不确定这种方法是否有任何缺点，但更小，在views.py中:

entry = form.save()

# save uploaded file
if request.FILES['myfile']:
    entry.myfile.save(request.FILES['myfile']._name, request.FILES['myfile'], True)

你可以参考Fine Uploader中的服务器示例，它有django版本。 https://github.com/FineUploader/server-examples/tree/master/python/django-fine-uploader

它非常优雅，最重要的是，它提供了特色的js lib。Template不包含在服务器示例中，但是你可以在它的网站上找到demo。 精美上传:http://fineuploader.com/demos.html

django-fine-uploader

views.py

UploadView将post和delete请求分派给各自的处理程序。

class UploadView(View):

    @csrf_exempt
    def dispatch(self, *args, **kwargs):
        return super(UploadView, self).dispatch(*args, **kwargs)

    def post(self, request, *args, **kwargs):
        """A POST request. Validate the form and then handle the upload
        based ont the POSTed data. Does not handle extra parameters yet.
        """
        form = UploadFileForm(request.POST, request.FILES)
        if form.is_valid():
            handle_upload(request.FILES['qqfile'], form.cleaned_data)
            return make_response(content=json.dumps({ 'success': True }))
        else:
            return make_response(status=400,
                content=json.dumps({
                    'success': False,
                    'error': '%s' % repr(form.errors)
                }))

    def delete(self, request, *args, **kwargs):
        """A DELETE request. If found, deletes a file with the corresponding
        UUID from the server's filesystem.
        """
        qquuid = kwargs.get('qquuid', '')
        if qquuid:
            try:
                handle_deleted_file(qquuid)
                return make_response(content=json.dumps({ 'success': True }))
            except Exception, e:
                return make_response(status=400,
                    content=json.dumps({
                        'success': False,
                        'error': '%s' % repr(e)
                    }))
        return make_response(status=404,
            content=json.dumps({
                'success': False,
                'error': 'File not present'
            }))

forms.py

class UploadFileForm(forms.Form):

    """ This form represents a basic request from Fine Uploader.
    The required fields will **always** be sent, the other fields are optional
    based on your setup.
    Edit this if you want to add custom parameters in the body of the POST
    request.
    """
    qqfile = forms.FileField()
    qquuid = forms.CharField()
    qqfilename = forms.CharField()
    qqpartindex = forms.IntegerField(required=False)
    qqchunksize = forms.IntegerField(required=False)
    qqpartbyteoffset = forms.IntegerField(required=False)
    qqtotalfilesize = forms.IntegerField(required=False)
    qqtotalparts = forms.IntegerField(required=False)

不确定这种方法是否有任何缺点，但更小，在views.py中:

entry = form.save()

# save uploaded file
if request.FILES['myfile']:
    entry.myfile.save(request.FILES['myfile']._name, request.FILES['myfile'], True)

我也有类似的要求。网上的大多数例子都要求创建模型和表单，我不想使用。这是我的最终代码。

if request.method == 'POST':
    file1 = request.FILES['file']
    contentOfFile = file1.read()
    if file1:
        return render(request, 'blogapp/Statistics.html', {'file': file1, 'contentOfFile': contentOfFile})

在HTML中我写了:

{% block content %}
    <h1>File content</h1>
    <form action="{% url 'blogapp:uploadComplete'%}" method="post" enctype="multipart/form-data">
         {% csrf_token %}
        <input id="uploadbutton" type="file" value="Browse" name="file" accept="text/csv" />
        <input type="submit" value="Upload" />
    </form>
    {% endblock %}

下面是显示文件内容的HTML:

{% block content %}
    <h3>File uploaded successfully</h3>
    {{file.name}}
    </br>content = {{contentOfFile}}
{% endblock %}

以亨利为例:

import tempfile
import shutil

FILE_UPLOAD_DIR = '/home/imran/uploads'

def handle_uploaded_file(source):
    fd, filepath = tempfile.mkstemp(prefix=source.name, dir=FILE_UPLOAD_DIR)
    with open(filepath, 'wb') as dest:
        shutil.copyfileobj(source, dest)
    return filepath

你可以在上传文件对象的视图中调用handle_uploaded_file函数。这将在文件系统中保存具有唯一名称的文件(以原始上传文件的文件名作为前缀)，并返回所保存文件的完整路径。您可以将该路径保存在数据库中，稍后对该文件进行处理。

我必须说我发现django的文档令人困惑。 还有一个最简单的例子，为什么要提到表单? 我在views.py中工作的例子是:-

for key, file in request.FILES.items():
    path = file.name
    dest = open(path, 'w')
    if file.multiple_chunks:
        for c in file.chunks():
            dest.write(c)
    else:
        dest.write(file.read())
    dest.close()

html文件看起来像下面的代码，尽管这个例子只上传了一个文件，保存文件的代码处理许多:-

<form action="/upload_file/" method="post" enctype="multipart/form-data">{% csrf_token %}
<label for="file">Filename:</label>
<input type="file" name="file" id="file" />
<br />
<input type="submit" name="submit" value="Submit" />
</form>

这些示例不是我的代码，它们是从我找到的其他两个示例中选取的。 我是一个相对初学者django，所以很可能我错过了一些关键点。