我如何编写两个函数,如果它以指定的字符/字符串开头或以指定的字符串结尾,那么它们将接受字符串并返回?

例如:

$str = '|apples}';

echo startsWith($str, '|'); //Returns true
echo endsWith($str, '}'); //Returns true

当前回答

我会这样做

     function startWith($haystack,$needle){
              if(substr($haystack,0, strlen($needle))===$needle)
              return true;
        }

  function endWith($haystack,$needle){
              if(substr($haystack, -strlen($needle))===$needle)
              return true;
        }

其他回答

前面的许多答案也同样有效。然而,这可能是尽可能短的,你可以让它做你想做的事情。你只需要声明你希望它“回归真实”。因此,我包含了返回布尔值真/假和文本真/假的解决方案。

// boolean true/false
function startsWith($haystack, $needle)
{
    return strpos($haystack, $needle) === 0 ? 1 : 0;
}

function endsWith($haystack, $needle)
{
    return stripos($haystack, $needle) === 0 ? 1 : 0;
}


// textual true/false
function startsWith($haystack, $needle)
{
    return strpos($haystack, $needle) === 0 ? 'true' : 'false';
}

function endsWith($haystack, $needle)
{
    return stripos($haystack, $needle) === 0 ? 'true' : 'false';
}

我会这样做

     function startWith($haystack,$needle){
              if(substr($haystack,0, strlen($needle))===$needle)
              return true;
        }

  function endWith($haystack,$needle){
              if(substr($haystack, -strlen($needle))===$needle)
              return true;
        }

2016年8月23日更新

功能

function substr_startswith($haystack, $needle) {
    return substr($haystack, 0, strlen($needle)) === $needle;
}

function preg_match_startswith($haystack, $needle) {
    return preg_match('~' . preg_quote($needle, '~') . '~A', $haystack) > 0;
}

function substr_compare_startswith($haystack, $needle) {
    return substr_compare($haystack, $needle, 0, strlen($needle)) === 0;
}

function strpos_startswith($haystack, $needle) {
    return strpos($haystack, $needle) === 0;
}

function strncmp_startswith($haystack, $needle) {
    return strncmp($haystack, $needle, strlen($needle)) === 0;
}

function strncmp_startswith2($haystack, $needle) {
    return $haystack[0] === $needle[0]
        ? strncmp($haystack, $needle, strlen($needle)) === 0
        : false;
}

测验

echo 'generating tests';
for($i = 0; $i < 100000; ++$i) {
    if($i % 2500 === 0) echo '.';
    $test_cases[] = [
        random_bytes(random_int(1, 7000)),
        random_bytes(random_int(1, 3000)),
    ];
}
echo "done!\n";


$functions = ['substr_startswith', 'preg_match_startswith', 'substr_compare_startswith', 'strpos_startswith', 'strncmp_startswith', 'strncmp_startswith2'];
$results = [];

foreach($functions as $func) {
    $start = microtime(true);
    foreach($test_cases as $tc) {
        $func(...$tc);
    }
    $results[$func] = (microtime(true) - $start) * 1000;
}

asort($results);

foreach($results as $func => $time) {
    echo "$func: " . number_format($time, 1) . " ms\n";
}

结果(PHP 7.0.9)

(从最快到最慢排序)

strncmp_startswith2: 40.2 ms
strncmp_startswith: 42.9 ms
substr_compare_startswith: 44.5 ms
substr_startswith: 48.4 ms
strpos_startswith: 138.7 ms
preg_match_startswith: 13,152.4 ms

结果(PHP 5.3.29)

(从最快到最慢排序)

strncmp_startswith2: 477.9 ms
strpos_startswith: 522.1 ms
strncmp_startswith: 617.1 ms
substr_compare_startswith: 706.7 ms
substr_startswith: 756.8 ms
preg_match_startswith: 10,200.0 ms

启动基准.php

$ends_with = strrchr($text, '.'); // Ends with dot
$start_with = (0 === strpos($text, '.')); // Starts with dot

PHP 8更新

PHP 8包含了新的str_starts_with和str_ends_with函数,它们最终为这个问题提供了一个高效便捷的解决方案:

$str = "beginningMiddleEnd";
if (str_starts_with($str, "beg")) echo "printed\n";
if (str_starts_with($str, "Beg")) echo "not printed\n";
if (str_ends_with($str, "End")) echo "printed\n";
if (str_ends_with($str, "end")) echo "not printed\n";

该特性的RFC提供了更多信息,同时也讨论了明显(但不那么明显)用户区域实现的优点和问题。