一些扩展Date的实现https://gist.github.com/netstart/c92e09730f3675ba8fb33be48520a86d

/**
 * just import, like
 *
 * import './../shared/utils/date.prototype.extendions.ts';
 */
declare global {
  interface Date {
    addDays(days: number, useThis?: boolean): Date;

    addSeconds(seconds: number): Date;

    addMinutes(minutes: number): Date;

    addHours(hours: number): Date;

    addMonths(months: number): Date;

    isToday(): boolean;

    clone(): Date;

    isAnotherMonth(date: Date): boolean;

    isWeekend(): boolean;

    isSameDate(date: Date): boolean;

    getStringDate(): string;
  }
}

Date.prototype.addDays = function(days: number): Date {
  if (!days) {
    return this;
  }
  this.setDate(this.getDate() + days);
  return this;
};

Date.prototype.addSeconds = function(seconds: number) {
  let value = this.valueOf();
  value += 1000 * seconds;
  return new Date(value);
};

Date.prototype.addMinutes = function(minutes: number) {
  let value = this.valueOf();
  value += 60000 * minutes;
  return new Date(value);
};

Date.prototype.addHours = function(hours: number) {
  let value = this.valueOf();
  value += 3600000 * hours;
  return new Date(value);
};

Date.prototype.addMonths = function(months: number) {
  const value = new Date(this.valueOf());

  let mo = this.getMonth();
  let yr = this.getYear();

  mo = (mo + months) % 12;
  if (0 > mo) {
    yr += (this.getMonth() + months - mo - 12) / 12;
    mo += 12;
  } else {
    yr += ((this.getMonth() + months - mo) / 12);
  }

  value.setMonth(mo);
  value.setFullYear(yr);
  return value;
};

Date.prototype.isToday = function(): boolean {
  const today = new Date();
  return this.isSameDate(today);
};

Date.prototype.clone = function(): Date {
  return new Date(+this);
};

Date.prototype.isAnotherMonth = function(date: Date): boolean {
  return date && this.getMonth() !== date.getMonth();
};

Date.prototype.isWeekend = function(): boolean {
  return this.getDay() === 0 || this.getDay() === 6;
};

Date.prototype.isSameDate = function(date: Date): boolean {
  return date && this.getFullYear() === date.getFullYear() && this.getMonth() === date.getMonth() && this.getDate() === date.getDate();
};

Date.prototype.getStringDate = function(): string {
  // Month names in Brazilian Portuguese
  const monthNames = ['Janeiro', 'Fevereiro', 'Março', 'Abril', 'Maio', 'Junho', 'Julho', 'Agosto', 'Setembro', 'Outubro', 'Novembro', 'Dezembro'];
  // Month names in English
  // let monthNames = ['January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December'];
  const today = new Date();
  if (this.getMonth() === today.getMonth() && this.getDay() === today.getDay()) {
    return 'Hoje';
    // return "Today";
  } else if (this.getMonth() === today.getMonth() && this.getDay() === today.getDay() + 1) {
    return 'Amanhã';
    // return "Tomorrow";
  } else if (this.getMonth() === today.getMonth() && this.getDay() === today.getDay() - 1) {
    return 'Ontem';
    // return "Yesterday";
  } else {
    return this.getDay() + ' de ' + this.monthNames[this.getMonth()] + ' de ' + this.getFullYear();
    // return this.monthNames[this.getMonth()] + ' ' + this.getDay() + ', ' +  this.getFullYear();
  }
};


export {};

感谢Jason的回答，您的回答符合预期，这里是您的代码和AnthonyWJones的便捷格式的混合：

Date.prototype.addDays = function(days){
    var ms = new Date().getTime() + (86400000 * days);
    var added = new Date(ms);
    return added;
}

我们的团队认为date fns是这个领域最好的图书馆。它将日期视为不可变的（Moment.js可能永远不会采用不变性），速度更快，可以模块化加载。

const newDate = DateFns.addDays(oldDate, 2);

我真不敢相信，5年后，这条线索中没有捷径可走！SO：要获得一天中相同的时间，而不考虑夏季的干扰：

Date.prototype.addDays = function(days)
    {
    var dat = new Date( this.valueOf() )

    var hour1 = dat.getHours()
    dat.setTime( dat.getTime() + days * 86400000) // 24*60*60*1000 = 24 hours
    var hour2 = dat.getHours()

    if (hour1 != hour2) // summertime occured +/- a WHOLE number of hours thank god!
        dat.setTime( dat.getTime() + (hour1 - hour2) * 3600000) // 60*60*1000 = 1 hour

    return dat
or
    this.setTime( dat.getTime() ) // to modify the object directly
    }

那里完成！

不使用第二个变量，您可以用接下来的x天替换7：

let d=new Date(new Date().getTime() + (7 * 24 * 60 * 60 * 1000));

我试图解决类似的问题，我更喜欢getTime方法，但有一些奇怪的基于时区的副作用。

ofc将“今天”替换为您需要的任何日期，并将时间也输入。关键是获取UTC时间，然后用毫秒来做加法，以避免这些副作用。

var now = new Date(Date.now());
var today = new Date(Date.UTC(now.getFullYear(), now.getMonth(), now.getDate()));

const dayInMs = 86400000; //24 hours
const tomorrow = new Date(today.getTime() + dayInMs);