我感兴趣的是从数据库表中选择第n行的一些(理想的)数据库不可知的方法。看看如何使用以下数据库的本机功能来实现这一点也很有趣:

SQL Server MySQL PostgreSQL SQLite 甲骨文

我目前正在SQL Server 2005中做以下事情,但我有兴趣看到其他更不可知论的方法:

WITH Ordered AS (
SELECT ROW_NUMBER() OVER (ORDER BY OrderID) AS RowNumber, OrderID, OrderDate
FROM Orders)
SELECT *
FROM Ordered
WHERE RowNumber = 1000000

以上SQL: Firoz Ansari的Weblog的功劳

更新:参见Troels Arvin关于SQL标准的回答。Troels,你有我们可以引用的链接吗?


当前回答

如果你想查看本机功能: MySQL, PostgreSQL, SQLite和Oracle(基本上SQL Server似乎没有这个函数),你实际上可以使用NTH_VALUE窗口函数。 Oracle来源:Oracle函数:NTH_VALUE

实际上,我已经在我们的Oracle DB中对此进行了一些实验,以比较第一行(排序后)和第二行(同样是排序后)。 代码看起来像这样(如果你不想去链接):

SELECT DISTINCT dept_id
     , NTH_VALUE(salary,2) OVER (PARTITION BY dept_id ORDER BY salary DESC
           RANGE BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) 
        AS "SECOND HIGHEST"
     , NTH_VALUE(salary,3) OVER (PARTITION BY dept_id ORDER BY salary DESC
           RANGE BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING)
        AS "THIRD HIGHEST"
  FROM employees
 WHERE dept_id in (10,20)
 ORDER 
    BY dept_id;

我发现它很有趣,我希望他们能让我用它。

其他回答

我不确定其他的,但我知道SQLite和MySQL没有任何“默认”行排序。至少在这两种方言中,下面的代码片段从the_table中抓取了第15个条目,按添加的日期/时间排序:

SELECT * 
FROM the_table 
ORDER BY added DESC 
LIMIT 1,15

(当然,您需要添加一个DATETIME字段,并将其设置为条目添加的日期/时间…)

SQL 2005及以上版本内置了这个特性。使用ROW_NUMBER()函数。它非常适合浏览<< Prev和Next >>样式的网页:

语法:

SELECT
    *
FROM
    (
        SELECT
            ROW_NUMBER () OVER (ORDER BY MyColumnToOrderBy) AS RowNum,
            *
        FROM
            Table_1
    ) sub
WHERE
    RowNum = 23

从表中选择N个记录号

select * from
 (select row_number() over (order by Rand() desc) as Rno,* from TableName) T where T.Rno = RecordNumber

Where  RecordNumber --> Record Number to Select
       TableName --> To be Replaced with your Table Name

例如,要从表Employee中选择第5条记录,您的查询应该是

select * from
 (select row_number() over (order by Rand() desc) as Rno,* from Employee) T where T.Rno = 5

我在这里有点晚了,但我已经在不需要窗口或使用的情况下做到了这一点

WHERE x IN (...)
SELECT TOP 1
--select the value needed from t1
[col2]
FROM
(
   SELECT TOP 2 --the Nth row, alter this to taste
   UE2.[col1],
   UE2.[col2],
   UE2.[date],
   UE2.[time],
   UE2.[UID]
   FROM
   [table1] AS UE2
   WHERE
   UE2.[col1] = ID --this is a subquery 
   AND
   UE2.[col2] IS NOT NULL
   ORDER BY
   UE2.[date] DESC, UE2.[time] DESC --sorting by date and time newest first
) AS t1
ORDER BY t1.[date] ASC, t1.[time] ASC --this reverses the order of the sort in t1

它似乎工作得相当快,尽管公平地说,我只有大约500行数据

这在MSSQL中有效

SQL SERVER


从顶部选择第n条记录

SELECT * FROM (
SELECT 
ID, NAME, ROW_NUMBER() OVER(ORDER BY ID) AS ROW
FROM TABLE 
) AS TMP 
WHERE ROW = n

从底部选择第n条记录

SELECT * FROM (
SELECT 
ID, NAME, ROW_NUMBER() OVER(ORDER BY ID DESC) AS ROW
FROM TABLE 
) AS TMP 
WHERE ROW = n