在python3中，你可以使用pathlib模块(pathlib. python)。例如PurePath):

>>> import pathlib

>>> path = pathlib.PurePath('/folderA/folderB/folderC/folderD/')
>>> path.name
'folderD'

如果您想要文件所在的最后一个文件夹名称:

>>> path = pathlib.PurePath('/folderA/folderB/folderC/folderD/file.py')
>>> path.parent.name
'folderD'

str = "/folderA/folderB/folderC/folderD/"
print str.split("/")[-2]

path = "/folderA/folderB/folderC/folderD/"
last = path.split('/').pop()

以下是我的方法:

>>> import os
>>> print os.path.basename(
        os.path.dirname('/folderA/folderB/folderC/folderD/test.py'))
folderD
>>> print os.path.basename(
        os.path.dirname('/folderA/folderB/folderC/folderD/'))
folderD
>>> print os.path.basename(
        os.path.dirname('/folderA/folderB/folderC/folderD'))
folderC

在python3中，你可以使用pathlib模块(pathlib. python)。例如PurePath):

>>> import pathlib

>>> path = pathlib.PurePath('/folderA/folderB/folderC/folderD/')
>>> path.name
'folderD'

如果您想要文件所在的最后一个文件夹名称:

>>> path = pathlib.PurePath('/folderA/folderB/folderC/folderD/file.py')
>>> path.parent.name
'folderD'

我正在寻找一个解决方案，以获得文件所在的最后一个文件夹名，我只是使用分裂两次，以获得正确的部分。这不是问题，但谷歌把我调到了这里。

pathname = "/folderA/folderB/folderC/folderD/filename.py"
head, tail = os.path.split(os.path.split(pathname)[0])
print(head + "   "  + tail)