我如何通过一个自定义类型的对象从一个活动到另一个使用类意图的putExtra()方法?
当前回答
你可以使用putExtra(Serializable..)和getSerializableExtra()方法来传递和检索你的类类型的对象;你必须将你的类标记为Serializable,并确保你所有的成员变量也是Serializable…
其他回答
Intent i = new Intent();
i.putExtra("name_of_extra", myParcelableObject);
startACtivity(i);
POJO类“Post”(注意它是实现Serializable的)
package com.example.booklib;
import java.io.Serializable;
import java.util.ArrayList;
import java.util.List;
import android.graphics.Bitmap;
public class Post implements Serializable{
public String message;
public String bitmap;
List<Comment> commentList = new ArrayList<Comment>();
public String getMessage() {
return message;
}
public void setMessage(String message) {
this.message = message;
}
public String getBitmap() {
return bitmap;
}
public void setBitmap(String bitmap) {
this.bitmap = bitmap;
}
public List<Comment> getCommentList() {
return commentList;
}
public void setCommentList(List<Comment> commentList) {
this.commentList = commentList;
}
}
POJO类“Comment”(由于是Post类的成员,它也需要实现Serializable)
package com.example.booklib;
import java.io.Serializable;
public class Comment implements Serializable{
public String message;
public String fromName;
public String getMessage() {
return message;
}
public void setMessage(String message) {
this.message = message;
}
public String getFromName() {
return fromName;
}
public void setFromName(String fromName) {
this.fromName = fromName;
}
}
然后在您的活动类中,您可以执行以下操作将对象传递给另一个活动。
ListView listview = (ListView) findViewById(R.id.post_list);
listview.setOnItemClickListener(new OnItemClickListener(){
@Override
public void onItemClick(AdapterView<?> parent, View view,
int position, long id) {
Post item = (Post)parent.getItemAtPosition(position);
Intent intent = new Intent(MainActivity.this,CommentsActivity.class);
intent.putExtra("post",item);
startActivity(intent);
}
});
在您的接收类“CommentsActivity”中,您可以获得如下数据
Post post =(Post)getIntent().getSerializableExtra("post");
如果你的对象类实现了Serializable,你不需要做任何其他事情,你可以传递一个Serializable对象。这就是我用的。
We can send data one Activty1 to Activity2 with multiple ways like.
1- Intent
2- bundle
3- create an object and send through intent
.................................................
1 - Using intent
Pass the data through intent
Intent intentActivity1 = new Intent(Activity1.this, Activity2.class);
intentActivity1.putExtra("name", "Android");
startActivity(intentActivity1);
Get the data in Activity2 calss
Intent intent = getIntent();
if(intent.hasExtra("name")){
String userName = getIntent().getStringExtra("name");
}
..................................................
2- Using Bundle
Intent intentActivity1 = new Intent(Activity1.this, Activity2.class);
Bundle bundle = new Bundle();
bundle.putExtra("name", "Android");
intentActivity1.putExtra(bundle);
startActivity(bundle);
Get the data in Activity2 calss
Intent intent = getIntent();
if(intent.hasExtra("name")){
String userName = getIntent().getStringExtra("name");
}
..................................................
3- Put your Object into Intent
Intent intentActivity1 = new Intent(Activity1.this, Activity2.class);
intentActivity1.putExtra("myobject", myObject);
startActivity(intentActivity1);
Receive object in the Activity2 Class
Intent intent = getIntent();
Myobject obj = (Myobject) intent.getSerializableExtra("myobject");
如果你有一个单例类(fx Service)作为你的模型层的网关,它可以通过在该类中有一个带有getter和setter的变量来解决。
活动一:
Intent intent = new Intent(getApplicationContext(), Activity2.class);
service.setSavedOrder(order);
startActivity(intent);
活动二:
private Service service;
private Order order;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_quality);
service = Service.getInstance();
order = service.getSavedOrder();
service.setSavedOrder(null) //If you don't want to save it for the entire session of the app.
}
在服务:
private static Service instance;
private Service()
{
//Constructor content
}
public static Service getInstance()
{
if(instance == null)
{
instance = new Service();
}
return instance;
}
private Order savedOrder;
public Order getSavedOrder()
{
return savedOrder;
}
public void setSavedOrder(Order order)
{
this.savedOrder = order;
}
此解决方案不需要对相关对象进行任何序列化或其他“打包”。但是,只有在使用这种架构时才会有好处。
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