上面的一些正则表达式有点限制性。请注意真正的邮政编码:“W1K 7AA”将失败，因为上面的“位置3 - AEHMNPRTVXY仅使用”规则将不允许“K”。

正则表达式:

^(GIR 0AA|[A-PR-UWYZ]([0-9]{1,2}|([A-HK-Y][0-9]|[A-HK-Y][0-9]([0-9]|[ABEHMNPRV-Y]))|[0-9][A-HJKPS-UW])[0-9][ABD-HJLNP-UW-Z]{2})$

似乎更准确一点，请参阅维基百科上题为“英国的邮政编码”的文章。

注意，这个正则表达式只要求大写字符。

更大的问题是，您是限制用户输入，只允许实际存在的邮政编码，还是只是试图阻止用户在表单字段中输入完全的垃圾。正确匹配每一个可能的邮政编码，并在未来校对，是一个更难的难题，除非你是HMRC，否则可能不值得这么做。

下面的方法将检查邮政编码并提供完整的信息

const isValidUKPostcode = postcode => {
    try {
        postcode = postcode.replace(/\s/g, "");
        const fromat = postcode
            .toUpperCase()
            .match(/^([A-Z]{1,2}\d{1,2}[A-Z]?)\s*(\d[A-Z]{2})$/);
        const finalValue = `${fromat[1]} ${fromat[2]}`;
        const regex = /^([Gg][Ii][Rr] 0[Aa]{2})|((([A-Za-z][0-9]{1,2})|(([A-Za-z][A-Ha-hJ-Yj-y][0-9]{1,2})|(([AZa-z][0-9][A-Za-z])|([A-Za-z][A-Ha-hJ-Yj-y][0-9]?[A-Za-z]))))[0-9][A-Za-z]{2})$/i;
        return {
            isValid: regex.test(postcode),
            formatedPostCode: finalValue,
            error: false,
            message: 'It is a valid postcode'
        };
    } catch (error) {
        return { error: true , message: 'Invalid postcode'};
    }
};

console.log(isValidUKPostcode('GU348RR'))
{isValid: true, formattedPostcode: "GU34 8RR", error: false, message: "It is a valid postcode"}

console.log(isValidUKPostcode('sdasd4746asd'))
{error: true, message: "Invalid postcode!"}

valid_postcode('787898523')
result => {error: true, message: "Invalid postcode"}

下面是一个基于链接到marcj答案的文档中指定格式的正则表达式:

/^[A-Z]{1,2}[0-9][0-9A-Z]? ?[0-9][A-Z]{2}$/

这和规格之间的唯一区别是，根据规格，最后两个字符不能在[CIKMOV]中。

编辑: 下面是另一个测试末尾字符限制的版本。

/^[A-Z]{1,2}[0-9][0-9A-Z]? ?[0-9][A-BD-HJLNP-UW-Z]{2}$/

我有英国邮政编码验证的正则表达式。

这是适用于所有类型的邮政编码，无论是内部或外部

^((([A-PR-UWYZ][0-9])|([A-PR-UWYZ][0-9][0-9])|([A-PR-UWYZ][A-HK-Y][0-9])|([A-PR-UWYZ][A-HK-Y][0-9][0-9])|([A-PR-UWYZ][0-9][A-HJKSTUW])|([A-PR-UWYZ][A-HK-Y][0-9][ABEHMNPRVWXY]))) || ^((GIR)[ ]?(0AA))$|^(([A-PR-UWYZ][0-9])[ ]?([0-9][ABD-HJLNPQ-UW-Z]{0,2}))$|^(([A-PR-UWYZ][0-9][0-9])[ ]?([0-9][ABD-HJLNPQ-UW-Z]{0,2}))$|^(([A-PR-UWYZ][A-HK-Y0-9][0-9])[ ]?([0-9][ABD-HJLNPQ-UW-Z]{0,2}))$|^(([A-PR-UWYZ][A-HK-Y0-9][0-9][0-9])[ ]?([0-9][ABD-HJLNPQ-UW-Z]{0,2}))$|^(([A-PR-UWYZ][0-9][A-HJKS-UW0-9])[ ]?([0-9][ABD-HJLNPQ-UW-Z]{0,2}))$|^(([A-PR-UWYZ][A-HK-Y0-9][0-9][ABEHMNPRVWXY0-9])[ ]?([0-9][ABD-HJLNPQ-UW-Z]{0,2}))$

这适用于所有类型的格式。

例子:

Ab10 -------------------->仅为外部邮政编码 A1 1 aa ------------------> (内部和外部)邮政编码的组合 WC2A --------------------> 外

我需要一个可以在SAS中使用PRXMATCH和相关函数的版本，所以我想到了这个:

^[A-PR-UWYZ](([A-HK-Y]?\d\d?)|(\d[A-HJKPSTUW])|([A-HK-Y]\d[ABEHMNPRV-Y]))\s?\d[ABD-HJLNP-UW-Z]{2}$

测试用例和注意事项:

/* 
Notes
The letters QVX are not used in the 1st position.
The letters IJZ are not used in the second position.
The only letters to appear in the third position are ABCDEFGHJKPSTUW when the structure starts with A9A.
The only letters to appear in the fourth position are ABEHMNPRVWXY when the structure starts with AA9A.
The final two letters do not use the letters CIKMOV, so as not to resemble digits or each other when hand-written.
*/

/*
    Bits and pieces
    1st position (any):         [A-PR-UWYZ]         
    2nd position (if letter):   [A-HK-Y]
    3rd position (A1A format):  [A-HJKPSTUW]
    4th position (AA1A format): [ABEHMNPRV-Y]
    Last 2 positions:           [ABD-HJLNP-UW-Z]    
*/


data example;
infile cards truncover;
input valid 1. postcode &$10. Notes &$100.;
flag = prxmatch('/^[A-PR-UWYZ](([A-HK-Y]?\d\d?)|(\d[A-HJKPSTUW])|([A-HK-Y]\d[ABEHMNPRV-Y]))\s?\d[ABD-HJLNP-UW-Z]{2}$/',strip(postcode));
cards;
1  EC1A 1BB  Special case 1
1  W1A 0AX   Special case 2
1  M1 1AE    Standard format
1  B33 8TH   Standard format
1  CR2 6XH   Standard format
1  DN55 1PT  Standard format
0  QN55 1PT  Bad letter in 1st position
0  DI55 1PT  Bad letter in 2nd position
0  W1Z 0AX   Bad letter in 3rd position
0  EC1Z 1BB  Bad letter in 4th position
0  DN55 1CT  Bad letter in 2nd group
0  A11A 1AA  Invalid digits in 1st group
0  AA11A 1AA  1st group too long
0  AA11 1AAA  2nd group too long
0  AA11 1AAA  2nd group too long
0  AAA 1AA   No digit in 1st group
0  AA 1AA    No digit in 1st group
0  A 1AA     No digit in 1st group
0  1A 1AA    Missing letter in 1st group
0  1 1AA     Missing letter in 1st group
0  11 1AA    Missing letter in 1st group
0  AA1 1A    Missing letter in 2nd group
0  AA1 1     Missing letter in 2nd group
;
run;

通过经验测试和观察，以及https://en.wikipedia.org/wiki/Postcodes_in_the_United_Kingdom#Validation的确认，以下是我的Python正则表达式版本，可以正确地解析和验证英国邮政编码:

UK_POSTCODE_REGEX = r ' (? P < postcode_area > [a - z] {1,2}) (? P <区> (?:[0 - 9]{1,2})| (?:[0 - 9][a - z])) (? P <部门> [0 - 9])(? P <邮编> [a - z]{2})”

这个正则表达式很简单，并且有捕获组。它不包括所有合法的英国邮政编码的验证，而只考虑字母与数字的位置。

下面是我在代码中如何使用它:

@dataclass
class UKPostcode:
    postcode_area: str
    district: str
    sector: int
    postcode: str

    # https://en.wikipedia.org/wiki/Postcodes_in_the_United_Kingdom#Validation
    # Original author of this regex: @jontsai
    # NOTE TO FUTURE DEVELOPER:
    # Verified through empirical testing and observation, as well as confirming with the Wiki article
    # If this regex fails to capture all valid UK postcodes, then I apologize, for I am only human.
    UK_POSTCODE_REGEX = r'(?P<postcode_area>[A-Z]{1,2})(?P<district>(?:[0-9]{1,2})|(?:[0-9][A-Z]))(?P<sector>[0-9])(?P<postcode>[A-Z]{2})'

    @classmethod
    def from_postcode(cls, postcode):
        """Parses a string into a UKPostcode

        Returns a UKPostcode or None
        """
        m = re.match(cls.UK_POSTCODE_REGEX, postcode.replace(' ', ''))

        if m:
            uk_postcode = UKPostcode(
                postcode_area=m.group('postcode_area'),
                district=m.group('district'),
                sector=m.group('sector'),
                postcode=m.group('postcode')
            )
        else:
            uk_postcode = None

        return uk_postcode


def parse_uk_postcode(postcode):
    """Wrapper for UKPostcode.from_postcode
    """
    uk_postcode = UKPostcode.from_postcode(postcode)
    return uk_postcode

下面是单元测试:

@pytest.mark.parametrize(
    'postcode, expected', [
        # https://en.wikipedia.org/wiki/Postcodes_in_the_United_Kingdom#Validation
        (
            'EC1A1BB',
            UKPostcode(
                postcode_area='EC',
                district='1A',
                sector='1',
                postcode='BB'
            ),
        ),
        (
            'W1A0AX',
            UKPostcode(
                postcode_area='W',
                district='1A',
                sector='0',
                postcode='AX'
            ),
        ),
        (
            'M11AE',
            UKPostcode(
                postcode_area='M',
                district='1',
                sector='1',
                postcode='AE'
            ),
        ),
        (
            'B338TH',
            UKPostcode(
                postcode_area='B',
                district='33',
                sector='8',
                postcode='TH'
            )
        ),
        (
            'CR26XH',
            UKPostcode(
                postcode_area='CR',
                district='2',
                sector='6',
                postcode='XH'
            )
        ),
        (
            'DN551PT',
            UKPostcode(
                postcode_area='DN',
                district='55',
                sector='1',
                postcode='PT'
            )
        )
    ]
)
def test_parse_uk_postcode(postcode, expected):
    uk_postcode = parse_uk_postcode(postcode)
    assert(uk_postcode == expected)