我有一个如下格式的文本文件。第一行是“KEY”,第二行是“VALUE”。

KEY 4048:1736 string
3
KEY 0:1772 string
1
KEY 4192:1349 string
1
KEY 7329:2407 string
2
KEY 0:1774 string
1

我需要这个值和键在同一行。所以输出应该是这样的…

KEY 4048:1736 string 3
KEY 0:1772 string 1
KEY 4192:1349 string 1
KEY 7329:2407 string 2
KEY 0:1774 string 1

如果我可以使用一些分隔符,如$或:

KEY 4048:1736 string , 3

我如何将两条线合并成一条?


当前回答

更通用的解决方案(允许连接多个后续行)是shell脚本。这在每一个之间增加了一条线,因为我需要可见性,但这很容易补救。在这个例子中,“key”行以:结尾,而其他行没有。

#!/bin/bash
#
# join "The rest of the story" when the first line of each   story
# matches $PATTERN
# Nice for looking for specific changes in bart output
#

PATTERN='*:';
LINEOUT=""
while read line; do
    case $line in
        $PATTERN)
                echo ""
                echo $LINEOUT
                LINEOUT="$line"
                        ;;
        "")
                LINEOUT=""
                echo ""
                ;;

        *)      LINEOUT="$LINEOUT $line"
                ;;
    esac        
done

其他回答

下面是另一种使用awk的方法:

awk 'ORS=NR%2?FS:RS' file

$ cat file KEY 4048:1736 string 3 KEY 0:1772 string 1 KEY 4192:1349 string 1 KEY 7329:2407 string 2 KEY 0:1774 string 1 $ awk 'ORS=NR%2?FS:RS' file KEY 4048:1736 string 3 KEY 0:1772 string 1 KEY 4192:1349 string 1 KEY 7329:2407 string 2 KEY 0:1774 string 1 As indicated by Ed Morton in the comments, it is better to add braces for safety and parens for portability. awk '{ ORS = (NR%2 ? FS : RS) } 1' file ORS stands for Output Record Separator. What we are doing here is testing a condition using the NR which stores the line number. If the modulo of NR is a true value (>0) then we set the Output Field Separator to the value of FS (Field Separator) which by default is space, else we assign the value of RS (Record Separator) which is newline. If you wish to add , as the separator then use the following: awk '{ ORS = (NR%2 ? "," : RS) } 1' file

更通用的解决方案(允许连接多个后续行)是shell脚本。这在每一个之间增加了一条线,因为我需要可见性,但这很容易补救。在这个例子中,“key”行以:结尾,而其他行没有。

#!/bin/bash
#
# join "The rest of the story" when the first line of each   story
# matches $PATTERN
# Nice for looking for specific changes in bart output
#

PATTERN='*:';
LINEOUT=""
while read line; do
    case $line in
        $PATTERN)
                echo ""
                echo $LINEOUT
                LINEOUT="$line"
                        ;;
        "")
                LINEOUT=""
                echo ""
                ;;

        *)      LINEOUT="$LINEOUT $line"
                ;;
    esac        
done

这是我在bash中的解决方案:

while read line1; do read line2; echo "$line1, $line2"; done < data.txt

粘贴很适合这个工作:

paste -d " "  - - < filename

awk:

awk 'NR%2{printf "%s ",$0;next;}1' yourFile

注意,在输出的末尾有一个空行。

sed:

sed 'N;s/\n/ /' yourFile