我有一个JavaScript数组dataArray，我想把它推到一个新数组newArray。只是我不想让newArray[0]为dataArray。我想把所有的项都推入新数组:
var newArray = [];
newArray.pushValues(dataArray1);
newArray.pushValues(dataArray2);
// ...
或者更好:
var newArray = new Array (
dataArray1.values(),
dataArray2.values(),
// ... where values() (or something equivalent) would push the individual values into the array, rather than the array itself
);
现在新数组包含了各个数据数组的所有值。是否有一些像pushValues这样的速记可用，这样我就不必遍历每个单独的数据数组，逐个添加项?
当前回答
我提供了两种简单的方法:
解决方案1:
let dataArray1= [0, 1];
let dataArray1= [2, 3];
dataArray1.push(...dataArray2);
console.log(dataArray1)
解决方案2:
let dataArray1 = [1, 2];
let dataArray2 = [3, 4];
let newArray = dataArray1.concat(dataArray2);
console.log(newArray)
其他回答
var a=new Array('a','b','c');
var b=new Array('d','e','f');
var d=new Array('x','y','z');
var c=a.concat(b,d)
这能解决你的问题吗?
Тhis是一个工作代码，它工作得很好:
var els = document.getElementsByTagName('input'), i;
var invnum = new Array();
var k = els.length;
for(i = 0; i < k; i++){invnum.push(new Array(els[i].id,els[i].value))}
试试这个:
var arrayA = [1, 2];
var arrayB = [3, 4];
var newArray = arrayB.reduce((pre, cur) => [...pre, ...cur], arrayA);
console.log(newArray)
关于array。prototype。push。apply有很多答案。这里有一个明显的例子:
数据1 = [1,2]; 变量dataArray2 = [3,4,5]; var newArray = []; 阵列原型推送。apply (newArray, dataArray1);// newArray = [1,2] 阵列原型推送。apply (newArray, dataArray2);// newArray = [1,2,3,4,5] console . log (JSON stringify (newArray));//输出:[1、2、3、4、5]
如果你有ES6语法:
数据1 = [1,2]; 变量dataArray2 = [3,4,5]; var newArray = []; newArray。push (... dataArray1);// newArray = [1,2] newArray。push (... dataArray2);// newArray = [1,2,3,4,5] console . log (JSON stringify (newArray));//输出:[1、2、3、4、5]
我提供了两种简单的方法:
解决方案1:
let dataArray1= [0, 1];
let dataArray1= [2, 3];
dataArray1.push(...dataArray2);
console.log(dataArray1)
解决方案2:
let dataArray1 = [1, 2];
let dataArray2 = [3, 4];
let newArray = dataArray1.concat(dataArray2);
console.log(newArray)
