我真的很沮丧，在阅读所有的代码，其中张贴作为一个解决方案，因为我是一个新的是，我试图添加一个功能到一个简单的应用程序的实践。解决这个问题的简单方法是

let testArray = [5, 7, 8, 4];

function(){
sum = 0;
for(let i = 0; i < testArray.length; i++){
    sum += testArray[i];
}

//会给你数组的和

只是另一种说法，这就是原生JavaScript函数Map和Reduce的用途(Map和Reduce是许多语言中的强大功能)。

var traveler = [{description: 'Senior', Amount: 50},
                {description: 'Senior', Amount: 50},
                {description: 'Adult', Amount: 75},
                {description: 'Child', Amount: 35},
                {description: 'Infant', Amount: 25}];

function amount(item){
  return item.Amount;
}

function sum(prev, next){
  return prev + next;
}

traveler.map(amount).reduce(sum);
// => 235;

// or use arrow functions
traveler.map(item => item.Amount).reduce((prev, next) => prev + next);

注意:通过创建独立的小函数，我们可以再次使用它们。

// Example of reuse.
// Get only Amounts greater than 0;

// Also, while using Javascript, stick with camelCase.
// If you do decide to go against the standards, 
// then maintain your decision with all keys as in...

// { description: 'Senior', Amount: 50 }

// would be

// { Description: 'Senior', Amount: 50 };

var travelers = [{description: 'Senior', amount: 50},
                {description: 'Senior', amount: 50},
                {description: 'Adult', amount: 75},
                {description: 'Child', amount: 35},
                {description: 'Infant', amount: 0 }];

// Directly above Travelers array I changed "Amount" to "amount" to match standards.

function amount(item){
  return item.amount;
}

travelers.filter(amount);
// => [{description: 'Senior', amount: 50},
//     {description: 'Senior', amount: 50},
//     {description: 'Adult', amount: 75},
//     {description: 'Child', amount: 35}];
//     Does not include "Infant" as 0 is falsey.

使用reduce和解构来求和

const traveler = [
  { description: 'Senior', Amount: 50 },
  { description: 'Senior', Amount: 50 },
  { description: 'Adult', Amount: 75 },
  { description: 'Child', Amount: 35 },
  { description: 'Infant', Amount: 25 },
];

console.log(traveler.reduce((n, {Amount}) => n + Amount, 0))

您可以执行以下操作:

$scope.traveler.map(o=>o.Amount).reduce((a,c)=>a+c);

这里有一个我觉得更灵活的解决办法:

function sumOfArrayWithParameter (array, parameter) {
  let sum = null;
  if (array && array.length > 0 && typeof parameter === 'string') {
    sum = 0;
    for (let e of array) if (e && e.hasOwnProperty(parameter)) sum += e[parameter];
  }
  return sum;
}

要得到和，只需像这样使用它:

let sum = sumOfArrayWithParameter(someArray, 'someProperty');

它在TypeScript和JavaScript中为我工作:

令LST = [ {说明:'高级'，价格:10}， {说明:“成人”，价格:20}， {描述:“儿童”，价格:30} ]; 令sum = lst。Map (o => o.price)。Reduce ((a, c) => {return a + c}); console.log(总和);

希望对大家有用。