如何使用JSP/Servlet上传文件到服务器?

我试了一下:

<form action="upload" method="post">
    <input type="text" name="description" />
    <input type="file" name="file" />
    <input type="submit" />
</form>

但是,我只得到了文件名,而不是文件内容。当我添加enctype="multipart/form-data"到<form>时,request.getParameter()返回null。

在研究过程中,我偶然发现了Apache Common FileUpload。我试了一下:

FileItemFactory factory = new DiskFileItemFactory();
ServletFileUpload upload = new ServletFileUpload(factory);
List items = upload.parseRequest(request); // This line is where it died.

不幸的是,servlet抛出了一个异常,没有明确的消息和原因。下面是stacktrace:

SEVERE: Servlet.service() for servlet UploadServlet threw exception
javax.servlet.ServletException: Servlet execution threw an exception
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:313)
    at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206)
    at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233)
    at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191)
    at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127)
    at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102)
    at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109)
    at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298)
    at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:852)
    at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588)
    at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489)
    at java.lang.Thread.run(Thread.java:637)

当前回答

您需要将common-io.1.4.jar文件包含在lib目录中,或者如果您在任何编辑器中工作,例如NetBeans,那么您需要转到项目属性并添加JAR文件,然后就完成了。

要获得common.io.jar文件,只需谷歌它,或者只需访问Apache Tomcat网站,在那里您可以获得免费下载该文件的选项。但请记住一件事:如果您是Windows用户,请下载二进制ZIP文件。

其他回答

HTML页面

<html>
    <head>
        <title>File Uploading Form</title>
    </head>

    <body>
        <h3>File Upload:</h3>
        Select a file to upload: <br />
        <form action="UploadServlet" method="post"
              enctype="multipart/form-data">

            <input type="file" name="file" size="50" />
            <br />
            <input type="submit" value="Upload File" />
        </form>
    </body>
</html>

Servlet文件

// Import required java libraries
import java.io.*;
import java.util.*;

import javax.servlet.ServletConfig;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.apache.commons.fileupload.FileItem;
import org.apache.commons.fileupload.FileUploadException;
import org.apache.commons.fileupload.disk.DiskFileItemFactory;
import org.apache.commons.fileupload.servlet.ServletFileUpload;
import org.apache.commons.io.output.*;

public class UploadServlet extends HttpServlet {

    private boolean isMultipart;
    private String filePath;
    private int maxFileSize = 50 * 1024;
    private int maxMemSize = 4 * 1024;
    private File file;

    public void init() {
        // Get the file location where it would be stored.
        filePath =
               getServletContext().getInitParameter("file-upload");
    }

    public void doPost(HttpServletRequest request,
                       HttpServletResponse response)
               throws ServletException, java.io.IOException {

        // Check that we have a file upload request
        isMultipart = ServletFileUpload.isMultipartContent(request);
        response.setContentType("text/html");
        java.io.PrintWriter out = response.getWriter();
        if (!isMultipart) {
            out.println("<html>");
            out.println("<head>");
            out.println("<title>Servlet upload</title>");
            out.println("</head>");
            out.println("<body>");
            out.println("<p>No file uploaded</p>");
            out.println("</body>");
            out.println("</html>");
            return;
        }

        DiskFileItemFactory factory = new DiskFileItemFactory();
        // Maximum size that will be stored in memory
        factory.setSizeThreshold(maxMemSize);
        // Location to save data that is larger than maxMemSize.
        factory.setRepository(new File("c:\\temp"));

        // Create a new file upload handler
        ServletFileUpload upload = new ServletFileUpload(factory);
        // maximum file size to be uploaded.
        upload.setSizeMax(maxFileSize);

        try {
            // Parse the request to get file items.
            List fileItems = upload.parseRequest(request);

            // Process the uploaded file items
            Iterator i = fileItems.iterator();

            out.println("<html>");
            out.println("<head>");
            out.println("<title>Servlet upload</title>");
            out.println("</head>");
            out.println("<body>");
            while (i.hasNext())
            {
                FileItem fi = (FileItem)i.next();
                if (!fi.isFormField())
                {
                     // Get the uploaded file parameters
                     String fieldName = fi.getFieldName();
                     String fileName = fi.getName();
                     String contentType = fi.getContentType();
                     boolean isInMemory = fi.isInMemory();
                     long sizeInBytes = fi.getSize();

                     // Write the file
                     if (fileName.lastIndexOf("\\") >= 0) {
                         file = new File(filePath +
                         fileName.substring(fileName.lastIndexOf("\\")));
                     }
                     else {
                         file = new File(filePath +
                         fileName.substring(fileName.lastIndexOf("\\") + 1));
                     }
                     fi.write(file);
                     out.println("Uploaded Filename: " + fileName + "<br>");
                }
            }
            out.println("</body>");
            out.println("</html>");
        }
        catch(Exception ex) {
            System.out.println(ex);
        }
    }

    public void doGet(HttpServletRequest request,
                        HttpServletResponse response)
            throws ServletException, java.io.IOException {

        throw new ServletException("GET method used with " +
                 getClass().getName() + ": POST method required.");
    }
}

文件web . xml

编译上面的servlet UploadServlet并在web.xml文件中创建所需的条目,如下所示。

<servlet>
   <servlet-name>UploadServlet</servlet-name>
   <servlet-class>UploadServlet</servlet-class>
</servlet>

<servlet-mapping>
   <servlet-name>UploadServlet</servlet-name>
   <url-pattern>/UploadServlet</url-pattern>
</servlet-mapping>

对于Spring MVC

我设法有一个更简单的版本,用于获取表单输入,包括数据和图像。

<form action="/handleform" method="post" enctype="multipart/form-data">
    <input type="text" name="name" />
    <input type="text" name="age" />
    <input type="file" name="file" />
    <input type="submit" />
</form>

要处理的控制器

@Controller
public class FormController {
    @RequestMapping(value="/handleform",method= RequestMethod.POST)
    ModelAndView register(@RequestParam String name, @RequestParam int age, @RequestParam MultipartFile file)
            throws ServletException, IOException {

        System.out.println(name);
        System.out.println(age);
        if(!file.isEmpty()){
            byte[] bytes = file.getBytes();
            String filename = file.getOriginalFilename();
            BufferedOutputStream stream =new BufferedOutputStream(new FileOutputStream(new File("D:/" + filename)));
            stream.write(bytes);
            stream.flush();
            stream.close();
        }
        return new ModelAndView("index");
    }
}

首先你必须将表单的enctype属性设置为"multipart/form-data"

如下所示。

<form action="Controller" method="post" enctype="multipart/form-data">
     <label class="file-upload"> Click here to upload an Image </label>
     <input type="file" name="file" id="file" required>
</form>

然后,在Servlet“控制器”中添加用于多部分的注释,以指示在Servlet中处理多部分数据。

完成此操作后,检索通过表单发送的部分,然后检索提交文件的文件名(带路径)。使用它在所需的路径中创建一个新文件,并将文件的部分写入新创建的文件以重新创建该文件。

如下图所示:

@MultipartConfig

public class Controller extends HttpServlet {

    protected void doPost(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        insertImage(request, response);
    }

    private void addProduct(HttpServletRequest request, HttpServletResponse response) {
        Part filePart = request.getPart("file");
        String imageName = Paths.get(filePart.getSubmittedFileName()).getFileName().toString();

        String imageSavePath = "specify image path to save image"; //path to save image
        FileOutputStream outputStream = null;
        InputStream fileContent = null;

        try {
            outputStream = new FileOutputStream(new File(imageSavePath + File.separator + imageName));
            // Creating a new file with file path and the file name
            fileContent = filePart.getInputStream();
            // Getting the input stream
            int readBytes = 0;
            byte[] readArray = new byte[1024];
            // Initializing a byte array with size 1024

            while ((readBytes = fileContent.read(readArray)) != -1) {
                outputStream.write(readArray, 0, readBytes);
            } // This loop will write the contents of the byte array unitl the end to the output stream
        } catch (Exception ex) {
            System.out.println("Error Writing File: " + ex);
        } finally {
            if (outputStream != null) {
                outputStream.close();
                // Closing the output stream
            }
            if (fileContent != null) {
                fileContent.close();
                // Closing the input stream
            }
        }
    }
}

下面是一个使用apache common -fileupload的例子:

// apache commons-fileupload to handle file upload
DiskFileItemFactory factory = new DiskFileItemFactory();
factory.setRepository(new File(DataSources.TORRENTS_DIR()));
ServletFileUpload fileUpload = new ServletFileUpload(factory);

List<FileItem> items = fileUpload.parseRequest(req.raw());
FileItem item = items.stream()
  .filter(e ->
  "the_upload_name".equals(e.getFieldName()))
  .findFirst().get();
String fileName = item.getName();

item.write(new File(dir, fileName));
log.info(fileName);

对于文件和输入控件,我能想到的最简单的方法是:

  <%
      if (request.getContentType() == null)
          return;
      // For input type=text controls
      String v_Text =
          (new BufferedReader(new InputStreamReader(request.getPart("Text1").getInputStream()))).readLine();

      // For input type=file controls
      InputStream inStr = request.getPart("File1").getInputStream();
      char charArray[] = new char[inStr.available()];
      new InputStreamReader(inStr).read(charArray);
      String contents = new String(charArray);
  %>