信用卡的第一个数字可以用来大致了解供应商:

签证:49、44或47 Visa电子:42、45、48、49 万事达卡:51 美国运通:34 就餐者:30、36、38 JCB: 35

一个javascript改进的@Anatoliy答案

function getCardType (number) { const numberFormated = number.replace(/\D/g, '') var patterns = { VISA: /^4[0-9]{12}(?:[0-9]{3})?$/, MASTER: /^5[1-5][0-9]{14}$/, AMEX: /^3[47][0-9]{13}$/, ELO: /^((((636368)|(438935)|(504175)|(451416)|(636297))\d{0,10})|((5067)|(4576)|(4011))\d{0,12})$/, AURA: /^(5078\d{2})(\d{2})(\d{11})$/, JCB: /^(?:2131|1800|35\d{3})\d{11}$/, DINERS: /^3(?:0[0-5]|[68][0-9])[0-9]{11}$/, DISCOVERY: /^6(?:011|5[0-9]{2})[0-9]{12}$/, HIPERCARD: /^(606282\d{10}(\d{3})?)|(3841\d{15})$/, ELECTRON: /^(4026|417500|4405|4508|4844|4913|4917)\d+$/, MAESTRO: /^(5018|5020|5038|5612|5893|6304|6759|6761|6762|6763|0604|6390)\d+$/, DANKORT: /^(5019)\d+$/, INTERPAYMENT: /^(636)\d+$/, UNIONPAY: /^(62|88)\d+$/, } for (var key in patterns) { if (patterns[key].test(numberFormated)) { return key } } } console.log(getCardType("4539 5684 7526 2091"))

这里有完整的c#或VB代码，用于各种CC相关的东西。

IsValidNumber GetCardTypeFromNumber GetCardTestNumber PassesLuhnTest

这篇文章已经发布了几年，没有任何负面评论。

我搜索了很多信用卡格式和电话号码格式。找到了很多好的提示，但没有一个真正符合我的需求，所以我创建了这段代码。你可以这样使用它:

var sf = smartForm.formatCC(myInputString);
var cardType = sf.cardType;

看看这个:

http://www.breakingpar.com/bkp/home.nsf/0/87256B280015193F87256CC70060A01B

function isValidCreditCard(type, ccnum) {
    /* Visa: length 16, prefix 4, dashes optional.
    Mastercard: length 16, prefix 51-55, dashes optional.
    Discover: length 16, prefix 6011, dashes optional.
    American Express: length 15, prefix 34 or 37.
    Diners: length 14, prefix 30, 36, or 38. */

    var re = new Regex({
        "visa": "/^4\d{3}-?\d{4}-?\d{4}-?\d",
        "mc": "/^5[1-5]\d{2}-?\d{4}-?\d{4}-?\d{4}$/",
        "disc": "/^6011-?\d{4}-?\d{4}-?\d{4}$/",
        "amex": "/^3[47]\d{13}$/",
        "diners": "/^3[068]\d{12}$/"
    }[type.toLowerCase()])

    if (!re.test(ccnum)) return false;
    // Remove all dashes for the checksum checks to eliminate negative numbers
    ccnum = ccnum.split("-").join("");
    // Checksum ("Mod 10")
    // Add even digits in even length strings or odd digits in odd length strings.
    var checksum = 0;
    for (var i = (2 - (ccnum.length % 2)); i <= ccnum.length; i += 2) {
        checksum += parseInt(ccnum.charAt(i - 1));
    }
    // Analyze odd digits in even length strings or even digits in odd length strings.
    for (var i = (ccnum.length % 2) + 1; i < ccnum.length; i += 2) {
        var digit = parseInt(ccnum.charAt(i - 1)) * 2;
        if (digit < 10) { checksum += digit; } else { checksum += (digit - 9); }
    }
    if ((checksum % 10) == 0) return true;
    else return false;
}

anatoly用PHP回答:

 public static function detectCardType($num)
 {
    $re = array(
        "visa"       => "/^4[0-9]{12}(?:[0-9]{3})?$/",
        "mastercard" => "/^5[1-5][0-9]{14}$/",
        "amex"       => "/^3[47][0-9]{13}$/",
        "discover"   => "/^6(?:011|5[0-9]{2})[0-9]{12}$/",
    );

    if (preg_match($re['visa'],$num))
    {
        return 'visa';
    }
    else if (preg_match($re['mastercard'],$num))
    {
        return 'mastercard';
    }
    else if (preg_match($re['amex'],$num))
    {
        return 'amex';
    }
    else if (preg_match($re['discover'],$num))
    {
        return 'discover';
    }
    else
    {
        return false;
    }
 }