假设你想要单引号之间的部分，使用一个Matcher正则表达式:

"'(.*?)'"

例子:

String mydata = "some string with 'the data i want' inside";
Pattern pattern = Pattern.compile("'(.*?)'");
Matcher matcher = pattern.matcher(mydata);
if (matcher.find())
{
    System.out.println(matcher.group(1));
}

结果:

the data i want

假设你想要单引号之间的部分，使用一个Matcher正则表达式:

"'(.*?)'"

例子:

String mydata = "some string with 'the data i want' inside";
Pattern pattern = Pattern.compile("'(.*?)'");
Matcher matcher = pattern.matcher(mydata);
if (matcher.find())
{
    System.out.println(matcher.group(1));
}

结果:

the data i want

String dataIWant = mydata.replaceFirst(".*'(.*?)'.*", "$1");

你可以用这个 我使用while循环存储所有匹配子字符串在数组中，如果你使用

如果(matcher.find ()) ｛ System.out.println (matcher.group (1)); ｝

你会得到匹配子串所以你可以用这个来获取所有匹配子串

Matcher m = Pattern.compile("[a-zA-Z0-9_.+-]+@[a-zA-Z0-9-]+\\.[a-zA-Z0-9-.]+").matcher(text);
   // Matcher  mat = pattern.matcher(text);
    ArrayList<String>matchesEmail = new ArrayList<>();
        while (m.find()){
            String s = m.group();
            if(!matchesEmail.contains(s))
                matchesEmail.add(s);
        }

    Log.d(TAG, "emails: "+matchesEmail);

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Test {
    public static void main(String[] args) {
        Pattern pattern = Pattern.compile(".*'([^']*)'.*");
        String mydata = "some string with 'the data i want' inside";

        Matcher matcher = pattern.matcher(mydata);
        if(matcher.matches()) {
            System.out.println(matcher.group(1));
        }

    }
}

String dataIWant = mydata.split("'")[1];

参见现场演示