刚遇到这个问题，最简单的方法就是用moment:

你需要先安装moment和moment-range:

const Moment = require('moment');
const MomentRange = require('moment-range');
const moment = MomentRange.extendMoment(Moment);

const start = moment()
const end = moment().add(2, 'months')
const range = moment.range(start, end)
const arrayOfDates = Array.from(range.by('days'))
console.log(arrayOfDates)

这是一个罐装方法，它将接受Moment日期或字符串或混合作为输入，并生成一个日期数组作为Moment日期。如果不希望将Moment日期作为输出，则更改map()方法返回的内容。

const moment = require('moment');

// ...

/**
 * @param {string|import('moment').Moment} start
 * @param {string|import('moment').Moment} end
 * @returns {import('moment').Moment[]}
 */
const getDateRange = (start, end) => {
  const s = moment.isMoment(start) ? start : moment(start);
  const e = moment.isMoment(end) ? end : moment(end);
  return [...Array(1 + e.diff(s, 'days')).keys()].map(n => moment(s).add(n, 'days'));
};

Array(7).fill().map((_,i) => dayjs().subtract(i, "day").format("YYYY-MM-DD"));

var boxingDay = new Date("12/26/2010");
var nextWeek  = boxingDay*1 + 7*24*3600*1000;

function getDates( d1, d2 ){
  var oneDay = 24*3600*1000;
  for (var d=[],ms=d1*1,last=d2*1;ms<last;ms+=oneDay){
    d.push( new Date(ms) );
  }
  return d;
}

getDates( boxingDay, nextWeek ).join("\n");
// Sun Dec 26 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Mon Dec 27 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Tue Dec 28 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Wed Dec 29 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Thu Dec 30 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Fri Dec 31 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Sat Jan 01 2011 00:00:00 GMT-0700 (Mountain Standard Time)

不是最短的，而是简单的，不可变的，没有依赖关系

function datesArray(start, end) {
    let result = [], current = new Date(start);
    while (current <= end)
        result.push(current) && (current = new Date(current)) && current.setDate(current.getDate() + 1);
    return result;
}

使用

函数datesArray(start, end) { let result = []， current = new Date(start); While (current <= end) result.push(current) && (current = new Date(current)) && current. setdate (current. getdate () + 1); 返回结果; } / /使用 const test = datesArray( 新的日期(“2020-02-26”), 新日期(“2020-03-05”) ）; 对于(设I = 0;I < test.length;I ++) { console.log ( 测试[我].toISOString () .slice (0, 10) ）; }

我喜欢这样做

// hours * minutes * seconds * milliseconds
const DAY_IN_MS = 24 * 60 * 60 * 1000

/**
 * Get range of dates 
 * @param {Date} startDate 
 * @param {Number} numOfDays 
 * @returns {array}
 */
const dateRange = (startDate, numOfDays) => {
    const startDateMs = startDate.getTime()

    // get array of days and map it to Date object
    return [...Array(numOfDays).keys()].map(i => new Date(startDateMs + i * DAY_IN_MS))
}