通过使用Http,我们调用一个方法来进行网络调用,并返回一个Http可观察对象:
getCustomer() {
return this.http.get('/someUrl').map(res => res.json());
}
如果我们获取这个可观察对象并向其添加多个订阅者:
let network$ = getCustomer();
let subscriber1 = network$.subscribe(...);
let subscriber2 = network$.subscribe(...);
我们要做的是确保这不会导致多个网络请求。
这似乎是一个不寻常的场景,但实际上很常见:例如,如果调用者订阅了可观察对象以显示错误消息,并使用异步管道将其传递给模板,那么我们已经有两个订阅者了。
在RxJs 5中正确的方法是什么?
也就是说,这似乎工作得很好:
getCustomer() {
return this.http.get('/someUrl').map(res => res.json()).share();
}
但是这是RxJs 5中惯用的方法吗,或者我们应该用别的方法来代替?
注意:根据Angular 5的新HttpClient,所有示例中的.map(res => res. JSON())部分现在都是无用的,因为现在默认假设JSON结果。
只需在map之后和任何订阅之前调用share()。
在我的例子中,我有一个通用服务(RestClientService.ts),它进行其余调用,提取数据,检查错误,并将可观察对象返回到具体的实现服务(f.ex)。: ContractClientService.ts),最后这个具体的实现将可观察对象返回给de ContractComponent。Ts,这个订阅来更新视图。
RestClientService.ts:
export abstract class RestClientService<T extends BaseModel> {
public GetAll = (path: string, property: string): Observable<T[]> => {
let fullPath = this.actionUrl + path;
let observable = this._http.get(fullPath).map(res => this.extractData(res, property));
observable = observable.share(); //allows multiple subscribers without making again the http request
observable.subscribe(
(res) => {},
error => this.handleError2(error, "GetAll", fullPath),
() => {}
);
return observable;
}
private extractData(res: Response, property: string) {
...
}
private handleError2(error: any, method: string, path: string) {
...
}
}
ContractService.ts:
export class ContractService extends RestClientService<Contract> {
private GET_ALL_ITEMS_REST_URI_PATH = "search";
private GET_ALL_ITEMS_PROPERTY_PATH = "contract";
public getAllItems(): Observable<Contract[]> {
return this.GetAll(this.GET_ALL_ITEMS_REST_URI_PATH, this.GET_ALL_ITEMS_PROPERTY_PATH);
}
}
ContractComponent.ts:
export class ContractComponent implements OnInit {
getAllItems() {
this.rcService.getAllItems().subscribe((data) => {
this.items = data;
});
}
}
我写了一个缓存类,
/**
* Caches results returned from given fetcher callback for given key,
* up to maxItems results, deletes the oldest results when full (FIFO).
*/
export class StaticCache
{
static cachedData: Map<string, any> = new Map<string, any>();
static maxItems: number = 400;
static get(key: string){
return this.cachedData.get(key);
}
static getOrFetch(key: string, fetcher: (string) => any): any {
let value = this.cachedData.get(key);
if (value != null){
console.log("Cache HIT! (fetcher)");
return value;
}
console.log("Cache MISS... (fetcher)");
value = fetcher(key);
this.add(key, value);
return value;
}
static add(key, value){
this.cachedData.set(key, value);
this.deleteOverflowing();
}
static deleteOverflowing(): void {
if (this.cachedData.size > this.maxItems) {
this.deleteOldest(this.cachedData.size - this.maxItems);
}
}
/// A Map object iterates its elements in insertion order — a for...of loop returns an array of [key, value] for each iteration.
/// However that seems not to work. Trying with forEach.
static deleteOldest(howMany: number): void {
//console.debug("Deleting oldest " + howMany + " of " + this.cachedData.size);
let iterKeys = this.cachedData.keys();
let item: IteratorResult<string>;
while (howMany-- > 0 && (item = iterKeys.next(), !item.done)){
//console.debug(" Deleting: " + item.value);
this.cachedData.delete(item.value); // Deleting while iterating should be ok in JS.
}
}
static clear(): void {
this.cachedData = new Map<string, any>();
}
}
由于我们使用它的方式不同,所以它都是静态的,但是可以随意地将它变成一个正常的类和服务。我不确定angular是否会一直保持一个实例(对于Angular2来说是新的)。
我是这样使用它的:
let httpService: Http = this.http;
function fetcher(url: string): Observable<any> {
console.log(" Fetching URL: " + url);
return httpService.get(url).map((response: Response) => {
if (!response) return null;
if (typeof response.json() !== "array")
throw new Error("Graph REST should return an array of vertices.");
let items: any[] = graphService.fromJSONarray(response.json(), httpService);
return array ? items : items[0];
});
}
// If data is a link, return a result of a service call.
if (this.data[verticesLabel][name]["link"] || this.data[verticesLabel][name]["_type"] == "link")
{
// Make an HTTP call.
let url = this.data[verticesLabel][name]["link"];
let cachedObservable: Observable<any> = StaticCache.getOrFetch(url, fetcher);
if (!cachedObservable)
throw new Error("Failed loading link: " + url);
return cachedObservable;
}
我认为可能有更聪明的方法,使用一些可观察的技巧,但这对我的目的来说已经很好了。
上面的大多数答案都适用于不接受输入的http请求。每次你想要使用一些输入进行api调用时,都需要重新创建请求。上面唯一可以处理这个问题的回复是@Arlo的回复。
我已经创建了一个稍微简单的装饰器,您可以使用它将响应共享给每个具有相同输入的调用者。与Arlo的回复不同,它不会对延迟的订阅者重放响应,而是将同时发生的请求作为一个请求来处理。如果目标是重放响应给延迟的观察者(也就是缓存的响应),你可以修改下面的代码并用shaereplay(1)替换share():
https://gist.github.com/OysteinAmundsen/b97a2359292463feb8c0e2270ed6695a
import { finalize, Observable, share } from 'rxjs';
export function SharedObservable(): MethodDecorator {
const obs$ = new Map<string, Observable<any>>();
return (target: any, propertyKey: string | symbol, descriptor: PropertyDescriptor) => {
const originalMethod = descriptor.value;
descriptor.value = function (...args: any[]) {
const key = JSON.stringify(args);
if (!obs$.has(key)) {
// We have no observable for this key yet, so we create one
const res = originalMethod.apply(this, args).pipe(
share(), // Make the observable hot
finalize(() => obs$.delete(key)) // Cleanup when observable is complete
);
obs$.set(key, res);
}
// Return the cached observable
return obs$.get(key);
};
return descriptor;
};
}
用法:
@SharedObservable()
myFunc(id: number): Observable<any> {
return this.http.get<any>(`/api/someUrl/${id}`);
}
RXJS 5.3.0
我对.map(myFunction).publishReplay(1).refCount()不满意
对于多个订阅者,.map()在某些情况下执行myFunction两次(我希望它只执行一次)。一个修复似乎是publishReplay(1).refCount().take(1)
你可以做的另一件事,就是不使用refCount(),让Observable立即热:
let obs = this.http.get('my/data.json').publishReplay(1);
obs.connect();
return obs;
这将启动HTTP请求,而不考虑订阅者。我不确定在HTTP GET完成之前取消订阅是否会取消它。