这里有很多有效的答案，它们都是在方法中实现的。为了制作一个通用的计时方法，我通常有一个timing类，它由以下内容组成。

public record TimedResult<T>(T result, Duration duration) {}

public static Duration time(Runnable r) {
    var s = Instant.now();
    r.run();
    var dur = Duration.between(s, Instant.now());
    return dur;
}

public static <T> TimedResult<T> time(Callable<T> r) throws Exception {
    var s = Instant.now();
    T res = r.call();
    var dur = Duration.between(s, Instant.now());
    return new TimedResult<>(res, dur);
}

这足够通用，可以传递Runnable或Callable对象。

Duration result = Timing.time(() -> {
    // do some work.
});

TimedResult<String> result = Timing.time(() -> {
    // do some work.
    return "answer";
});

Duration timeTaken = result.duration();
String answer = result.result();

总有一些过时的方法:

long startTime = System.nanoTime();
methodToTime();
long endTime = System.nanoTime();

long duration = (endTime - startTime);  //divide by 1000000 to get milliseconds.

如果你想要时间

long start_time = System.currentTimeMillis();
object.method();
long end_time = System.currentTimeMillis();
long execution_time = end_time - start_time;

这里有很多有效的答案，它们都是在方法中实现的。为了制作一个通用的计时方法，我通常有一个timing类，它由以下内容组成。

public record TimedResult<T>(T result, Duration duration) {}

public static Duration time(Runnable r) {
    var s = Instant.now();
    r.run();
    var dur = Duration.between(s, Instant.now());
    return dur;
}

public static <T> TimedResult<T> time(Callable<T> r) throws Exception {
    var s = Instant.now();
    T res = r.call();
    var dur = Duration.between(s, Instant.now());
    return new TimedResult<>(res, dur);
}

这足够通用，可以传递Runnable或Callable对象。

Duration result = Timing.time(() -> {
    // do some work.
});

TimedResult<String> result = Timing.time(() -> {
    // do some work.
    return "answer";
});

Duration timeTaken = result.duration();
String answer = result.result();

对于java 8+，另一种可能的解决方案(更通用，函数风格，没有方面)可能是创建一些实用程序方法，将代码作为参数接受

public static <T> T timed (String description, Consumer<String> out, Supplier<T> code) {
    final LocalDateTime start = LocalDateTime.now ();
    T res = code.get ();
    final long execTime = Duration.between (start, LocalDateTime.now ()).toMillis ();
    out.accept (String.format ("%s: %d ms", description, execTime));
    return res;
}

调用代码可以是这样的smth:

public static void main (String[] args) throws InterruptedException {
    timed ("Simple example", System.out::println, Timing::myCode);
}

public static Object myCode () {
    try {
        Thread.sleep (1500);
    } catch (InterruptedException e) {
        e.printStackTrace ();
    }
    return null;
}

我已经编写了一个方法，以易于阅读的形式打印方法执行时间。 例如，要计算100万的阶乘，大约需要9分钟。因此，执行时间打印为:

Execution Time: 9 Minutes, 36 Seconds, 237 MicroSeconds, 806193 NanoSeconds

代码在这里:

public class series
{
    public static void main(String[] args)
    {
        long startTime = System.nanoTime();

        long n = 10_00_000;
        printFactorial(n);

        long endTime = System.nanoTime();
        printExecutionTime(startTime, endTime);

    }

    public static void printExecutionTime(long startTime, long endTime)
    {
        long time_ns = endTime - startTime;
        long time_ms = TimeUnit.NANOSECONDS.toMillis(time_ns);
        long time_sec = TimeUnit.NANOSECONDS.toSeconds(time_ns);
        long time_min = TimeUnit.NANOSECONDS.toMinutes(time_ns);
        long time_hour = TimeUnit.NANOSECONDS.toHours(time_ns);

        System.out.print("\nExecution Time: ");
        if(time_hour > 0)
            System.out.print(time_hour + " Hours, ");
        if(time_min > 0)
            System.out.print(time_min % 60 + " Minutes, ");
        if(time_sec > 0)
            System.out.print(time_sec % 60 + " Seconds, ");
        if(time_ms > 0)
            System.out.print(time_ms % 1E+3 + " MicroSeconds, ");
        if(time_ns > 0)
            System.out.print(time_ns % 1E+6 + " NanoSeconds");
    }
}