在解决方案属性中,我已经将我唯一的项目的配置设置为“发布”。

在主例程的开头,我有这样的代码,它显示“Mode=Debug”。 我在最上面还有这两行:

#define DEBUG 
#define RELEASE

我测试的变量对吗?

#if (DEBUG)
            Console.WriteLine("Mode=Debug"); 
#elif (RELEASE)
            Console.WriteLine("Mode=Release"); 
#endif

我的目标是根据调试和发布模式为变量设置不同的默认值。


当前回答

DEBUG/_DEBUG应该已经在VS中定义了。

在代码中删除#define DEBUG。在构建配置中为特定的构建设置预处理器。

它打印“Mode=Debug”的原因是因为你的#define,然后跳过elif。

正确的检查方法是:

#if DEBUG
    Console.WriteLine("Mode=Debug"); 
#else
    Console.WriteLine("Mode=Release"); 
#endif

不要检查RELEASE。

其他回答

如果您试图使用为构建类型定义的变量,您应该删除这两行…

#define DEBUG  
#define RELEASE 

... 这将导致#if (DEBUG)始终为真。

RELEASE也没有默认的条件编译符号。如果您想定义一个转到项目属性,单击Build选项卡,然后将RELEASE添加到General标题下的Conditional编译符号文本框中。

另一个选择是这样做……

#if DEBUG
    Console.WriteLine("Debug");
#else
    Console.WriteLine("Release");
#endif

删除定义并检查条件是否处于调试模式。你不需要检查指令是否处于释放模式。

就像这样:

#if DEBUG
     Console.WriteLine("Mode=Debug"); 
#else
    Console.WriteLine("Mode=Release"); 
#endif

删除顶部的定义

#if DEBUG
        Console.WriteLine("Mode=Debug"); 
#else
        Console.WriteLine("Mode=Release"); 
#endif

确保在“项目生成属性”中定义了DEBUG常量。这将启用#if DEBUG。我没有看到预定义的RELEASE常量,所以这可能意味着任何不在DEBUG块中的东西都是RELEASE模式。

It is worth noting here that one of the most significant differences between conditionally executing code based on #if DEBUG versus if(System.Diagnostics.Debugger.IsAttached) is that the compiler directive changes the code that is compiled. That is, if you have two different statements in an #if DEBUG/#else/#endif conditional block, only one of them will appear in the compiled code. This is an important distinction because it allows you do do things such as conditionally compile method definitions to be public void mymethod() versus internal void mymethod() depending on build type so that you can, for example, run unit tests on debug builds that will not break access control on production builds, or conditionally compile helper functions in debug builds that will not appear in the final code if they would violate security in some way should they escape into the wild. The IsAttached property, on the other hand, does not affect the compiled code. Both sets of code are in all of the builds - the IsAttached condition will only affect what is executed. This by itself can present a security issue.