我们可以使用筛选器和包含来实现逻辑

const checkAlpha2Code = ['BD', 'NZ', 'IN'] let countryAlpha2Code = ['US', 'CA', 'BD', 'NZ', 'AF' , 'AR' , 'BR'] /** * Returns the modified array countryAlpha2Code * after removing elements which matches with the checkAlpha2Code */ countryAlpha2Code = countryAlpha2Code.filter(alpha2code => { return !checkAlpha2Code.includes(alpha2code); }); console.log(countryAlpha2Code) // Output: [ 'US', 'CA', 'AF', 'AR', 'BR' ] // Resetting the values again countryAlpha2Code = ['US', 'CA', 'BD', 'NZ', 'AF' , 'AR' , 'BR'] /** * Returns the modified array countryAlpha2Code * which only matches elements with the checkAlpha2Code */ countryAlpha2Code = countryAlpha2Code.filter(alpha2code => { return checkAlpha2Code.includes(alpha2code); }); console.log(countryAlpha2Code) // Output: [ 'BD', 'NZ' ]

在ES6中，你可以使用以下代码:

removeDocument(doc){
   this.documents.forEach( (item, index) => {
     if(item === doc) this.documents.splice(index,1);
   });
}

我看到许多抱怨，删除方法不是内置的。考虑使用Set而不是array——它有内置的添加和删除方法。

类似于Abdus Salam Azad的答案，但将数组作为参数 / / https://love2dev.com/blog/javascript-remove-from-array/

function arrayRemove(arr:[], value:any) { 
    
    return arr.filter(function(ele){ 
        return ele != value; 
    });
}

只是想为数组添加扩展方法。

interface Array<T> {
      remove(element: T): Array<T>;
    }

    Array.prototype.remove = function (element) {
      const index = this.indexOf(element, 0);
      if (index > -1) {
        return this.splice(index, 1);
      }
      return this;
    };

let foo_object; // Itemitem(object here) to remove
this.foo_objects = this.foo_objects.filter(obj => return obj !== foo_object);