你也可以用纯JS来做:

// Create the XHR object.
function createCORSRequest(method, url) {
  var xhr = new XMLHttpRequest();
if ("withCredentials" in xhr) {
// XHR for Chrome/Firefox/Opera/Safari.
xhr.open(method, url, true);
} else if (typeof XDomainRequest != "undefined") {
// XDomainRequest for IE.
xhr = new XDomainRequest();
xhr.open(method, url);
} else {
// CORS not supported.
xhr = null;
}
return xhr;
}

// Make the actual CORS request.
function makeCorsRequest() {
 // This is a sample server that supports CORS.
 var url = 'http://html5rocks-cors.s3-website-us-east-1.amazonaws.com/index.html';

var xhr = createCORSRequest('GET', url);
if (!xhr) {
alert('CORS not supported');
return;
}

// Response handlers.
xhr.onload = function() {
var text = xhr.responseText;
alert('Response from CORS request to ' + url + ': ' + text);
};

xhr.onerror = function() {
alert('Woops, there was an error making the request.');
};

xhr.send();
}

详见:html5rocks教程

现代、干净、简洁

fetch('https://baconipsum.com/api/?type=1')

让url = 'https://baconipsum.com/api/?type=all-meat&paras=1&start-with-lorem=2'; //只发送GET请求而不等待响应 fetch (url); //使用then来等待结果 获取(url)。然后(r = > r.json()。then(j=> console.log('\nREQUEST 2'，j))); //或async/await (异步()= > console.log('\nREQUEST 3'， await(await fetch(url)).json()) ) (); 打开Chrome控制台网络选项卡查看请求

一种支持旧浏览器的解决方案:

function httpRequest() {
    var ajax = null,
        response = null,
        self = this;

    this.method = null;
    this.url = null;
    this.async = true;
    this.data = null;

    this.send = function() {
        ajax.open(this.method, this.url, this.asnyc);
        ajax.send(this.data);
    };

    if(window.XMLHttpRequest) {
        ajax = new XMLHttpRequest();
    }
    else if(window.ActiveXObject) {
        try {
            ajax = new ActiveXObject("Msxml2.XMLHTTP.6.0");
        }
        catch(e) {
            try {
                ajax = new ActiveXObject("Msxml2.XMLHTTP.3.0");
            }
            catch(error) {
                self.fail("not supported");
            }
        }
    }

    if(ajax == null) {
        return false;
    }

    ajax.onreadystatechange = function() {
        if(this.readyState == 4) {
            if(this.status == 200) {
                self.success(this.responseText);
            }
            else {
                self.fail(this.status + " - " + this.statusText);
            }
        }
    };
}

这段代码可能有点过分，但绝对是安全的。

用法:

//create request with its porperties
var request = new httpRequest();
request.method = "GET";
request.url = "https://example.com/api?parameter=value";

//create callback for success containing the response
request.success = function(response) {
    console.log(response);
};

//and a fail callback containing the error
request.fail = function(error) {
    console.log(error);
};

//and finally send it away
request.send();

为了刷新来自joann的最佳答案，这是我的代码:

let httpRequestAsync = (method, url) => {
    return new Promise(function (resolve, reject) {
        var xhr = new XMLHttpRequest();
        xhr.open(method, url);
        xhr.onload = function () {
            if (xhr.status == 200) {
                resolve(xhr.responseText);
            }
            else {
                reject(new Error(xhr.responseText));
            }
        };
        xhr.send();
    });
}

function get(path) {
    var form = document.createElement("form");
    form.setAttribute("method", "get");
    form.setAttribute("action", path);
    document.body.appendChild(form);
    form.submit();
}


get('/my/url/')

同样的事情也可以为post request做。 看看这个链接JavaScript post请求像一个表单提交

原型让它变得非常简单

new Ajax.Request( '/myurl', {
  method:  'get',
  parameters:  { 'param1': 'value1'},
  onSuccess:  function(response){
    alert(response.responseText);
  },
  onFailure:  function(){
    alert('ERROR');
  }
});