有没有一种方法告诉AutoMapper忽略所有的属性,除了那些显式映射的?
我有可能从外部更改的外部DTO类,并且我希望避免显式地指定要忽略的每个属性,因为添加新属性将在尝试将它们映射到自己的对象时破坏功能(导致异常)。
有没有一种方法告诉AutoMapper忽略所有的属性,除了那些显式映射的?
我有可能从外部更改的外部DTO类,并且我希望避免显式地指定要忽略的每个属性,因为添加新属性将在尝试将它们映射到自己的对象时破坏功能(导致异常)。
当前回答
您希望如何指定忽略某些成员?是否有您想要应用的约定、基类或属性?一旦您开始显式地指定所有映射,我不确定您能从AutoMapper中得到什么价值。
其他回答
您希望如何指定忽略某些成员?是否有您想要应用的约定、基类或属性?一旦您开始显式地指定所有映射,我不确定您能从AutoMapper中得到什么价值。
The only infromation about ignoring many of members is this thread - http://groups.google.com/group/automapper-users/browse_thread/thread/9928ce9f2ffa641f . I think you can use the trick used in ProvidingCommonBaseClassConfiguration to ignore common properties for similar classes. And there is no information about the "Ignore the rest" functionality. I've looked at the code before and it seems to me that will be very and very hard to add such functionality. Also you can try to use some attribute and mark with it ignored properties and add some generic/common code to ignore all marked properties.
版本12 这是一个非常糟糕的代码,但它解决了紧急工作。
CreateMap<RepairPutRequest, Repair>(MemberList.None)
.ForAbdusselamMember(x => x.ClosedLostTimeId, y => y.MapFrom(z => z.ClosedLostTimeId))
.ForAbdusselamMember(x => x.Explanation, y => y.MapFrom(z => z.Explanation)).IgnoreUnmapped()
;
public static class MappingExtensions
{
public static Dictionary<string, List<string>> list = new Dictionary<string, List<string>>();
public static IMappingExpression<TSource, TDestination> IgnoreUnmapped<TSource, TDestination>(this IMappingExpression<TSource, TDestination> expression)
{
var sourceType = typeof(TSource);
var destinationType = typeof(TDestination);
var key =$"{sourceType.FullName}__||__{destinationType.FullName}" ;
var t = list[key];
foreach (var item in destinationType.GetProperties())
{
if (!t.Contains(item.Name)) {
expression.ForMember(item.Name, x => x.Ignore());
}
}
return expression;
}
public static IMappingExpression<TSource, TDestination> ForAbdusselamMember<TSource, TDestination, TMember>(this IMappingExpression<TSource, TDestination> expression,
Expression<Func<TDestination, TMember>> destinationMember, Action<IMemberConfigurationExpression<TSource, TDestination, TMember>> memberOptions )
{
var sourceType = typeof(TSource);
var destinationType = typeof(TDestination);
var key = $"{sourceType.FullName}__||__{destinationType.FullName}";
if (!list.ContainsKey(key))
{
list[key]=new List<string>();
}
expression.ForMember(destinationMember, memberOptions);
var memberInfo = ReflectionHelper.FindProperty(destinationMember);
list[key].Add(memberInfo.Name);
return expression;
}
}
根据我的理解,这个问题是,目标上的字段在源中没有映射字段,这就是为什么您要寻找方法来忽略那些非映射的目标字段。
而不是实现和使用这些扩展方法,您可以简单地使用
Mapper.CreateMap<sourceModel, destinationModel>(MemberList.Source);
现在,automapper知道它只需要验证所有源字段都映射了,而不是相反。
你还可以使用:
Mapper.CreateMap<sourceModel, destinationModel>(MemberList.Destination);
我更新了Robert Schroeder对AutoMapper 4.2的答案。对于非静态映射器配置,我们不能使用mapper . getalltypemaps(),但表达式有一个对所需的TypeMap的引用:
public static IMappingExpression<TSource, TDestination>
IgnoreAllNonExisting<TSource, TDestination>(this IMappingExpression<TSource, TDestination> expression)
{
foreach (var property in expression.TypeMap.GetUnmappedPropertyNames())
{
expression.ForMember(property, opt => opt.Ignore());
}
return expression;
}