我想使用JavaScript来计算字符串的宽度。如果不使用单行字体,这可能吗?

如果它不是内置的,我唯一的想法是为每个字符创建一个宽度表,但这是非常不合理的,特别是支持Unicode和不同的类型大小(以及所有浏览器)。


当前回答

下面的代码片段,“计算”span标签的宽度,如果它太长,就添加“…”,并减少文本长度,直到它适合它的父标签(或者直到它尝试了超过1000次)

CSS

div.places {
  width : 100px;
}
div.places span {
  white-space:nowrap;
  overflow:hidden;
}

HTML

<div class="places">
  <span>This is my house</span>
</div>
<div class="places">
  <span>And my house are your house</span>
</div>
<div class="places">
  <span>This placename is most certainly too wide to fit</span>
</div>

JavaScript(使用jQuery)

// loops elements classed "places" and checks if their child "span" is too long to fit
$(".places").each(function (index, item) {
    var obj = $(item).find("span");
    if (obj.length) {
        var placename = $(obj).text();
        if ($(obj).width() > $(item).width() && placename.trim().length > 0) {
            var limit = 0;
            do {
                limit++;
                                    placename = placename.substring(0, placename.length - 1);
                                    $(obj).text(placename + "...");
            } while ($(obj).width() > $(item).width() && limit < 1000)
        }
    }
});

其他回答

ExtJS javascript库中有一个很棒的类,叫做Ext.util.TextMetrics,它“为文本块提供精确的像素测量,这样你就可以准确地确定给定文本块的高和宽(以像素为单位)”。您可以直接使用它,也可以查看它的源代码以了解如何完成此操作。

http://docs.sencha.com/extjs/6.5.3/modern/Ext.util.TextMetrics.html

jQuery:

(function($) {

 $.textMetrics = function(el) {

  var h = 0, w = 0;

  var div = document.createElement('div');
  document.body.appendChild(div);
  $(div).css({
   position: 'absolute',
   left: -1000,
   top: -1000,
   display: 'none'
  });

  $(div).html($(el).html());
  var styles = ['font-size','font-style', 'font-weight', 'font-family','line-height', 'text-transform', 'letter-spacing'];
  $(styles).each(function() {
   var s = this.toString();
   $(div).css(s, $(el).css(s));
  });

  h = $(div).outerHeight();
  w = $(div).outerWidth();

  $(div).remove();

  var ret = {
   height: h,
   width: w
  };

  return ret;
 }

})(jQuery);

如果有人在这里寻找一种测量字符串宽度的方法,以及一种知道适合特定宽度的最大字体大小的方法,这里有一个基于@Domi的解决方案的函数,使用二进制搜索:

/**
 * Find the largest font size (in pixels) that allows the string to fit in the given width.
 * 
 * @param {String} text - The text to be rendered.
 * @param {String} font - The css font descriptor that text is to be rendered with (e.g. "bold ?px verdana") -- note the use of ? in place of the font size.
 * @param {Number} width - The width in pixels the string must fit in
 * @param {Number} minFontPx - The smallest acceptable font size in pixels
 * @param {Number} maxFontPx - The largest acceptable font size in pixels
 **/
function GetTextSizeForWidth(text, font, width, minFontPx, maxFontPx) {
  for (;;) {
    var s = font.replace("?", maxFontPx);
    var w = GetTextWidth(text, s);
    if (w <= width) {
      return maxFontPx;
    }

    var g = (minFontPx + maxFontPx) / 2;

    if (Math.round(g) == Math.round(minFontPx) || Math.round(g) == Math.round(maxFontPx)) {
      return g;
    }

    s = font.replace("?", g);
    w = GetTextWidth(text, s);
    if (w >= width) {
      maxFontPx = g;
    } else {
      minFontPx = g;
    }
  }
}

工作示例:http://jsfiddle.net/tdpLdqpo/1/

HTML:

<h1 id="test1">
    How wide is this text?
</h1>
<div id="result1"></div>
<hr/>
<p id="test2">
    How wide is this text?
</p>
<div id="result2"></div>
<hr/>
<p id="test3">
    How wide is this text?<br/><br/>
    f sdfj f sdlfj lfj lsdk jflsjd fljsd flj sflj sldfj lsdfjlsdjkf sfjoifoewj flsdjfl jofjlgjdlsfjsdofjisdojfsdmfnnfoisjfoi  ojfo dsjfo jdsofjsodnfo sjfoj ifjjfoewj fofew jfos fojo foew jofj s f j
</p>
<div id="result3"></div>

JavaScript代码:

function getTextWidth(text, font) {
    var canvas = getTextWidth.canvas ||
        (getTextWidth.canvas = document.createElement("canvas"));
    var context = canvas.getContext("2d");
    context.font = font;
    var metrics = context.measureText(text);
    return metrics.width;
};

$("#result1")
.text("answer: " +
    getTextWidth(
             $("#test1").text(),
             $("#test1").css("font")) + " px");

$("#result2")
    .text("answer: " +
        getTextWidth(
             $("#test2").text(),
             $("#test2").css("font")) + " px");

$("#result3")
    .text("answer: " +
        getTextWidth(
             $("#test3").text(),
             $("#test3").css("font")) + " px");

我喜欢你的“唯一的想法”只是做一个静态字符宽度地图!它实际上很适合我的目的。有时,出于性能原因,或者因为不容易访问DOM,您可能只想要一个快速的、独立的、校准为单一字体的计算器。这是一个用Helvetica字体校准的;传递一个字符串和字体大小:

const widths = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0.2796875,0.2765625,0.3546875,0.5546875,0.5546875,0.8890625,0.665625,0.190625,0.3328125,0.3328125,0.3890625,0.5828125,0.2765625,0.3328125,0.2765625,0.3015625,0.5546875,0.5546875,0.5546875,0.5546875,0.5546875,0.5546875,0.5546875,0.5546875,0.5546875,0.5546875,0.2765625,0.2765625,0.584375,0.5828125,0.584375,0.5546875,1.0140625,0.665625,0.665625,0.721875,0.721875,0.665625,0.609375,0.7765625,0.721875,0.2765625,0.5,0.665625,0.5546875,0.8328125,0.721875,0.7765625,0.665625,0.7765625,0.721875,0.665625,0.609375,0.721875,0.665625,0.94375,0.665625,0.665625,0.609375,0.2765625,0.3546875,0.2765625,0.4765625,0.5546875,0.3328125,0.5546875,0.5546875,0.5,0.5546875,0.5546875,0.2765625,0.5546875,0.5546875,0.221875,0.240625,0.5,0.221875,0.8328125,0.5546875,0.5546875,0.5546875,0.5546875,0.3328125,0.5,0.2765625,0.5546875,0.5,0.721875,0.5,0.5,0.5,0.3546875,0.259375,0.353125,0.5890625]
const avg = 0.5279276315789471

function measureText(str, fontSize) {
  return Array.from(str).reduce(
    (acc, cur) => acc + (widths[cur.charCodeAt(0)] ?? avg), 0
  ) * fontSize
}

这个巨大的丑陋数组是由字符代码索引的ASCII字符宽度。所以这只支持ASCII(否则它假设平均字符宽度)。幸运的是,宽度基本上是随字体大小线性缩放的,所以它在任何字体大小下都能很好地工作。它明显缺乏对字距或结扎之类的意识。

为了“校准”,我只是在svg上渲染了charCode 126(强大的波浪号)的每个字符,并获得了边界框并将其保存到这个数组中;这里有更多的代码、解释和演示。