flags属性集的枚举:
public static bool AnyOf(this object mask, object flags)
{
return ((int)mask & (int)flags) != 0;
}
public static bool AllOf(this object mask, object flags)
{
return ((int)mask & (int)flags) == (int)flags;
}
public static object SetOn(this object mask, object flags)
{
return (int)mask | (int)flags;
}
etc.
使用示例:
var options = SomeOptions.OptionA;
options = options.SetOn(OptionB);
options = options.SetOn(OptionC);
if (options.AnyOf(SomeOptions.OptionA | SomeOptions.OptionB))
{
etc.
原始方法来自本文:http://www.codeproject.com/KB/cs/masksandflags.aspx?display=Print
我只是把它们转换成扩展方法。
但它们的一个问题是对象类型的参数,这意味着所有对象最终都被这些方法扩展,而理想情况下,它们应该只应用于枚举。
更新
根据评论,你可以绕过“签名污染”,以牺牲性能为代价,如下所示:
public static bool AnyOf(this Enum mask, object flags)
{
return (Convert.ToInt642(mask) & (int)flags) != 0;
}
字符串。格式的快捷方式:
public static class StringExtensions
{
// Enable quick and more natural string.Format calls
public static string F(this string s, params object[] args)
{
return string.Format(s, args);
}
}
例子:
var s = "The co-ordinate is ({0}, {1})".F(point.X, point.Y);
要快速复制粘贴,请点击这里。
难道你不觉得输入“一些字符串”. f(“param”)而不是字符串更自然吗?格式(“一些字符串”,“参数”)?
想要一个更容易读懂的名字,试试下面的建议:
s = "Hello {0} world {1}!".Fmt("Stack", "Overflow");
s = "Hello {0} world {1}!".FormatBy("Stack", "Overflow");
s = "Hello {0} world {1}!".FormatWith("Stack", "Overflow");
s = "Hello {0} world {1}!".Display("Stack", "Overflow");
s = "Hello {0} world {1}!".With("Stack", "Overflow");
..