我刚来拉拉维尔。如何查找是否存在记录?

$user = User::where('email', '=', Input::get('email'));

我能做什么来查看$user是否有记录?


当前回答

if ($u = User::where('email', '=', $value)->first())
{
   // do something with $u
   return 'exists';
} else {
  return 'nope';
}

可以用try/catch吗

->get()仍然返回一个空数组

其他回答

if (User::where('email', 'user@email.com')->first()) {
    // It exists
} else {
    // It does not exist
}

如果只需要检查是否存在,请使用first(),而不要使用count()。

First()更快,因为它检查单个匹配,而count()计数所有匹配。

Laravel 6或顶部:写表名,然后给出where子句条件,例如where('id', $request->id)

 public function store(Request $request)
    {

        $target = DB:: table('categories')
                ->where('title', $request->name)
                ->get()->first();
        if ($target === null) { // do what ever you need to do
            $cat = new Category();
            $cat->title = $request->input('name');
            $cat->parent_id = $request->input('parent_id');
            $cat->user_id=auth()->user()->id;
            $cat->save();
            return redirect(route('cats.app'))->with('success', 'App created successfully.');

        }else{ // match found 
            return redirect(route('cats.app'))->with('error', 'App already exists.');
        }

    }

最短工作选项:

// if you need to do something with the user 
if ($user = User::whereEmail(Input::get('email'))->first()) {

    // ...

}

// otherwise
$userExists = User::whereEmail(Input::get('email'))->exists();
$user = User::where('email', request('email'))->first();
return (count($user) > 0 ? 'Email Exist' : 'Email Not Exist');

在laravel雄辩中,有默认的exists()方法,参考下面的例子。

if (User::where('id', $user_id )->exists()) {
    // your code...
}