返回任意次数的字符串的最佳或最简洁的方法是什么?

以下是我目前为止拍得最好的照片:

function repeat(s, n){
    var a = [];
    while(a.length < n){
        a.push(s);
    }
    return a.join('');
}

当前回答

使用分治法的递归解:

function repeat(n, s) {
    if (n==0) return '';
    if (n==1 || isNaN(n)) return s;
    with(Math) { return repeat(floor(n/2), s)+repeat(ceil(n/2), s); }
}

其他回答

/**  
@desc: repeat string  
@param: n - times  
@param: d - delimiter  
*/

String.prototype.repeat = function (n, d) {
    return --n ? this + (d || '') + this.repeat(n, d) : '' + this
};

这是如何重复字符串多次使用delimeter。

ES-Next有很多方法

1. ES2015/ES6已经实现了这个repeat()方法!

/** * str: String * count: Number */ const str = `hello repeat!\n`, count = 3; let resultString = str.repeat(count); console.log(`resultString = \n${resultString}`); /* resultString = hello repeat! hello repeat! hello repeat! */ ({ toString: () => 'abc', repeat: String.prototype.repeat }).repeat(2); // 'abcabc' (repeat() is a generic method) // Examples 'abc'.repeat(0); // '' 'abc'.repeat(1); // 'abc' 'abc'.repeat(2); // 'abcabc' 'abc'.repeat(3.5); // 'abcabcabc' (count will be converted to integer) // 'abc'.repeat(1/0); // RangeError // 'abc'.repeat(-1); // RangeError

2. ES2017/ES8新增String.prototype.padStart()

Const STR = 'abc '; Const times = 3; const newStr = str. padstartlength * times, str.toUpperCase()); console.log(' newStr = ', newStr); // "newStr =" "ABC ABC ABC "

3.ES2017/ES8新增String.prototype.padEnd()

Const STR = 'abc '; Const times = 3; const newStr = str. padend (str。length * times, str.toUpperCase()); console.log(' newStr = ', newStr); // "newStr =" "abc abc abc "

refs

http://www.ecma-international.org/ecma-262/6.0/#sec-string.prototype.repeat

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/repeat

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/padStart

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/padEnd

我已经测试了所有提议的方法的性能。

这是我找到的最快的变种。

String.prototype.repeat = function(count) {
    if (count < 1) return '';
    var result = '', pattern = this.valueOf();
    while (count > 1) {
        if (count & 1) result += pattern;
        count >>= 1, pattern += pattern;
    }
    return result + pattern;
};

或作为独立函数:

function repeat(pattern, count) {
    if (count < 1) return '';
    var result = '';
    while (count > 1) {
        if (count & 1) result += pattern;
        count >>= 1, pattern += pattern;
    }
    return result + pattern;
}

它基于wnrph算法。 它真的很快。与传统的Array(count + 1).join(string)方法相比,计数越大,它的运行速度就越快。

我只改变了两件事:

replace pattern = this with pattern = this. valueof()(清除一个明显的类型转换); 增加if (count < 1)检查从prototypejs到函数的顶部,以排除在这种情况下不必要的操作。 应用优化从丹尼斯的答案(5-7%的速度提高)

UPD

为感兴趣的人准备了一个性能测试场地。

变量计数~ 0 ..100:

常量= 1024:

如果可以的话,使用它,让它更快:)

各种方法的测试:

var repeatMethods = {
    control: function (n,s) {
        /* all of these lines are common to all methods */
        if (n==0) return '';
        if (n==1 || isNaN(n)) return s;
        return '';
    },
    divideAndConquer:   function (n, s) {
        if (n==0) return '';
        if (n==1 || isNaN(n)) return s;
        with(Math) { return arguments.callee(floor(n/2), s)+arguments.callee(ceil(n/2), s); }
    },
    linearRecurse: function (n,s) {
        if (n==0) return '';
        if (n==1 || isNaN(n)) return s;
        return s+arguments.callee(--n, s);
    },
    newArray: function (n, s) {
        if (n==0) return '';
        if (n==1 || isNaN(n)) return s;
        return (new Array(isNaN(n) ? 1 : ++n)).join(s);
    },
    fillAndJoin: function (n, s) {
        if (n==0) return '';
        if (n==1 || isNaN(n)) return s;
        var ret = [];
        for (var i=0; i<n; i++)
            ret.push(s);
        return ret.join('');
    },
    concat: function (n,s) {
        if (n==0) return '';
        if (n==1 || isNaN(n)) return s;
        var ret = '';
        for (var i=0; i<n; i++)
            ret+=s;
        return ret;
    },
    artistoex: function (n,s) {
        var result = '';
        while (n>0) {
            if (n&1) result+=s;
            n>>=1, s+=s;
        };
        return result;
    }
};
function testNum(len, dev) {
    with(Math) { return round(len+1+dev*(random()-0.5)); }
}
function testString(len, dev) {
    return (new Array(testNum(len, dev))).join(' ');
}
var testTime = 1000,
    tests = {
        biggie: { str: { len: 25, dev: 12 }, rep: {len: 200, dev: 50 } },
        smalls: { str: { len: 5, dev: 5}, rep: { len: 5, dev: 5 } }
    };
var testCount = 0;
var winnar = null;
var inflight = 0;
for (var methodName in repeatMethods) {
    var method = repeatMethods[methodName];
    for (var testName in tests) {
        testCount++;
        var test = tests[testName];
        var testId = methodName+':'+testName;
        var result = {
            id: testId,
            testParams: test
        }
        result.count=0;

        (function (result) {
            inflight++;
            setTimeout(function () {
                result.start = +new Date();
                while ((new Date() - result.start) < testTime) {
                    method(testNum(test.rep.len, test.rep.dev), testString(test.str.len, test.str.dev));
                    result.count++;
                }
                result.end = +new Date();
                result.rate = 1000*result.count/(result.end-result.start)
                console.log(result);
                if (winnar === null || winnar.rate < result.rate) winnar = result;
                inflight--;
                if (inflight==0) {
                    console.log('The winner: ');
                    console.log(winnar);
                }
            }, (100+testTime)*testCount);
        }(result));
    }
}

String.prototype.repeat现在是ES6标准。

'abc'.repeat(3); //abcabcabc