在我的Angular应用中，我有一个组件:
import { MakeService } from './../../services/make.service';
import { Component, OnInit } from '@angular/core';
@Component({
selector: 'app-vehicle-form',
templateUrl: './vehicle-form.component.html',
styleUrls: ['./vehicle-form.component.css']
})
export class VehicleFormComponent implements OnInit {
makes: any[];
vehicle = {};
constructor(private makeService: MakeService) { }
ngOnInit() {
this.makeService.getMakes().subscribe(makes => { this.makes = makes
console.log("MAKES", this.makes);
});
}
onMakeChange(){
console.log("VEHICLE", this.vehicle);
}
}
但是在“制造”属性中我犯了一个错误。
我不知道该怎么办……
转到你的tsconfig。Json文件，并更改属性:
"noImplicitReturns": false
然后加上
"strictPropertyInitialization": false
在"compilerOptions"属性下。
你的tsconfig。Json文件应该是这样的:
{
...
"compilerOptions": {
....
"noImplicitReturns": false,
....
"strictPropertyInitialization": false
},
"angularCompilerOptions": {
......
}
}
希望这能有所帮助!!
祝你好运
这个已经在Angular Github的https://github.com/angular/angular/issues/24571上讨论过了
我认为这是每个人都会转向的方向
引用自https://github.com/angular/angular/issues/24571#issuecomment-404606595
For angular components, use the following rules in deciding between:
a) adding initializer
b) make the field optional
c) leave the '!'
If the field is annotated with @input - Make the field optional b) or add an initializer a).
If the input is required for the component user - add an assertion in ngOnInit and apply c.
If the field is annotated @ViewChild, @ContentChild - Make the field optional b).
If the field is annotated with @ViewChildren or @ContentChildren - Add back '!' - c).
Fields that have an initializer, but it lives in ngOnInit. - Move the initializer to the constructor.
Fields that have an initializer, but it lives in ngOnInit and cannot be moved because it depends on other @input fields - Add back '!' - c).
