用于String数组的列表

list.forEach(s -> System.out.println(Arrays.toString((String[]) s )));

下面的代码很紧凑，避免了示例代码中的循环(并提供了漂亮的逗号):

System.out.println(Arrays.toString(list.toArray()));

然而，正如其他人指出的那样，如果您没有为列表中的对象实现合理的toString()方法，您将得到您所观察到的对象指针(实际上是哈希码)。无论它们是否在列表中，都是如此。

尝试重写toString()方法，因为您希望元素将被打印。 打印的方法可以是这样的:

for(int i=0;i<list.size();i++){
    System.out.println(list.get(i).toString());
} 

java 11问题的解决方案是:

String separator = ", ";
String toPrint = list.stream().map(o -> String.valueOf(o)).collect(Collectors.joining(separator));

System.out.println(toPrint);

我也遇到过类似的问题。我的代码:

List<Integer> leaveDatesList = new ArrayList<>();

.....inserted value in list.......

方法1:在for循环中打印一个列表

for(int i=0;i<leaveDatesList.size();i++){
    System.out.println(leaveDatesList.get(i));
}

方法2:在forEach中打印列表，for循环

for(Integer leave : leaveDatesList){
    System.out.println(leave);
}

方法3:在java 8中打印列表

leaveDatesList.forEach(System.out::println);

You haven't specified what kind of elements the list contains, if it is a primitive data type then you can print out the elements. But if the elements are objects then as Kshitij Mehta mentioned you need to implement (override) the method "toString" within that object - if it is not already implemented - and let it return something meaning full from within the object, example: class Person { private String firstName; private String lastName; @Override public String toString() { return this.firstName + " " + this.lastName; } }