在编写多线程应用程序时,遇到的最常见的问题之一是竞争条件。
我对社区的问题是:
竞态条件是什么? 你如何发现它们? 你是如何处理的? 最后,你如何防止它们的发生?
在编写多线程应用程序时,遇到的最常见的问题之一是竞争条件。
我对社区的问题是:
竞态条件是什么? 你如何发现它们? 你是如何处理的? 最后,你如何防止它们的发生?
当前回答
为了更好地理解竞态条件,请尝试以下基本示例:
public class ThreadRaceCondition {
/**
* @param args
* @throws InterruptedException
*/
public static void main(String[] args) throws InterruptedException {
Account myAccount = new Account(22222222);
// Expected deposit: 250
for (int i = 0; i < 50; i++) {
Transaction t = new Transaction(myAccount,
Transaction.TransactionType.DEPOSIT, 5.00);
t.start();
}
// Expected withdrawal: 50
for (int i = 0; i < 50; i++) {
Transaction t = new Transaction(myAccount,
Transaction.TransactionType.WITHDRAW, 1.00);
t.start();
}
// Temporary sleep to ensure all threads are completed. Don't use in
// realworld :-)
Thread.sleep(1000);
// Expected account balance is 200
System.out.println("Final Account Balance: "
+ myAccount.getAccountBalance());
}
}
class Transaction extends Thread {
public static enum TransactionType {
DEPOSIT(1), WITHDRAW(2);
private int value;
private TransactionType(int value) {
this.value = value;
}
public int getValue() {
return value;
}
};
private TransactionType transactionType;
private Account account;
private double amount;
/*
* If transactionType == 1, deposit else if transactionType == 2 withdraw
*/
public Transaction(Account account, TransactionType transactionType,
double amount) {
this.transactionType = transactionType;
this.account = account;
this.amount = amount;
}
public void run() {
switch (this.transactionType) {
case DEPOSIT:
deposit();
printBalance();
break;
case WITHDRAW:
withdraw();
printBalance();
break;
default:
System.out.println("NOT A VALID TRANSACTION");
}
;
}
public void deposit() {
this.account.deposit(this.amount);
}
public void withdraw() {
this.account.withdraw(amount);
}
public void printBalance() {
System.out.println(Thread.currentThread().getName()
+ " : TransactionType: " + this.transactionType + ", Amount: "
+ this.amount);
System.out.println("Account Balance: "
+ this.account.getAccountBalance());
}
}
class Account {
private int accountNumber;
private double accountBalance;
public int getAccountNumber() {
return accountNumber;
}
public double getAccountBalance() {
return accountBalance;
}
public Account(int accountNumber) {
this.accountNumber = accountNumber;
}
// If this method is not synchronized, you will see race condition on
// Remove syncronized keyword to see race condition
public synchronized boolean deposit(double amount) {
if (amount < 0) {
return false;
} else {
accountBalance = accountBalance + amount;
return true;
}
}
// If this method is not synchronized, you will see race condition on
// Remove syncronized keyword to see race condition
public synchronized boolean withdraw(double amount) {
if (amount > accountBalance) {
return false;
} else {
accountBalance = accountBalance - amount;
return true;
}
}
}
其他回答
当访问共享资源的多线程(或其他并行)代码可能以导致意外结果的方式访问共享资源时,就存在“竞争条件”。
举个例子:
for ( int i = 0; i < 10000000; i++ )
{
x = x + 1;
}
如果你有5个线程同时执行这段代码,x的值最终不会是50,000,000。事实上,它会随着每一次运行而变化。
这是因为,为了让每个线程增加x的值,它们必须做以下事情:(显然是简化的)
Retrieve the value of x Add 1 to this value Store this value to x
任何线程都可以在任何时间处于此进程的任何步骤,并且当涉及共享资源时,它们可以相互踩。在读取x和写回x之间的时间内,x的状态可以由另一个线程改变。
假设一个线程获取了x的值,但还没有存储它。另一个线程也可以检索相同的x值(因为还没有线程更改它),然后它们都将在x中存储相同的值(x+1) !
例子:
Thread 1: reads x, value is 7 Thread 1: add 1 to x, value is now 8 Thread 2: reads x, value is 7 Thread 1: stores 8 in x Thread 2: adds 1 to x, value is now 8 Thread 2: stores 8 in x
竞争条件可以通过在代码访问共享资源之前使用某种锁定机制来避免:
for ( int i = 0; i < 10000000; i++ )
{
//lock x
x = x + 1;
//unlock x
}
这里,答案每次都是50,000,000。
有关锁的更多信息,请搜索:互斥量,信号量,临界区,共享资源。
Race conditions occur in multi-threaded applications or multi-process systems. A race condition, at its most basic, is anything that makes the assumption that two things not in the same thread or process will happen in a particular order, without taking steps to ensure that they do. This happens commonly when two threads are passing messages by setting and checking member variables of a class both can access. There's almost always a race condition when one thread calls sleep to give another thread time to finish a task (unless that sleep is in a loop, with some checking mechanism).
防止竞争条件的工具依赖于语言和操作系统,但一些常见的工具是互斥锁、临界区和信号。互斥锁在你想确保你是唯一一个在做某事的时候很有用。当你想确保别人已经完成某件事时,信号是很好的。最小化共享资源还有助于防止意外行为
Detecting race conditions can be difficult, but there are a couple signs. Code which relies heavily on sleeps is prone to race conditions, so first check for calls to sleep in the affected code. Adding particularly long sleeps can also be used for debugging to try and force a particular order of events. This can be useful for reproducing the behavior, seeing if you can make it disappear by changing the timing of things, and for testing solutions put in place. The sleeps should be removed after debugging.
但是,如果某个问题只在某些机器上断断续续地发生,则是存在竞争条件的标志性标志。常见的错误是崩溃和死锁。使用日志记录,您应该能够找到受影响的区域并从那里返回。
考虑一个操作,该操作必须在计数增加时立即显示计数。ie。,只要CounterThread增加值,DisplayThread就需要显示最近更新的值。
int i = 0;
输出
CounterThread -> i = 1
DisplayThread -> i = 1
CounterThread -> i = 2
CounterThread -> i = 3
CounterThread -> i = 4
DisplayThread -> i = 4
在这里,CounterThread频繁地获取锁,并在DisplayThread显示它之前更新值。这里存在一个竞态条件。竞争条件可以通过使用同步来解决
如果你使用“原子”类,你可以防止竞争条件。原因是线程没有分开操作get和set,示例如下:
AtomicInteger ai = new AtomicInteger(2);
ai.getAndAdd(5);
因此,你将有7在链接“ai”。 虽然你做了两个操作,但这两个操作都确认了同一个线程,没有其他线程会干涉这,这意味着没有竞争条件!
为了更好地理解竞态条件,请尝试以下基本示例:
public class ThreadRaceCondition {
/**
* @param args
* @throws InterruptedException
*/
public static void main(String[] args) throws InterruptedException {
Account myAccount = new Account(22222222);
// Expected deposit: 250
for (int i = 0; i < 50; i++) {
Transaction t = new Transaction(myAccount,
Transaction.TransactionType.DEPOSIT, 5.00);
t.start();
}
// Expected withdrawal: 50
for (int i = 0; i < 50; i++) {
Transaction t = new Transaction(myAccount,
Transaction.TransactionType.WITHDRAW, 1.00);
t.start();
}
// Temporary sleep to ensure all threads are completed. Don't use in
// realworld :-)
Thread.sleep(1000);
// Expected account balance is 200
System.out.println("Final Account Balance: "
+ myAccount.getAccountBalance());
}
}
class Transaction extends Thread {
public static enum TransactionType {
DEPOSIT(1), WITHDRAW(2);
private int value;
private TransactionType(int value) {
this.value = value;
}
public int getValue() {
return value;
}
};
private TransactionType transactionType;
private Account account;
private double amount;
/*
* If transactionType == 1, deposit else if transactionType == 2 withdraw
*/
public Transaction(Account account, TransactionType transactionType,
double amount) {
this.transactionType = transactionType;
this.account = account;
this.amount = amount;
}
public void run() {
switch (this.transactionType) {
case DEPOSIT:
deposit();
printBalance();
break;
case WITHDRAW:
withdraw();
printBalance();
break;
default:
System.out.println("NOT A VALID TRANSACTION");
}
;
}
public void deposit() {
this.account.deposit(this.amount);
}
public void withdraw() {
this.account.withdraw(amount);
}
public void printBalance() {
System.out.println(Thread.currentThread().getName()
+ " : TransactionType: " + this.transactionType + ", Amount: "
+ this.amount);
System.out.println("Account Balance: "
+ this.account.getAccountBalance());
}
}
class Account {
private int accountNumber;
private double accountBalance;
public int getAccountNumber() {
return accountNumber;
}
public double getAccountBalance() {
return accountBalance;
}
public Account(int accountNumber) {
this.accountNumber = accountNumber;
}
// If this method is not synchronized, you will see race condition on
// Remove syncronized keyword to see race condition
public synchronized boolean deposit(double amount) {
if (amount < 0) {
return false;
} else {
accountBalance = accountBalance + amount;
return true;
}
}
// If this method is not synchronized, you will see race condition on
// Remove syncronized keyword to see race condition
public synchronized boolean withdraw(double amount) {
if (amount > accountBalance) {
return false;
} else {
accountBalance = accountBalance - amount;
return true;
}
}
}