我正在寻找一种简单的方法来获得mime类型,其中文件扩展名是不正确的或没有给出,类似于这个问题只有在. net。
当前回答
iis7或以上
使用此代码,但您需要是服务器上的管理员
public bool CheckMimeMapExtension(string fileExtension)
{
try
{
using (
ServerManager serverManager = new ServerManager())
{
// connects to default app.config
var config = serverManager.GetApplicationHostConfiguration();
var staticContent = config.GetSection("system.webServer/staticContent");
var mimeMap = staticContent.GetCollection();
foreach (var mimeType in mimeMap)
{
if (((String)mimeType["fileExtension"]).Equals(fileExtension, StringComparison.OrdinalIgnoreCase))
return true;
}
}
return false;
}
catch (Exception ex)
{
Console.WriteLine("An exception has occurred: \n{0}", ex.Message);
Console.Read();
}
return false;
}
其他回答
I think the right answer is a combination of Steve Morgan's and Serguei's answers. That's how Internet Explorer does it. The pinvoke call to FindMimeFromData works for only 26 hard-coded mime types. Also, it will give ambigous mime types (such as text/plain or application/octet-stream) even though there may exist a more specific, more appropriate mime type. If it fails to give a good mime type, you can go to the registry for a more specific mime type. The server registry could have more up-to-date mime types.
参考网址:http://msdn.microsoft.com/en-us/library/ms775147(VS.85).aspx
@Steve Morgan和@Richard Gourlay,这是一个很好的解决方案,谢谢你们。一个小缺点是,当文件中的字节数为255或以下时,mime类型有时会产生“application/octet-stream”,这对于期望产生“text/plain”的文件来说有点不准确。对于这种情况,我更新了你原来的方法如下:
如果文件中的字节数小于或等于255,并且推导出的mime类型是"application/octet-stream",那么创建一个新的字节数组,该数组由重复n次的原始文件字节组成,直到字节总数为>= 256。然后重新检查新字节数组上的mime-type。
修改方法:
Imports System.Runtime.InteropServices
<DllImport("urlmon.dll", CharSet:=CharSet.Auto)> _
Private Shared Function FindMimeFromData(pBC As System.UInt32, <MarshalAs(UnmanagedType.LPStr)> pwzUrl As System.String, <MarshalAs(UnmanagedType.LPArray)> pBuffer As Byte(), cbSize As System.UInt32, <MarshalAs(UnmanagedType.LPStr)> pwzMimeProposed As System.String, dwMimeFlags As System.UInt32, _
ByRef ppwzMimeOut As System.UInt32, dwReserverd As System.UInt32) As System.UInt32
End Function
Private Function GetMimeType(ByVal f As FileInfo) As String
'See http://stackoverflow.com/questions/58510/using-net-how-can-you-find-the-mime-type-of-a-file-based-on-the-file-signature
Dim returnValue As String = ""
Dim fileStream As FileStream = Nothing
Dim fileStreamLength As Long = 0
Dim fileStreamIsLessThanBByteSize As Boolean = False
Const byteSize As Integer = 255
Const bbyteSize As Integer = byteSize + 1
Const ambiguousMimeType As String = "application/octet-stream"
Const unknownMimeType As String = "unknown/unknown"
Dim buffer As Byte() = New Byte(byteSize) {}
Dim fnGetMimeTypeValue As New Func(Of Byte(), Integer, String)(
Function(_buffer As Byte(), _bbyteSize As Integer) As String
Dim _returnValue As String = ""
Dim mimeType As UInt32 = 0
FindMimeFromData(0, Nothing, _buffer, _bbyteSize, Nothing, 0, mimeType, 0)
Dim mimeTypePtr As IntPtr = New IntPtr(mimeType)
_returnValue = Marshal.PtrToStringUni(mimeTypePtr)
Marshal.FreeCoTaskMem(mimeTypePtr)
Return _returnValue
End Function)
If (f.Exists()) Then
Try
fileStream = New FileStream(f.FullName(), FileMode.Open, FileAccess.Read, FileShare.ReadWrite)
fileStreamLength = fileStream.Length()
If (fileStreamLength >= bbyteSize) Then
fileStream.Read(buffer, 0, bbyteSize)
Else
fileStreamIsLessThanBByteSize = True
fileStream.Read(buffer, 0, CInt(fileStreamLength))
End If
returnValue = fnGetMimeTypeValue(buffer, bbyteSize)
If (returnValue.Equals(ambiguousMimeType, StringComparison.OrdinalIgnoreCase) AndAlso fileStreamIsLessThanBByteSize AndAlso fileStreamLength > 0) Then
'Duplicate the stream content until the stream length is >= bbyteSize to get a more deterministic mime type analysis.
Dim currentBuffer As Byte() = buffer.Take(fileStreamLength).ToArray()
Dim repeatCount As Integer = Math.Floor((bbyteSize / fileStreamLength) + 1)
Dim bBufferList As List(Of Byte) = New List(Of Byte)
While (repeatCount > 0)
bBufferList.AddRange(currentBuffer)
repeatCount -= 1
End While
Dim bbuffer As Byte() = bBufferList.Take(bbyteSize).ToArray()
returnValue = fnGetMimeTypeValue(bbuffer, bbyteSize)
End If
Catch ex As Exception
returnValue = unknownMimeType
Finally
If (fileStream IsNot Nothing) Then fileStream.Close()
End Try
End If
Return returnValue
End Function
如果你想要托管你的ASP. mimetype,来自Nuget的guessmimetype将是最终的解决方案。NET解决方案在非windows环境。
文件扩展名映射非常不安全。如果攻击者上传无效的扩展名,映射字典将允许可执行文件在.jpg文件中分发。 因此,始终使用内容嗅探库来了解真正的内容类型。
public static string MimeTypeFrom(byte[] dataBytes, string fileName)
{
var contentType = HeyRed.Mime.MimeGuesser.GuessMimeType(dataBytes);
if (string.IsNullOrEmpty(contentType))
{
return HeyRed.Mime.MimeTypesMap.GetMimeType(fileName);
}
return contentType;
如果你正在使用。net Framework 4.5或更高版本,现在有一个MimeMapping.GetMimeMapping(filename)方法,它将返回一个字符串,其中包含传递文件名的正确Mime映射。注意,这里使用的是文件扩展名,而不是文件本身中的数据。
文档请见http://msdn.microsoft.com/en-us/library/system.web.mimemapping.getmimemapping
iis7或以上
使用此代码,但您需要是服务器上的管理员
public bool CheckMimeMapExtension(string fileExtension)
{
try
{
using (
ServerManager serverManager = new ServerManager())
{
// connects to default app.config
var config = serverManager.GetApplicationHostConfiguration();
var staticContent = config.GetSection("system.webServer/staticContent");
var mimeMap = staticContent.GetCollection();
foreach (var mimeType in mimeMap)
{
if (((String)mimeType["fileExtension"]).Equals(fileExtension, StringComparison.OrdinalIgnoreCase))
return true;
}
}
return false;
}
catch (Exception ex)
{
Console.WriteLine("An exception has occurred: \n{0}", ex.Message);
Console.Read();
}
return false;
}
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