寻找返回目录中最新文件的命令。

没有看到ls的limit参数…


当前回答

试试这个简单的命令

ls -ltq  <path>  | head -n 1

如果需要文件名-最后修改,path = /ab/cd/*.log

如果要修改目录名称-最后一次修改,则path = /ab/cd/*/

其他回答

这是一个递归版本(即,它在某个目录或其任何子目录中查找最近更新的文件)

find /dir/path -type f -printf "%T@ %p\n" | sort -n | cut -d' ' -f 2- | tail -n 1

命令行简单的外行解释:

find /dir/path -type f finds all the files in the directory -printf "%T@ %p\n" prints a line for each file where %T@ is the float seconds since 1970 epoch and %p is the filename path and \n is the new line character for more info see man find | is a shell pipe (see man bash section on Pipelines) sort -n means to sort on the first column and to treat the token as numerical instead of lexicographic (see man sort) cut -d' ' -f 2- means to split each line using the character and then to print all tokens starting at the second token (see man cut) NOTE: -f 2 would print only the second token tail -n 1 means to print the last line (see man tail)

递归地:

find $1 -type f -exec stat --format '%Y :%y %n' "{}" \; | sort -nr | cut -d: -f2- | head

我喜欢echo *(om[1]) (zsh语法),因为它只给出文件名,而不调用任何其他命令。

ls -t -1 | sed '1q'

将显示文件夹中最后修改的项目。与grep配对以查找带有关键字的最新条目

ls -t -1 | grep foo | sed '1q'

我使用:

ls -ABrt1——group- directory -first | tail -n1 . ls -ABrt1——group- directory -first | tail -n1 . ls

它只给我文件名,不包括文件夹。