在ng-options中选择一个项目可能有点棘手，这取决于您如何设置数据源。

在与它们斗争了一段时间后，我最终用我使用的最常用的数据源制作了一个样本。你可以在这里找到它:

http://plnkr.co/edit/fGq2PM?p=preview

现在要让ng-options工作，需要考虑以下几点:

Normally you get the options from one source and the selected value from other. For example: states :: data for ng-options user.state :: Option to set as selected Based on 1, the easiest/logical thing to do is to fill the select with one source and then set the selected value trough code. Rarely would it be better to get a mixed dataset. AngularJS allows select controls to hold more than key | label. Many online examples put objects as 'key', and if you need information from the object set it that way, otherwise use the specific property you need as key. (ID, CODE, etc.. As in the plckr sample) The way to set the value of the dropdown/select control depends on #3, If the dropdown key is a single property (like in all examples in the plunkr), you just set it, e.g.: $scope.dropdownmodel = $scope.user.state; If you set the object as key, you need to loop trough the options, even assigning the object will not set the item as selected as they will have different hashkeys, e.g.: for (var i = 0, len = $scope.options.length; i < len; i++) { if ($scope.options[i].id == savedValue) { // Your own property here: console.log('Found target! '); $scope.value = $scope.options[i]; break; } }

您可以在另一个对象$scope.myObject.myProperty中替换相同属性的savedValue。

一年后，我不得不找到这个问题的答案，因为这些问题都没有给出实际答案，至少对我来说是这样。

你问过如何选择选项，但没有人说这两件事不一样:

如果我们有这样的选项:

$scope.options = [
    { label: 'one', value: 1 },
    { label: 'two', value: 2 }
  ];

我们试着像这样设置一个默认选项:

$scope.incorrectlySelected = { label: 'two', value: 2 };

它不会工作，但如果你尝试选择这样的选项:

$scope.correctlySelected = $scope.options[1];

它会起作用的。

尽管这两个对象具有相同的属性，AngularJS仍然将它们视为DIFFERENT，因为AngularJS是通过引用进行比较的。

看看小提琴http://jsfiddle.net/qWzTb/。

我也有这个问题。我不能在ng-options中设置我的值。生成的每个选项都设置为0,1，…, n。

为了让它正确，我在ng-options中做了这样的事情:

HTML:

<select ng-options="room.name for room in Rooms track by room.price">
    <option value="">--Rooms--</option>
</select>

我使用“track by”来设置所有的room.price值。

(这个例子很糟糕:因为如果有多个价格相等，代码就会失败。所以一定要有不同的值。)

JSON:

$scope.Rooms = [
            { name: 'SALA01', price: 100 },
            { name: 'SALA02', price: 200 },
            { name: 'SALA03', price: 300 }
        ];

我从一篇博客文章中学会了如何使用Angular.JS ng-options & track by设置一个选择元素的初始选择值。

观看视频。这是一个很好的类:)

请使用属性跟踪来区分选择框中的值和标签。

请尝试

<select ng-options="obj.text for obj in array track by obj.value"></select>

它将为文本分配标签，并为value(来自数组)分配值

这个问题的正确答案由用户frm提供。Adiputra，因为目前这似乎是显式控制选项元素的value属性的唯一方法。

然而，我只是想强调，“select”在这里不是关键字，而只是表达式的占位符。请参考以下列表，“select”表达式的定义以及ng-options指令中可以使用的其他表达式。

问题中描述的select的用法:

ng-options='select p.text for p  in resultOptions'

本质上是错误的。

根据表达式列表，当在对象数组中给出选项时，似乎可以使用trackexpr来指定值，但它仅用于分组。

来自AngularJS的ng-options文档:

array / object: an expression which evaluates to an array / object to iterate over. value: local variable which will refer to each item in the array or each property value of object during iteration. key: local variable which will refer to a property name in object during iteration. label: The result of this expression will be the label for element. The expression will most likely refer to the value variable (e.g. value.propertyName). select: The result of this expression will be bound to the model of the parent element. If not specified, select expression will default to value. group: The result of this expression will be used to group options using the DOM element. trackexpr: Used when working with an array of objects. The result of this expression will be used to identify the objects in the array. The trackexpr will most likely refer to the value variable (e.g. value.propertyName).

<select ng-model="color" ng-options="(c.name+' '+c.shade) for c in colors"></select><br>