如何从Node.js中的HTTP post方法中提取表单数据(form[method="post"])和文件上传?
我看了文件,谷歌了一下,什么都没找到。
function (request, response) {
//request.post????
}
有图书馆或黑客吗?
如何从Node.js中的HTTP post方法中提取表单数据(form[method="post"])和文件上传?
我看了文件,谷歌了一下,什么都没找到。
function (request, response) {
//request.post????
}
有图书馆或黑客吗?
当前回答
下面是一个非常简单的无框架包装,基于这里发布的其他答案和文章:
var http = require('http');
var querystring = require('querystring');
function processPost(request, response, callback) {
var queryData = "";
if(typeof callback !== 'function') return null;
if(request.method == 'POST') {
request.on('data', function(data) {
queryData += data;
if(queryData.length > 1e6) {
queryData = "";
response.writeHead(413, {'Content-Type': 'text/plain'}).end();
request.connection.destroy();
}
});
request.on('end', function() {
request.post = querystring.parse(queryData);
callback();
});
} else {
response.writeHead(405, {'Content-Type': 'text/plain'});
response.end();
}
}
使用的例子:
http.createServer(function(request, response) {
if(request.method == 'POST') {
processPost(request, response, function() {
console.log(request.post);
// Use request.post here
response.writeHead(200, "OK", {'Content-Type': 'text/plain'});
response.end();
});
} else {
response.writeHead(200, "OK", {'Content-Type': 'text/plain'});
response.end();
}
}).listen(8000);
其他回答
如果希望表单数据在req.body中可用,则需要使用bodyParser()。 Body-parser解析您的请求并将其转换为可以轻松提取所需相关信息的格式。
例如,假设在前端有一个注册表单。您正在填写它,并请求服务器将详细信息保存在某个地方。
如果使用体解析器,则从请求中提取用户名和密码如下所示。
.............................................................
var loginDetails = {
username : request.body.username,
password : request.body.password
};
对于那些使用原始二进制POST上传没有编码开销,你可以使用:
客户:
var xhr = new XMLHttpRequest();
xhr.open("POST", "/api/upload", true);
var blob = new Uint8Array([65,72,79,74]); // or e.g. recorder.getBlob()
xhr.send(blob);
服务器:
var express = require('express');
var router = express.Router();
var fs = require('fs');
router.use (function(req, res, next) {
var data='';
req.setEncoding('binary');
req.on('data', function(chunk) {
data += chunk;
});
req.on('end', function() {
req.body = data;
next();
});
});
router.post('/api/upload', function(req, res, next) {
fs.writeFile("binaryFile.png", req.body, 'binary', function(err) {
res.send("Binary POST successful!");
});
});
如果你将数据编码为JSON,然后将其发送到Node.js,会更简洁。
function (req, res) {
if (req.method == 'POST') {
var jsonString = '';
req.on('data', function (data) {
jsonString += data;
});
req.on('end', function () {
console.log(JSON.parse(jsonString));
});
}
}
如果你从POST接收到JSON格式的数据。:
import http from 'http';
const hostname = '127.0.0.1';
const port = 3000;
const httpServer: http.Server = http.createServer((req: http.IncomingMessage, res:
http.ServerResponse) => {
if(req.method === 'POST') {
let body: string = '';
req.on('data',(chunck) => {
body += chunck;
});
req.on('end', () => {
const body = JSON.parse(body);
res.statusCode = 200;
res.end('OK post');
});
}
});
httpServer.listen(port, hostname, () => {
console.info(`Server started at port ${port}`);
})
要详细说明使用URLSearchParams:
Node.js知识:如何读取POST数据? 类:URLSearchParams .js文档 MDN: URLSearchParams
const http = require('http');
const POST_HTML =
'<html><head><title>Post Example</title></head>' +
'<body>' +
'<form method="post">' +
'Input 1: <input name="input1"><br>' +
'Input 2: <input name="input2"><br>' +
'Input 1: <input name="input1"><br>' +
'<input type="submit">' +
'</form>' +
'</body></html>';
const FORM_DATA = 'application/x-www-form-urlencoded';
function processFormData(body) {
const params = new URLSearchParams(body);
for ([name, value] of params.entries()) console.log(`${name}: ${value}`);
}
// req: http.IncomingMessage
// res: http.ServerResponse
//
function requestListener(req, res) {
const contentType = req.headers['content-type'];
let body = '';
const append = (chunk) => {
body += chunk;
};
const complete = () => {
if (contentType === FORM_DATA) processFormData(body);
res.writeHead(200);
res.end(POST_HTML);
};
req.on('data', append);
req.on('end', complete);
}
http.createServer(requestListener).listen(8080);
$ node index.js
input1: one
input2: two
input1: three