This answer for those who struggling with the same issue. You can implement your own custom filter based on ActionMethodSelectorAttribute. Here I found the best solution for solving your question. Works fine on .net 5 project. If you try to implement the same logic as was in web api controllers then use Microsoft.AspNetCore.Mvc.WebApiCompatShim. This nuget package provides compatibility in ASP.NET Core MVC with ASP.NET Web API 2 to simplify migration of existing Web API implementations. Please check this answer but consider that starting with ASP.NET Core 3.0, the Microsoft.AspNetCore.Mvc.WebApiCompatShim package is no longer available.

如果这是尝试对几个视图使用一个GET操作，这些视图POST到不同模型的几个操作，那么尝试为每个POST操作添加一个GET操作，重定向到第一个GET，以防止刷新时出现404。

可能性不大，但很常见。

据我所知，你只能有相同的方法时，使用不同的http方法。

i.e.

[AcceptVerbs("GET")]
public ActionResult MyAction()
{

}

[AcceptVerbs("POST")]
public ActionResult MyAction(FormResult fm)
{

}

我在申请的时候也遇到过同样的问题。没有Modifiyig任何方法信息，我已经提供了[ActionName(“SomeMeaningfulName”)]在动作头部。问题解决

[ActionName("_EmployeeDetailsByModel")]
        public PartialViewResult _EmployeeDetails(Employee model)
        {
            // Some Operation                
                return PartialView(model);
            }
        }

[ActionName("_EmployeeDetailsByModelWithPagination")]
        public PartialViewResult _EmployeeDetails(Employee model,int Page,int PageSize)
        {

                // Some Operation
                return PartialView(model);

        }

是的。我已经能够通过为每个控制器方法设置HttpGet/HttpPost(或等效的AcceptVerbs属性)来做到这一点，即HttpGet或HttpPost，但不是两者都有。这样它就可以根据请求的类型来判断使用哪个方法。

[HttpGet]
public ActionResult Show()
{
   ...
}

[HttpPost]
public ActionResult Show( string userName )
{
   ...
}

我的一个建议是，对于这种情况，应该有一个私有实现，你的两个公共Action方法都依赖于它，以避免重复代码。

您可以使用[ActionName("NewActionName")]来使用不同名称的相同方法:

public class HomeController : Controller
{
    public ActionResult GetEmpName()
    {
        return Content("This is the test Message");
    }

    [ActionName("GetEmpWithCode")]
    public ActionResult GetEmpName(string EmpCode)
    {
        return Content("This is the test Messagewith Overloaded");
    }
}