在PostgreSQL中,有Limit和Offset关键字,可以非常容易地对结果集进行分页。

SQL Server的等效语法是什么?


当前回答

我假设,在c#表达式/LINQ语句的跳过和采取生成下面的SQL命令

DECLARE @p0 Int = 1
DECLARE @p1 Int = 3
SELECT [t1].[Id]
FROM (
    SELECT ROW_NUMBER() OVER (ORDER BY [t0].[Id]
    FROM [ShoppingCart] AS [t0]
    ) AS [t1]
WHERE [t1].[ROW_NUMBER] BETWEEN @p0 + 1 AND @p0 + @p1
ORDER BY [t1].[ROW_NUMBER]

其他回答

因为,我测试了更多次这个脚本更有用的100万条记录,每页100条记录分页工作更快,我的PC执行这个脚本0秒,而与mysql相比有自己的限制和偏移约4.5秒得到结果。

有些人可能不理解Row_Number()总是按特定字段排序。如果我们只需要按顺序定义行,应该使用:

Row_number () over (order by (select null))

SELECT TOP {LIMIT} * FROM (
      SELECT TOP {LIMIT} + {OFFSET} ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) AS ROW_NO,*
      FROM  {TABLE_NAME}
) XX WHERE ROW_NO > {OFFSET}

解释:

{LIMIT}:每页的记录数 {OFFSET}:跳过记录的个数

另一个例子:

declare @limit int 
declare @offset int 
set @offset = 2;
set @limit = 20;
declare @count int
declare @idxini int 
declare @idxfim int 
select @idxfim = @offset * @limit
select @idxini = @idxfim - (@limit-1);
WITH paging AS
    (
        SELECT 
             ROW_NUMBER() OVER (order by object_id) AS rowid, *
        FROM 
            sys.objects 
    )
select *
    from 
        (select COUNT(1) as rowqtd from paging) qtd, 
            paging 
    where 
        rowid between @idxini and @idxfim
    order by 
        rowid;

我能做到的最接近

select * FROM( SELECT *, ROW_NUMBER() over (ORDER BY ID ) as ct from [db].[dbo].[table] ) sub where ct > fromNumber  and ct <= toNumber

我猜类似于select * from [db].[dbo]。[table] LIMIT 0,10

select top {LIMIT HERE} * from (
      select *, ROW_NUMBER() over (order by {ORDER FIELD}) as r_n_n 
      from {YOUR TABLES} where {OTHER OPTIONAL FILTERS}
) xx where r_n_n >={OFFSET HERE}

注意: 这个解决方案只能在SQL Server 2005或更高版本中工作,因为这是实现ROW_NUMBER()的时候。

我假设,在c#表达式/LINQ语句的跳过和采取生成下面的SQL命令

DECLARE @p0 Int = 1
DECLARE @p1 Int = 3
SELECT [t1].[Id]
FROM (
    SELECT ROW_NUMBER() OVER (ORDER BY [t0].[Id]
    FROM [ShoppingCart] AS [t0]
    ) AS [t1]
WHERE [t1].[ROW_NUMBER] BETWEEN @p0 + 1 AND @p0 + @p1
ORDER BY [t1].[ROW_NUMBER]