我想知道是否有一种在Android中以编程方式阅读手机模型的方法。

我想要一个像HTC梦想,里程碑,蓝宝石或任何字符串…


当前回答

对于谁谁寻找完整的属性列表构建这里是一个索尼Z1 Compact的例子:

Build.BOARD = MSM8974
Build.BOOTLOADER = s1
Build.BRAND = Sony
Build.CPU_ABI = armeabi-v7a
Build.CPU_ABI2 = armeabi
Build.DEVICE = D5503
Build.DISPLAY = 14.6.A.1.236
Build.FINGERPRINT = Sony/D5503/D5503:5.1.1/14.6.A.1.236/2031203XXX:user/release-keys
Build.HARDWARE = qcom
Build.HOST = BuildHost
Build.ID = 14.6.A.1.236
Build.IS_DEBUGGABLE = false
Build.MANUFACTURER = Sony
Build.MODEL = D5503
Build.PRODUCT = D5503
Build.RADIO = unknown
Build.SERIAL = CB5A1YGVMT
Build.SUPPORTED_32_BIT_ABIS = [Ljava.lang.String;@3dd90541
Build.SUPPORTED_64_BIT_ABIS = [Ljava.lang.String;@1da4fc3
Build.SUPPORTED_ABIS = [Ljava.lang.String;@525f635
Build.TAGS = release-keys
Build.TIME = 144792559XXXX
Build.TYPE = user
Build.UNKNOWN = unknown
Build.USER = BuildUser

你可以在调试模式下使用kotlin的“evaluate expression”对话框轻松列出这些属性:

android.os.Build::class.java.fields.map { "Build.${it.name} = ${it.get(it.name)}"}.joinToString("\n")

其他回答

Kotlin简写版:

import android.os.Build.MANUFACTURER
import android.os.Build.MODEL

fun getDeviceName(): String =
    if (MODEL.startsWith(MANUFACTURER, ignoreCase = true)) {
        MODEL
    } else {
        "$MANUFACTURER $MODEL"
    }.capitalize(Locale.ROOT)

你可以尝试跟随函数,它会以字符串格式返回你的phoneModel名字。

public String phoneModel() {

    return Build.MODEL;
}
String deviceName = android.os.Build.MODEL; // returns model name 

String deviceManufacturer = android.os.Build.MANUFACTURER; // returns manufacturer

使用以下方法以编程方式获取模型和制造商

  public String getDeviceName() {
        String manufacturer = Build.MANUFACTURER;
        String model = Build.MODEL;
        if (model.toLowerCase().startsWith(manufacturer.toLowerCase())) {
            return capitalize(model);
        } else {
            return capitalize(manufacturer) + " " + model;
        }
    }


    private String capitalize(String s) {
    if (s == null || s.length() == 0) {
        return "";
    }
    char first = s.charAt(0);
    if (Character.isUpperCase(first)) {
        return s;
    } else {
        return Character.toUpperCase(first) + s.substring(1);
    }

对于谁谁寻找完整的属性列表构建这里是一个索尼Z1 Compact的例子:

Build.BOARD = MSM8974
Build.BOOTLOADER = s1
Build.BRAND = Sony
Build.CPU_ABI = armeabi-v7a
Build.CPU_ABI2 = armeabi
Build.DEVICE = D5503
Build.DISPLAY = 14.6.A.1.236
Build.FINGERPRINT = Sony/D5503/D5503:5.1.1/14.6.A.1.236/2031203XXX:user/release-keys
Build.HARDWARE = qcom
Build.HOST = BuildHost
Build.ID = 14.6.A.1.236
Build.IS_DEBUGGABLE = false
Build.MANUFACTURER = Sony
Build.MODEL = D5503
Build.PRODUCT = D5503
Build.RADIO = unknown
Build.SERIAL = CB5A1YGVMT
Build.SUPPORTED_32_BIT_ABIS = [Ljava.lang.String;@3dd90541
Build.SUPPORTED_64_BIT_ABIS = [Ljava.lang.String;@1da4fc3
Build.SUPPORTED_ABIS = [Ljava.lang.String;@525f635
Build.TAGS = release-keys
Build.TIME = 144792559XXXX
Build.TYPE = user
Build.UNKNOWN = unknown
Build.USER = BuildUser

你可以在调试模式下使用kotlin的“evaluate expression”对话框轻松列出这些属性:

android.os.Build::class.java.fields.map { "Build.${it.name} = ${it.get(it.name)}"}.joinToString("\n")

这是我的代码,以获得制造商,品牌名称,Os版本和支持API级别

String manufacturer = Build.MANUFACTURER;

String model = Build.MODEL + " " + android.os.Build.BRAND +" ("
           + android.os.Build.VERSION.RELEASE+")"
           + " API-" + android.os.Build.VERSION.SDK_INT;

if (model.startsWith(manufacturer)) {
    return capitalize(model);
} else {
    return capitalize(manufacturer) + " " + model;
}

输出:

System.out: button press on device name = Lava Alfa L iris(5.0) API-21