如何在Java中将字节大小转换为人类可读的格式?
比如1024应该变成“1 Kb”,1024*1024应该变成“1 Mb”。
我有点厌倦了为每个项目写这个实用方法。在Apache Commons中有这样的静态方法吗?
如何在Java中将字节大小转换为人类可读的格式?
比如1024应该变成“1 Kb”,1024*1024应该变成“1 Mb”。
我有点厌倦了为每个项目写这个实用方法。在Apache Commons中有这样的静态方法吗?
当前回答
private String bytesIntoHumanReadable(long bytes) {
long kilobyte = 1024;
long megabyte = kilobyte * 1024;
long gigabyte = megabyte * 1024;
long terabyte = gigabyte * 1024;
if ((bytes >= 0) && (bytes < kilobyte)) {
return bytes + " B";
} else if ((bytes >= kilobyte) && (bytes < megabyte)) {
return (bytes / kilobyte) + " KB";
} else if ((bytes >= megabyte) && (bytes < gigabyte)) {
return (bytes / megabyte) + " MB";
} else if ((bytes >= gigabyte) && (bytes < terabyte)) {
return (bytes / gigabyte) + " GB";
} else if (bytes >= terabyte) {
return (bytes / terabyte) + " TB";
} else {
return bytes + " Bytes";
}
}
其他回答
private static final String[] Q = new String[]{"", "K", "M", "G", "T", "P", "E"};
public String getAsString(long bytes)
{
for (int i = 6; i > 0; i--)
{
double step = Math.pow(1024, i);
if (bytes > step) return String.format("%3.1f %s", bytes / step, Q[i]);
}
return Long.toString(bytes);
}
创建接口:
public interface IUnits {
public String format(long size, String pattern);
public long getUnitSize();
}
创建StorageUnits类:
import java.text.DecimalFormat;
public class StorageUnits {
private static final long K = 1024;
private static final long M = K * K;
private static final long G = M * K;
private static final long T = G * K;
enum Unit implements IUnits {
TERA_BYTE {
@Override
public String format(long size, String pattern) {
return format(size, getUnitSize(), "TB", pattern);
}
@Override
public long getUnitSize() {
return T;
}
@Override
public String toString() {
return "Terabytes";
}
},
GIGA_BYTE {
@Override
public String format(long size, String pattern) {
return format(size, getUnitSize(), "GB", pattern);
}
@Override
public long getUnitSize() {
return G;
}
@Override
public String toString() {
return "Gigabytes";
}
},
MEGA_BYTE {
@Override
public String format(long size, String pattern) {
return format(size, getUnitSize(), "MB", pattern);
}
@Override
public long getUnitSize() {
return M;
}
@Override
public String toString() {
return "Megabytes";
}
},
KILO_BYTE {
@Override
public String format(long size, String pattern) {
return format(size, getUnitSize(), "kB", pattern);
}
@Override
public long getUnitSize() {
return K;
}
@Override
public String toString() {
return "Kilobytes";
}
};
String format(long size, long base, String unit, String pattern) {
return new DecimalFormat(pattern).format(
Long.valueOf(size).doubleValue() /
Long.valueOf(base).doubleValue()
) + unit;
}
}
public static String format(long size, String pattern) {
for(Unit unit : Unit.values()) {
if(size >= unit.getUnitSize()) {
return unit.format(size, pattern);
}
}
return ("???(" + size + ")???");
}
public static String format(long size) {
return format(size, "#,##0.#");
}
}
叫它:
class Main {
public static void main(String... args) {
System.out.println(StorageUnits.format(21885));
System.out.println(StorageUnits.format(2188121545L));
}
}
输出:
21.4kB
2GB
我使用了一个比公认答案稍作修改的方法:
public static String formatFileSize(long bytes) {
if (bytes <= 0)
return "";
if (bytes < 1000)
return bytes + " B";
CharacterIterator ci = new StringCharacterIterator("kMGTPE");
while (bytes >= 99_999) {
bytes /= 1000;
ci.next();
}
return String.format(Locale.getDefault(), "%.1f %cB", bytes / 1000.0, ci.current());
}
因为我想看到另一个输出:
SI
0: <--------- instead of 0 B
27: 27 B
999: 999 B
1000: 1.0 kB
1023: 1.0 kB
1024: 1.0 kB
1728: 1.7 kB
110592: 0.1 MB <--------- instead of 110.6 kB
7077888: 7.1 MB
452984832: 0.5 GB <--------- instead of 453.0 MB
28991029248: 29.0 GB
如果你使用Android,你可以简单地使用Android .text.format. formatter . formatfilesize()。它的优点是易于使用,并且它取决于区域设置,以便为用户更好地显示它。缺点是它不处理EB,而且它只用于公制单位(每个Kilo是1000字节,不能作为1024字节使用)。
或者,这里有一个基于这篇热门文章的解决方案:
interface BytesFormatter {
/**called when the type of the result to format is Long. Example: 123KB
* @param unitPowerIndex the unit-power we need to format to. Examples: 0 is bytes, 1 is kb, 2 is mb, etc...
* available units and their order: B,K,M,G,T,P,E
* @param isMetric true if each kilo==1000, false if kilo==1024
* */
fun onFormatLong(valueToFormat: Long, unitPowerIndex: Int, isMetric: Boolean): String
/**called when the type of the result to format is Double. Example: 1.23KB
* @param unitPowerIndex the unit-power we need to format to. Examples: 0 is bytes, 1 is kb, 2 is mb, etc...
* available units and their order: B,K,M,G,T,P,E
* @param isMetric true if each kilo==1000, false if kilo==1024
* */
fun onFormatDouble(valueToFormat: Double, unitPowerIndex: Int, isMetric: Boolean): String
}
/**
* formats the bytes to a human readable format, by providing the values to format later in the unit that we've found best to fit it
*
* @param isMetric true if each kilo==1000, false if kilo==1024
* */
fun bytesIntoHumanReadable(
@IntRange(from = 0L) bytesToFormat: Long, bytesFormatter: BytesFormatter,
isMetric: Boolean = true
): String {
val units = if (isMetric) 1000L else 1024L
if (bytesToFormat < units)
return bytesFormatter.onFormatLong(bytesToFormat, 0, isMetric)
var bytesLeft = bytesToFormat
var unitPowerIndex = 0
while (unitPowerIndex < 6) {
val newBytesLeft = bytesLeft / units
if (newBytesLeft < units) {
val byteLeftAsDouble = bytesLeft.toDouble() / units
val needToShowAsInteger =
byteLeftAsDouble == (bytesLeft / units).toDouble()
++unitPowerIndex
if (needToShowAsInteger) {
bytesLeft = newBytesLeft
break
}
return bytesFormatter.onFormatDouble(byteLeftAsDouble, unitPowerIndex, isMetric)
}
bytesLeft = newBytesLeft
++unitPowerIndex
}
return bytesFormatter.onFormatLong(bytesLeft, unitPowerIndex, isMetric)
}
Sample usage:
// val valueToTest = 2_000L
// val valueToTest = 2_000_000L
// val valueToTest = 2_000_000_000L
// val valueToTest = 9_000_000_000_000_000_000L
// val valueToTest = 9_200_000_000_000_000_000L
val bytesToFormat = Random.nextLong(Long.MAX_VALUE)
val bytesFormatter = object : BytesFormatter {
val numberFormat = NumberFormat.getNumberInstance(Locale.ROOT).also {
it.maximumFractionDigits = 2
it.minimumFractionDigits = 0
}
private fun formatByUnit(formattedNumber: String, threePowerIndex: Int, isMetric: Boolean): String {
val sb = StringBuilder(formattedNumber.length + 4)
sb.append(formattedNumber)
val unitsToUse = "B${if (isMetric) "k" else "K"}MGTPE"
sb.append(unitsToUse[threePowerIndex])
if (threePowerIndex > 0)
if (isMetric) sb.append('B') else sb.append("iB")
return sb.toString()
}
override fun onFormatLong(valueToFormat: Long, unitPowerIndex: Int, isMetric: Boolean): String {
return formatByUnit(String.format("%,d", valueToFormat), unitPowerIndex, isMetric)
}
override fun onFormatDouble(valueToFormat: Double, unitPowerIndex: Int, isMetric: Boolean): String {
//alternative for using numberFormat :
//val formattedNumber = String.format("%,.2f", valueToFormat).let { initialFormattedString ->
// if (initialFormattedString.contains('.'))
// return@let initialFormattedString.dropLastWhile { it == '0' }
// else return@let initialFormattedString
//}
return formatByUnit(numberFormat.format(valueToFormat), unitPowerIndex, isMetric)
}
}
Log.d("AppLog", "formatting of $bytesToFormat bytes (${String.format("%,d", bytesToFormat)})")
Log.d("AppLog", bytesIntoHumanReadable(bytesToFormat, bytesFormatter))
Log.d("AppLog", "Android:${android.text.format.Formatter.formatFileSize(this, bytesToFormat)}")
有趣的事实:这里发布的原始代码片段是Stack Overflow上被复制最多的Java代码片段,它是有缺陷的。它被修好了,但却变得一团糟。 本文的完整故事:有史以来复制最多的堆栈溢出代码片段是有缺陷的!
来源:格式化字节大小到人类可读的格式|编程。指南
SI(1 k = 1,000)
public static String humanReadableByteCountSI(long bytes) {
if (-1000 < bytes && bytes < 1000) {
return bytes + " B";
}
CharacterIterator ci = new StringCharacterIterator("kMGTPE");
while (bytes <= -999_950 || bytes >= 999_950) {
bytes /= 1000;
ci.next();
}
return String.format("%.1f %cB", bytes / 1000.0, ci.current());
}
二进制(1's = 1,024)
public static String humanReadableByteCountBin(long bytes) {
long absB = bytes == Long.MIN_VALUE ? Long.MAX_VALUE : Math.abs(bytes);
if (absB < 1024) {
return bytes + " B";
}
long value = absB;
CharacterIterator ci = new StringCharacterIterator("KMGTPE");
for (int i = 40; i >= 0 && absB > 0xfffccccccccccccL >> i; i -= 10) {
value >>= 10;
ci.next();
}
value *= Long.signum(bytes);
return String.format("%.1f %ciB", value / 1024.0, ci.current());
}
示例输出:
SI BINARY
0: 0 B 0 B
27: 27 B 27 B
999: 999 B 999 B
1000: 1.0 kB 1000 B
1023: 1.0 kB 1023 B
1024: 1.0 kB 1.0 KiB
1728: 1.7 kB 1.7 KiB
110592: 110.6 kB 108.0 KiB
7077888: 7.1 MB 6.8 MiB
452984832: 453.0 MB 432.0 MiB
28991029248: 29.0 GB 27.0 GiB
1855425871872: 1.9 TB 1.7 TiB
9223372036854775807: 9.2 EB 8.0 EiB (Long.MAX_VALUE)