根据UITableView中选定单元格的自定义颜色，根据Maciej Swic的答案，很棒的解决方案

为了补充这一点，你在Cell配置中声明Swic的答案通常如下:

- （UITableViewCell *）tableView：（UITableView *）tableView cellForRowAtIndexPath：（NSIndexPath *）indexPath

为了增加效果，您可以使用RGB值来实现自定义颜色外观，而不是系统颜色。在我的代码中，我是这样实现的:

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath 

} 

 static NSString *CellIdentifier = @"YourCustomCellName";
 MakanTableCell *cell = [self.tableView dequeueReusableCellWithIdentifier:CellIdentifier forIndexPath:indexPath];

// Configure the cell...

if (cell == nil) {

cell = [[[NSBundle mainBundle]loadNibNamed:@"YourCustomCellClassName" owner:self options:nil]objectAtIndex:0];
                    } 

UIView *bgColorView = [[UIView alloc] init];
bgColorView.backgroundColor = [UIColor colorWithRed:255.0/256.0 green:239.0/256.0 blue:49.0/256.0 alpha:1];
bgColorView.layer.cornerRadius = 7;
bgColorView.layer.masksToBounds = YES;
[cell setSelectedBackgroundView:bgColorView];


return cell;

}

如果这对你也有用，请告诉我。你可以在选定单元格的角落上打乱拐角半径的数值。

在自定义单元格类中为表单元格创建一个自定义单元格。M把下面的代码，它会工作的很好。你需要把想要的颜色图像放在选择背景UIImage中。

- (void)setSelected:(BOOL)selected animated:(BOOL)animated
{
    UIImage *selectionBackground = [UIImage imageNamed:@"yellow_bar.png"];
    UIImageView *iview=[[UIImageView alloc] initWithImage:selectionBackground];
    self.selectedBackgroundView=iview;
}

我认为你在正确的轨道上，但根据selectedBackgroundView的类定义:

对于普通样式表(UITableViewStylePlain)中的单元格，默认为nil，对于section-group表(UITableViewStyleGrouped)中的单元格，默认为非nil。

因此，如果你使用的是普通样式的表，那么你需要alloc-init一个新的UIView，有你想要的背景颜色，然后分配给selectedBackgroundView。

或者，如果你想要的是灰色背景当单元格被选中时，你可以使用这个:

cell.selectionStyle = UITableViewCellSelectionStyleGray;

- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath
{
    [tableView reloadData];
    UITableViewCell *cell=(UITableViewCell*)[tableView cellForRowAtIndexPath:indexPath];
    [cell setBackgroundColor:[UIColor orangeColor]];
}

Swift 3.0扩展

extension UITableViewCell {
    var selectionColor: UIColor {
        set {
            let view = UIView()
            view.backgroundColor = newValue
            self.selectedBackgroundView = view
        }
        get {
            return self.selectedBackgroundView?.backgroundColor ?? UIColor.clear
        }
    }
}

细胞。selectionColor = uiccolor . formacar .blue

I've got a slightly different approach than everyone else that reflects the selection on touch rather than after being selected. I have a subclassed UITableViewCell. All you have to do is set the background color in the touch events, which simulates selection on touch, and then set the background color in the setSelected function. Setting the background color in the selSelected function allows for deselecting the cell. Make sure to pass the touch event to the super, otherwise the cell won't actually act as if its selected.

override func touchesBegan(touches: NSSet, withEvent event: UIEvent) {
    self.backgroundColor = UIColor(white: 0.0, alpha: 0.1)
    super.touchesBegan(touches, withEvent: event)
}

override func touchesCancelled(touches: NSSet!, withEvent event: UIEvent!) {
    self.backgroundColor = UIColor.clearColor()
    super.touchesCancelled(touches, withEvent: event)
}

override func setSelected(selected: Bool, animated: Bool) {
    super.setSelected(selected, animated: animated)

    // Configure the view for the selected state
    self.backgroundColor = selected ? UIColor(white: 0.0, alpha: 0.1) : UIColor.clearColor()
}