OP自己添加了以下答案，并附上了评论:

在回答和评论的帮助下，经过一些测试，我得出了这个结论:

function contains() {
    local n=$#
    local value=${!n}
    for ((i=1;i < $#;i++)) {
        if [ "${!i}" == "${value}" ]; then
            echo "y"
            return 0
        fi
    }
    echo "n"
    return 1
}

A=("one" "two" "three four")
if [ $(contains "${A[@]}" "one") == "y" ]; then
    echo "contains one"
fi
if [ $(contains "${A[@]}" "three") == "y" ]; then
    echo "contains three"
fi

另一个没有函数的代码:

(for e in "${array[@]}"; do [[ "$e" == "searched_item" ]] && exit 0; done) && echo "found" || echo "not found"

谢谢@Qwerty关于空格的提示!

对应的功能:

find_in_array() {
  local word=$1
  shift
  for e in "$@"; do [[ "$e" == "$word" ]] && return 0; done
  return 1
}

例子:

some_words=( these are some words )
find_in_array word "${some_words[@]}" || echo "expected missing! since words != word"

我通常只使用:

inarray=$(echo ${haystack[@]} | grep -o "needle" | wc -w)

非零值表示找到了匹配。

．.． 实际上，为了解决它不能与needle1和needle2工作的问题，如果你只想要一个精确匹配，没有更多，没有更少，只需在-o后面添加一个w标志，用于整个单词匹配:

inarray=$(echo ${haystack[@]} | grep -ow "needle" | wc -w)

以下是我对这个问题的看法。以下是简短的版本:

function arrayContains() {
        local haystack=${!1}
        local needle="$2"
        printf "%s\n" ${haystack[@]} | grep -q "^$needle$"
}

长一点的版本，我觉得看起来更舒服。

# With added utility function.
function arrayToLines() {
        local array=${!1}
        printf "%s\n" ${array[@]}
}

function arrayContains() {
        local haystack=${!1}
        local needle="$2"
        arrayToLines haystack[@] | grep -q "^$needle$"
}

例子:

test_arr=("hello" "world")
arrayContains test_arr[@] hello; # True
arrayContains test_arr[@] world; # True
arrayContains test_arr[@] "hello world"; # False
arrayContains test_arr[@] "hell"; # False
arrayContains test_arr[@] ""; # False

The answer with most votes is very concise and clean, but it can have false positives when a space is part of one of the array elements. This can be overcome when changing IFS and using "${array[*]}" instead of "${array[@]}". The method is identical, but it looks less clean. By using "${array[*]}", we print all elements of $array, separated by the first character in IFS. So by choosing a correct IFS, you can overcome this particular issue. In this particular case, we decide to set IFS to an uncommon character $'\001' which stands for Start of Heading (SOH)

$ array=("foo bar" "baz" "qux")
$ IFS=$'\001'
$ [[ "$IFS${array[*]}$IFS" =~ "${IFS}foo${IFS}" ]] && echo yes || echo no
no
$ [[ "$IFS${array[*]}$IFS" =~ "${IFS}foo bar${IFS}" ]] && echo yes || echo no
yes
$ unset IFS

这解决了大多数假阳性问题，但需要一个好的IFS选择。

注意:如果之前设置了IFS，最好保存并重新设置，而不是使用未设置的IFS

相关:

访问bash命令行参数$@ vs $*

如果你不想重复，这是值得研究的:

#!/bin/bash
myarray=("one" "two" "three");
wanted="two"
if `echo ${myarray[@]/"$wanted"/"WAS_FOUND"} | grep -q "WAS_FOUND" ` ; then
 echo "Value was found"
fi
exit

片段改编自:http://www.thegeekstuff.com/2010/06/bash-array-tutorial/ 我认为这很聪明。

编辑: 你可以这样做:

if `echo ${myarray[@]} | grep -q "$wanted"` ; then
echo "Value was found"
fi

但后者仅在数组包含唯一值时有效。我认为，在143中寻找1只会给出假阳性。