//Turn off submit on "Enter" key

$("form").bind("keypress", function (e) {
    if (e.keyCode == 13) {
        $("#btnSearch").attr('value');
        //add more buttons here
        return false;
    }
});

你会发现这更简单和有用:D

$(document).on('submit', 'form', function(e){
    /* on form submit find the trigger */
    if( $(e.delegateTarget.activeElement).not('input, textarea').length == 0 ){
        /* if the trigger is not between selectors list, return super false */
        e.preventDefault();
        return false;
    } 
});

在我的案例中，这个jQuery JavaScript解决了这个问题

jQuery(function() {
            jQuery("form.myform").submit(function(event) {
               event.preventDefault();
               return false;
            });
}

I Have come across this myself because I have multiple submit buttons with different 'name' values, so that when submitted they do different things on the same php file. The enter / return button breaks this as those values aren't submitted. So I was thinking, does the enter / return button activate the first submit button in the form? That way you could have a 'vanilla' submit button that is either hidden or has a 'name' value that returns the executing php file back to the page with the form in it. Or else a default (hidden) 'name' value that the keypress activates, and the submit buttons overwrite with their own 'name' values. Just a thought.

你将不得不调用这个函数，它将取消表单的默认提交行为。您可以将它附加到任何输入字段或事件。

function doNothing() {  
var keyCode = event.keyCode ? event.keyCode : event.which ? event.which : event.charCode;
    if( keyCode == 13 ) {


    if(!e) var e = window.event;

    e.cancelBubble = true;
    e.returnValue = false;

    if (e.stopPropagation) {
        e.stopPropagation();
        e.preventDefault();
    }
}

[2012修订版，没有内联处理程序，保留textarea进入处理]

function checkEnter(e){
 e = e || event;
 var txtArea = /textarea/i.test((e.target || e.srcElement).tagName);
 return txtArea || (e.keyCode || e.which || e.charCode || 0) !== 13;
}

现在你可以在表单上定义一个按键处理程序: <形式[…onkeypress="return checkEnter(event)">

document.querySelector('form').onkeypress = checkEnter;