我想获得MongoDB集合中所有键的名称。

例如,从这个:

db.things.insert( { type : ['dog', 'cat'] } );
db.things.insert( { egg : ['cat'] } );
db.things.insert( { type : [] } );
db.things.insert( { hello : []  } );

我想获得唯一的键:

type, egg, hello

当前回答

下面是用Python编写的示例: 这个示例内联返回结果。

from pymongo import MongoClient
from bson.code import Code

mapper = Code("""
    function() {
                  for (var key in this) { emit(key, null); }
               }
""")
reducer = Code("""
    function(key, stuff) { return null; }
""")

distinctThingFields = db.things.map_reduce(mapper, reducer
    , out = {'inline' : 1}
    , full_response = True)
## do something with distinctThingFields['results']

其他回答

我们可以通过使用mongo js文件来实现这一点。在getCollectionName.js文件中添加以下代码,并在Linux控制台中运行js文件,如下所示:

mongodb——host 192.168.1.135 getCollectionName.js

db_set = connect("192.168.1.135:27017/database_set_name"); // for Local testing
// db_set.auth("username_of_db", "password_of_db"); // if required

db_set.getMongo().setSlaveOk();

var collectionArray = db_set.getCollectionNames();

collectionArray.forEach(function(collectionName){

    if ( collectionName == 'system.indexes' || collectionName == 'system.profile' || collectionName == 'system.users' ) {
        return;
    }

    print("\nCollection Name = "+collectionName);
    print("All Fields :\n");

    var arrayOfFieldNames = []; 
    var items = db_set[collectionName].find();
    // var items = db_set[collectionName].find().sort({'_id':-1}).limit(100); // if you want fast & scan only last 100 records of each collection
    while(items.hasNext()) {
        var item = items.next(); 
        for(var index in item) {
            arrayOfFieldNames[index] = index;
        }
    }
    for (var index in arrayOfFieldNames) {
        print(index);
    }

});

quit();

由于@ackuser

这对我来说很有效:

var arrayOfFieldNames = [];

var items = db.NAMECOLLECTION.find();

while(items.hasNext()) {
  var item = items.next();
  for(var index in item) {
    arrayOfFieldNames[index] = index;
   }
}

for (var index in arrayOfFieldNames) {
  print(index);
}

使用python。返回集合中所有顶级键的集合:

#Using pymongo and connection named 'db'

reduce(
    lambda all_keys, rec_keys: all_keys | set(rec_keys), 
    map(lambda d: d.keys(), db.things.find()), 
    set()
)

下面是用Python编写的示例: 这个示例内联返回结果。

from pymongo import MongoClient
from bson.code import Code

mapper = Code("""
    function() {
                  for (var key in this) { emit(key, null); }
               }
""")
reducer = Code("""
    function(key, stuff) { return null; }
""")

distinctThingFields = db.things.map_reduce(mapper, reducer
    , out = {'inline' : 1}
    , full_response = True)
## do something with distinctThingFields['results']

如果你的目标集合不是很大,你可以在mongo shell客户端下尝试:

var allKeys = {};

db.YOURCOLLECTION.find().forEach(function(doc){Object.keys(doc).forEach(function(key){allKeys[key]=1})});

allKeys;