在我正在处理的提取中,我有2个datetime列。一列存储日期,另一列存储如下所示的时间。

如何查询表,将这两个字段组合成类型为datetime的1列?

日期

2009-03-12 00:00:00.000
2009-03-26 00:00:00.000
2009-03-26 00:00:00.000

1899-12-30 12:30:00.000
1899-12-30 10:00:00.000
1899-12-30 10:00:00.000

当前回答

这对我很有效

CAST(Tbl.date as DATETIME) + CAST(Tbl.TimeFrom AS TIME)

(适用于SQL 2008 R2)

其他回答

DECLARE @Dates table ([Date] datetime);
DECLARE @Times table ([Time] datetime);

INSERT INTO @Dates VALUES('2009-03-12 00:00:00.000');
INSERT INTO @Dates VALUES('2009-03-26 00:00:00.000');
INSERT INTO @Dates VALUES('2009-03-30 00:00:00.000');

INSERT INTO @Times VALUES('1899-12-30 12:30:00.000');
INSERT INTO @Times VALUES('1899-12-30 10:00:00.000');
INSERT INTO @Times VALUES('1899-12-30 10:00:00.000');

WITH Dates (ID, [Date])
AS (
    SELECT ROW_NUMBER() OVER (ORDER BY [Date]), [Date] FROM @Dates
), Times (ID, [Time])
AS (
    SELECT ROW_NUMBER() OVER (ORDER BY [Time]), [Time] FROM @Times
)
SELECT Dates.[Date] + Times.[Time] FROM Dates
    JOIN Times ON Times.ID = Dates.ID

打印:

2009-03-12 10:00:00.000
2009-03-26 10:00:00.000
2009-03-30 12:30:00.000

如上所述,我有很多错误,所以我这样做

try_parse(concat(convert(date,Arrival_date),' ',arrival_time) as datetime) AS ArrivalDateTime

这对我很管用。

select s.SalesID from SalesTbl s 
        where cast(cast(s.SaleDate  as date) as datetime) + cast(cast(s.SaleCreatedDate as time) as datetime) between @FromDate and @ToDate

如果两个字段都是datetime,那么简单地添加它们就可以了。 例如: 声明@d datetime, @t datetime Set @d = '2009-03-12 00:00:00.000'; Set @t = ' 189-12-30 12:30:00.000'; 选择@d + @t 如果您使用Date & Time数据类型,则只需将时间转换为datetime 例如: 声明@d日期,@t时间 Set @d = '2009-03-12'; Set @t = '12:30:00.000'; 选择@d + cast(@t as datetime)

将两个字段转换为DATETIME:

SELECT CAST(@DateField as DATETIME) + CAST(@TimeField AS DATETIME)

如果你正在使用Getdate(),首先使用这个:

DECLARE @FechaActual DATETIME = CONVERT(DATE, GETDATE());
SELECT CAST(@FechaActual as DATETIME) + CAST(@HoraInicioTurno AS DATETIME)