我有一个列表，我想从其中删除一个元素。我该怎么做呢?
我试着在参考手册中查找我认为这个函数的明显名称，但我没有找到任何合适的名称。
当前回答
rlist包(http://cran.r-project.org/web/packages/rlist/index.html)用于处理各种列表操作。
示例(http://cran.r-project.org/web/packages/rlist/vignettes/Filtering.html):
library(rlist)
devs <-
list(
p1=list(name="Ken",age=24,
interest=c("reading","music","movies"),
lang=list(r=2,csharp=4,python=3)),
p2=list(name="James",age=25,
interest=c("sports","music"),
lang=list(r=3,java=2,cpp=5)),
p3=list(name="Penny",age=24,
interest=c("movies","reading"),
lang=list(r=1,cpp=4,python=2)))
list.remove(devs, c("p1","p2"))
结果:
# $p3
# $p3$name
# [1] "Penny"
#
# $p3$age
# [1] 24
#
# $p3$interest
# [1] "movies" "reading"
#
# $p3$lang
# $p3$lang$r
# [1] 1
#
# $p3$lang$cpp
# [1] 4
#
# $p3$lang$python
# [1] 2
其他回答
rlist包(http://cran.r-project.org/web/packages/rlist/index.html)用于处理各种列表操作。
示例(http://cran.r-project.org/web/packages/rlist/vignettes/Filtering.html):
library(rlist)
devs <-
list(
p1=list(name="Ken",age=24,
interest=c("reading","music","movies"),
lang=list(r=2,csharp=4,python=3)),
p2=list(name="James",age=25,
interest=c("sports","music"),
lang=list(r=3,java=2,cpp=5)),
p3=list(name="Penny",age=24,
interest=c("movies","reading"),
lang=list(r=1,cpp=4,python=2)))
list.remove(devs, c("p1","p2"))
结果:
# $p3
# $p3$name
# [1] "Penny"
#
# $p3$age
# [1] 24
#
# $p3$interest
# [1] "movies" "reading"
#
# $p3$lang
# $p3$lang$r
# [1] 1
#
# $p3$lang$cpp
# [1] 4
#
# $p3$lang$python
# [1] 2
下面是如何在R中删除列表的最后一个元素:
x <- list("a", "b", "c", "d", "e")
x[length(x)] <- NULL
如果x可能是一个向量，那么你需要创建一个新对象:
x <- c("a", "b", "c", "d", "e")
x <- x[-length(x)]
处理列表和向量
我想补充的是，如果它是一个命名列表，你可以简单地使用。
l <- list(a = 1, b = 2)
> within(l, rm(a))
$b
[1] 2
所以你可以覆盖原来的列表
l <- within(l, rm(a))
从列表l中删除名为a的元素。
在命名列表的情况下，我发现这些helper函数很有用
member <- function(list,names){
## return the elements of the list with the input names
member..names <- names(list)
index <- which(member..names %in% names)
list[index]
}
exclude <- function(list,names){
## return the elements of the list not belonging to names
member..names <- names(list)
index <- which(!(member..names %in% names))
list[index]
}
aa <- structure(list(a = 1:10, b = 4:5, fruits = c("apple", "orange"
)), .Names = c("a", "b", "fruits"))
> aa
## $a
## [1] 1 2 3 4 5 6 7 8 9 10
## $b
## [1] 4 5
## $fruits
## [1] "apple" "orange"
> member(aa,"fruits")
## $fruits
## [1] "apple" "orange"
> exclude(aa,"fruits")
## $a
## [1] 1 2 3 4 5 6 7 8 9 10
## $b
## [1] 4 5
单行从列表中删除Null元素:
x = x(((酸式焦磷酸钠(x, is.null) arr.ind = TRUE)))
干杯
