是否有SQL语句可以返回表中列的类型?
当前回答
从SQL Server 2012开始:
SELECT * FROM sys.dm_exec_describe_first_result_set( N'SELECT * FROM [my].[Table]', NULL, 0 );
其他回答
要在上面的答案的基础上进行构建,获得列数据类型的格式与声明列的格式相同通常是很有用的。
例如,varchar(50), varchar(max), decimal(p, s)。
这允许你这样做:
SELECT
[Name] = c.[name]
, [Type] =
CASE
WHEN tp.[name] IN ('varchar', 'char', 'varbinary') THEN tp.[name] + '(' + IIF(c.max_length = -1, 'max', CAST(c.max_length AS VARCHAR(25))) + ')'
WHEN tp.[name] IN ('nvarchar','nchar') THEN tp.[name] + '(' + IIF(c.max_length = -1, 'max', CAST(c.max_length / 2 AS VARCHAR(25)))+ ')'
WHEN tp.[name] IN ('decimal', 'numeric') THEN tp.[name] + '(' + CAST(c.[precision] AS VARCHAR(25)) + ', ' + CAST(c.[scale] AS VARCHAR(25)) + ')'
WHEN tp.[name] IN ('datetime2') THEN tp.[name] + '(' + CAST(c.[scale] AS VARCHAR(25)) + ')'
ELSE tp.[name]
END
, [RawType] = tp.[name]
, [MaxLength] = c.max_length
, [Precision] = c.[precision]
, [Scale] = c.scale
, [IsNullable] = c.is_nullable
FROM sys.tables t
JOIN sys.schemas s ON t.schema_id = s.schema_id
JOIN sys.columns c ON t.object_id = c.object_id
JOIN sys.types tp ON c.user_type_id = tp.user_type_id
WHERE s.[name] = 'dbo' AND t.[name] = 'MyTable'
使用SQL Server:
SELECT DATA_TYPE
FROM INFORMATION_SCHEMA.COLUMNS
WHERE
TABLE_SCHEMA = 'yourSchemaName' AND
TABLE_NAME = 'yourTableName' AND
COLUMN_NAME = 'yourColumnName'
如果你正在使用MySQL,你可以试试
SHOW COLUMNS FROM `tbl_name`;
在dev.mysql.com上显示列
否则你应该能做到
DESCRIBE `tbl_name`;
使用此查询获取Schema, Table, Column,Type, max_length, is_nullable
SELECT QUOTENAME(SCHEMA_NAME(tb.[schema_id])) AS 'Schema'
,QUOTENAME(OBJECT_NAME(tb.[OBJECT_ID])) AS 'Table'
,C.NAME as 'Column'
,T.name AS 'Type'
,C.max_length
,C.is_nullable
FROM SYS.COLUMNS C INNER JOIN SYS.TABLES tb ON tb.[object_id] = C.[object_id]
INNER JOIN SYS.TYPES T ON C.system_type_id = T.user_type_id
WHERE tb.[is_ms_shipped] = 0
ORDER BY tb.[Name]
在TSQL/MSSQL中,它看起来像:
SELECT t.name, c.name
FROM sys.tables t
JOIN sys.columns c ON t.object_id = c.object_id
JOIN sys.types y ON y.user_type_id = c.user_type_id
WHERE t.name = ''
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