我能做到的最接近

select * FROM( SELECT *, ROW_NUMBER() over (ORDER BY ID ) as ct from [db].[dbo].[table] ) sub where ct > fromNumber  and ct <= toNumber

我猜类似于select * from [db].[dbo]。[table] LIMIT 0,10

另一个例子:

declare @limit int 
declare @offset int 
set @offset = 2;
set @limit = 20;
declare @count int
declare @idxini int 
declare @idxfim int 
select @idxfim = @offset * @limit
select @idxini = @idxfim - (@limit-1);
WITH paging AS
    (
        SELECT 
             ROW_NUMBER() OVER (order by object_id) AS rowid, *
        FROM 
            sys.objects 
    )
select *
    from 
        (select COUNT(1) as rowqtd from paging) qtd, 
            paging 
    where 
        rowid between @idxini and @idxfim
    order by 
        rowid;

您可以在公共表表达式中使用ROW_NUMBER来实现这一点。

;WITH My_CTE AS
(
     SELECT
          col1,
          col2,
          ROW_NUMBER() OVER(ORDER BY col1) AS row_number
     FROM
          My_Table
     WHERE
          <<<whatever>>>
)
SELECT
     col1,
     col2
FROM
     My_CTE
WHERE
     row_number BETWEEN @start_row AND @end_row

-- @RowsPerPage  can be a fixed number and @PageNumber number can be passed 
DECLARE @RowsPerPage INT = 10, @PageNumber INT = 2

SELECT *

FROM MemberEmployeeData

ORDER BY EmployeeNumber

OFFSET @PageNumber*@RowsPerPage ROWS

FETCH NEXT 10 ROWS ONLY

@nombre_row :nombre ligne par page  
@page:numero de la page

//--------------code sql---------------

declare  @page int,@nombre_row int;
    set @page='2';
    set @nombre_row=5;
    SELECT  *
FROM    ( SELECT    ROW_NUMBER() OVER ( ORDER BY etudiant_ID ) AS RowNum, *
      FROM      etudiant

    ) AS RowConstrainedResult
WHERE   RowNum >= ((@page-1)*@nombre_row)+1
    AND RowNum < ((@page)*@nombre_row)+1
ORDER BY RowNum

select top (@TakeCount) * --FETCH NEXT
from(
    Select  ROW_NUMBER() OVER (order by StartDate) AS rowid,*
    From YourTable
)A
where Rowid>@SkipCount --OFFSET