如何在另一个字符串的特定索引处插入一个字符串?

 var txt1 = "foo baz"

假设我想在“foo”之后插入“bar”,我该如何实现呢?

我想到了substring(),但一定有一个更简单更直接的方法。


当前回答

您可以将自己的splice()原型化为String。

Polyfill

if (!String.prototype.splice) {
    /**
     * {JSDoc}
     *
     * The splice() method changes the content of a string by removing a range of
     * characters and/or adding new characters.
     *
     * @this {String}
     * @param {number} start Index at which to start changing the string.
     * @param {number} delCount An integer indicating the number of old chars to remove.
     * @param {string} newSubStr The String that is spliced in.
     * @return {string} A new string with the spliced substring.
     */
    String.prototype.splice = function(start, delCount, newSubStr) {
        return this.slice(0, start) + newSubStr + this.slice(start + Math.abs(delCount));
    };
}

例子

String.prototype.splice = function(idx, rem, str) { 返回 this.slice(0, idx) + str + this.slice(idx + Math.abs(rem)); }; var result = “foo baz”.splice(4, 0, “bar ”); document.body.innerHTML = result;“嘟”


EDIT:修改它,以确保rem是一个绝对值。

其他回答

下面是我写的一个像所有其他编程语言一样的方法:

string .prototype.insert =函数(索引,字符串){ If (index > 0) { 返回。子字符串(0,index) +字符串+ this。substring(指数、this.length); } 返回string + this; }; //使用示例: var something =“你好吗?”; 某事=某事。插入(3,“are”); console.log(东西)

参考:

http://coderamblings.wordpress.com/2012/07/09/insert-a-string-at-a-specific-index/

从字符串实例化一个数组 使用数组#拼接 再次使用array# join进行Stringify

这种方法的好处有两方面:

简单的 Unicode编码点兼容

const pair = Array.from('USDGBP') 对。Splice (3,0, '/') console.log (pair.join ("))

更新2016:下面是另一个基于一行RegExp方法的原型函数(在未定义或负索引上提供prepend支持):

/**
 * Insert `what` to string at position `index`.
 */
String.prototype.insert = function(what, index) {
    return index > 0
        ? this.replace(new RegExp('.{' + index + '}'), '$&' + what)
        : what + this;
};

console.log( 'foo baz'.insert('bar ', 4) );  // "foo bar baz"
console.log( 'foo baz'.insert('bar ')    );  // "bar foo baz"

之前(回到2012年)只是为了好玩的解决方案:

var index = 4,
    what  = 'bar ';

'foo baz'.replace(/./g, function(v, i) {
    return i === index - 1 ? v + what : v;
});  // "foo bar baz"

以溶液为例。我用简单的格式写了这段代码:

const insertWord = (sentence,word,index) => {
    var sliceWord = word.slice(""),output = [],join; // Slicing the input word and declaring other variables
    var sliceSentence = sentence.slice(""); // Slicing the input sentence into each alphabets
    for (var i = 0; i < sliceSentence.length; i++) 
           {
        if (i === index) 
               { // checking if index of array === input index
            for (var j = 0; j < word.length; j++) 
                       {   // if yes we'll insert the word
                output.push(sliceWord[j]); // Condition is true we are inserting the word
                       }
            output.push(" "); // providing a single space at the end of the word
                 }
        output.push(sliceSentence[i]);  // pushing the remaining elements present in an array
            }
    join = output.join(""); // converting an array to string
    console.log(join)
    return join;
}

您可以将自己的splice()原型化为String。

Polyfill

if (!String.prototype.splice) {
    /**
     * {JSDoc}
     *
     * The splice() method changes the content of a string by removing a range of
     * characters and/or adding new characters.
     *
     * @this {String}
     * @param {number} start Index at which to start changing the string.
     * @param {number} delCount An integer indicating the number of old chars to remove.
     * @param {string} newSubStr The String that is spliced in.
     * @return {string} A new string with the spliced substring.
     */
    String.prototype.splice = function(start, delCount, newSubStr) {
        return this.slice(0, start) + newSubStr + this.slice(start + Math.abs(delCount));
    };
}

例子

String.prototype.splice = function(idx, rem, str) { 返回 this.slice(0, idx) + str + this.slice(idx + Math.abs(rem)); }; var result = “foo baz”.splice(4, 0, “bar ”); document.body.innerHTML = result;“嘟”


EDIT:修改它,以确保rem是一个绝对值。