我想进行base64编码和解码,但我无法从iPhone SDK中找到任何支持。我怎么能做base64编码和解码与或没有一个库?


当前回答

iOS 7

        NSData *data=[[NSData alloc]init];
        [data base64Encoding];

其他回答

我已经做到了使用以下类..

@implementation Base64Converter
static char base64EncodingTable[64] = {
'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L',  'M', 'N', 'O', 'P',
'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z', 'a', 'b', 'c', 'd', 'e', 'f',
'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v',
'w', 'x', 'y', 'z', '0', '1', '2', '3', '4', '5', '6', '7',    '8', '9', '+', '/'
};
+ (NSString *) base64StringFromData: (NSData *)data length: (int)length {

unsigned long ixtext, lentext;

long ctremaining;

unsigned char input[3], output[4];

short i, charsonline = 0, ctcopy;

const unsigned char *raw;

NSMutableString *result;

lentext = [data length];

if (lentext < 1)
    return @"";

result = [NSMutableString stringWithCapacity: lentext];

raw = [data bytes];

ixtext = 0;

while (true) {

    ctremaining = lentext - ixtext;

    if (ctremaining <= 0)
        break;

    for (i = 0; i < 3; i++) {
        unsigned long ix = ixtext + i;
        if (ix < lentext)
            input[i] = raw[ix];
        else
            input[i] = 0;
    }

    output[0] = (input[0] & 0xFC) >> 2;

    output[1] = ((input[0] & 0x03) << 4) | ((input[1] & 0xF0) >> 4);

    output[2] = ((input[1] & 0x0F) << 2) | ((input[2] & 0xC0) >> 6);

    output[3] = input[2] & 0x3F;

    ctcopy = 4;

    switch (ctremaining) {
        case 1:
            ctcopy = 2;
            break;

        case 2:
            ctcopy = 3;
            break;
    }

    for (i = 0; i < ctcopy; i++)
        [result appendString: [NSString stringWithFormat: @"%c", base64EncodingTable[output[i]]]];

    for (i = ctcopy; i < 4; i++)
        [result appendString: @"="];

    ixtext += 3;

    charsonline += 4;

    if ((length > 0) && (charsonline >= length))
        charsonline = 0;
}
return result;
}
@end

打电话的时候

 [Base64Converter base64StringFromData:dataval length:lengthval];

就是这样……

在mvds的出色改进中,存在两个问题。更改代码如下:

raw = tmpbuf;
inp = 0;
outbuf[outp++] = base64EncodingTable[(raw[inp] & 0xFC) >> 2];
outbuf[outp++] = base64EncodingTable[((raw[inp] & 0x03) << 4) | ((raw[inp+1] & 0xF0) >> 4)];
if ( left == 2 ) outbuf[outp++] = base64EncodingTable[((raw[inp+1] & 0x0F) << 2) | ((raw[inp+2] & 0xC0) >> 6)];
else outbuf[outp++] = '=';
outbuf[outp++] = '=';

在这个问题最初发布的时候,人们可以理解地引导您使用第三方base64库,因为缺乏任何本地例程。但iOS 7引入了base64编码例程(这实际上只是暴露了iOS从iOS 4开始就有的私有方法)。

你可以使用NSData方法base64EncodedStringWithOptions:从NSData创建一个base-64字符串。

NSString *string = [data base64EncodedStringWithOptions:kNilOptions];

你可以使用initWithBase64EncodedString:options:将一个base-64字符串转换回NSData:

NSData *data = [[NSData alloc] initWithBase64EncodedString:string options:kNilOptions]; 

或者,在Swift中:

let string = data.base64EncodedString()

And

let data = Data(base64Encoded: string)

更好的解决方案:

NSData中有一个内置函数

[data base64Encoding]; //iOS < 7.0
[data base64EncodedStringWithOptions:NSDataBase64Encoding76CharacterLineLength]; //iOS >= 7.0

我想这会有帮助的

 + (NSString *)toBase64String:(NSString *)string {
    NSData *data = [string dataUsingEncoding: NSUnicodeStringEncoding];

    NSString *ret = [data base64EncodedStringWithOptions:NSDataBase64Encoding64CharacterLineLength];

    return ret;
    }

    + (NSString *)fromBase64String:(NSString *)string {
NSData *aData = [string dataUsingEncoding:NSUTF8StringEncoding];
NSData *aDataDecoded = [[NSData alloc]initWithBase64EncodedString:string options:0];
NSString *decryptedStr = [[NSString alloc]initWithData:aDataDecoded encoding:NSUTF8StringEncoding];

return [decryptedStr autorelease];

}