在Python中如何将字符串截断为75个字符?
在JavaScript中是这样做的:
var data="saddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddsaddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddsadddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd"
var info = (data.length > 75) ? data.substring[0,75] + '..' : data;
当前回答
这里我使用的是文本包。缩短并处理更多的边缘情况。也包括最后一个单词的一部分，以防这个单词超过最大宽度的50%。
import textwrap
def shorten(text: str, width=30, placeholder="..."):
"""Collapse and truncate the given text to fit in the given width.
The text first has its whitespace collapsed. If it then fits in the *width*, it is returned as is.
Otherwise, as many words as possible are joined and then the placeholder is appended.
"""
if not text or not isinstance(text, str):
return str(text)
t = text.strip()
if len(t) <= width:
return t
# textwrap.shorten also throws ValueError if placeholder too large for max width
shorten_words = textwrap.shorten(t, width=width, placeholder=placeholder)
# textwrap.shorten doesn't split words, so if the text contains a long word without spaces, the result may be too short without this word.
# Here we use a different way to include the start of this word in case shorten_words is less than 50% of `width`
if len(shorten_words) - len(placeholder) < (width - len(placeholder)) * 0.5:
return t[:width - len(placeholder)].strip() + placeholder
return shorten_words
测试:
>>> shorten("123 456", width=7, placeholder="...")
'123 456'
>>> shorten("1 23 45 678 9", width=12, placeholder="...")
'1 23 45...'
>>> shorten("1 23 45 678 9", width=10, placeholder="...")
'1 23 45...'
>>> shorten("01 23456789", width=10, placeholder="...")
'01 2345...'
>>> shorten("012 3 45678901234567", width=17, placeholder="...")
'012 3 45678901...'
>>> shorten("1 23 45 678 9", width=9, placeholder="...")
'1 23...'
>>> shorten("1 23456", width=5, placeholder="...")
'1...'
>>> shorten("123 456", width=5, placeholder="...")
'12...'
>>> shorten("123 456", width=6, placeholder="...")
'123...'
>>> shorten("12 3456789", width=9, placeholder="...")
'12 345...'
>>> shorten(" 12 3456789 ", width=9, placeholder="...")
'12 345...'
>>> shorten('123 45', width=4, placeholder="...")
'1...'
>>> shorten('123 45', width=3, placeholder="...")
'...'
>>> shorten("123456", width=3, placeholder="...")
'...'
>>> shorten([1], width=9, placeholder="...")
'[1]'
>>> shorten(None, width=5, placeholder="...")
'None'
>>> shorten("", width=9, placeholder="...")
''
其他回答
info = data[:75] + ('..' if len(data) > 75 else '')
>>> info = lambda data: len(data)>10 and data[:10]+'...' or data
>>> info('sdfsdfsdfsdfsdfsdfsdfsdfsdfsdfsdf')
'sdfsdfsdfs...'
>>> info('sdfsdf')
'sdfsdf'
>>>
这里我使用的是文本包。缩短并处理更多的边缘情况。也包括最后一个单词的一部分，以防这个单词超过最大宽度的50%。
import textwrap
def shorten(text: str, width=30, placeholder="..."):
"""Collapse and truncate the given text to fit in the given width.
The text first has its whitespace collapsed. If it then fits in the *width*, it is returned as is.
Otherwise, as many words as possible are joined and then the placeholder is appended.
"""
if not text or not isinstance(text, str):
return str(text)
t = text.strip()
if len(t) <= width:
return t
# textwrap.shorten also throws ValueError if placeholder too large for max width
shorten_words = textwrap.shorten(t, width=width, placeholder=placeholder)
# textwrap.shorten doesn't split words, so if the text contains a long word without spaces, the result may be too short without this word.
# Here we use a different way to include the start of this word in case shorten_words is less than 50% of `width`
if len(shorten_words) - len(placeholder) < (width - len(placeholder)) * 0.5:
return t[:width - len(placeholder)].strip() + placeholder
return shorten_words
测试:
>>> shorten("123 456", width=7, placeholder="...")
'123 456'
>>> shorten("1 23 45 678 9", width=12, placeholder="...")
'1 23 45...'
>>> shorten("1 23 45 678 9", width=10, placeholder="...")
'1 23 45...'
>>> shorten("01 23456789", width=10, placeholder="...")
'01 2345...'
>>> shorten("012 3 45678901234567", width=17, placeholder="...")
'012 3 45678901...'
>>> shorten("1 23 45 678 9", width=9, placeholder="...")
'1 23...'
>>> shorten("1 23456", width=5, placeholder="...")
'1...'
>>> shorten("123 456", width=5, placeholder="...")
'12...'
>>> shorten("123 456", width=6, placeholder="...")
'123...'
>>> shorten("12 3456789", width=9, placeholder="...")
'12 345...'
>>> shorten(" 12 3456789 ", width=9, placeholder="...")
'12 345...'
>>> shorten('123 45', width=4, placeholder="...")
'1...'
>>> shorten('123 45', width=3, placeholder="...")
'...'
>>> shorten("123456", width=3, placeholder="...")
'...'
>>> shorten([1], width=9, placeholder="...")
'[1]'
>>> shorten(None, width=5, placeholder="...")
'None'
>>> shorten("", width=9, placeholder="...")
''
limit = 75
info = data[:limit] + '..' * (len(data) > limit)
这是另一种解决方案。在测试结束时，你会得到一些关于测试的反馈。
data = {True: data[:75] + '..', False: data}[len(data) > 75]
