我有一个字典,我需要通过使用字典生成一个JSON字符串。可以转换吗?你们能帮帮我吗?
当前回答
这里有NSArray和NSDictionary的类别,让这个超级简单。我添加了一个漂亮打印的选项(换行符和制表符使阅读更容易)。
@interface NSDictionary (BVJSONString)
-(NSString*) bv_jsonStringWithPrettyPrint:(BOOL) prettyPrint;
@end
.
@implementation NSDictionary (BVJSONString)
-(NSString*) bv_jsonStringWithPrettyPrint:(BOOL) prettyPrint {
NSError *error;
NSData *jsonData = [NSJSONSerialization dataWithJSONObject:self
options:(NSJSONWritingOptions) (prettyPrint ? NSJSONWritingPrettyPrinted : 0)
error:&error];
if (! jsonData) {
NSLog(@"%s: error: %@", __func__, error.localizedDescription);
return @"{}";
} else {
return [[NSString alloc] initWithData:jsonData encoding:NSUTF8StringEncoding];
}
}
@end
.
@interface NSArray (BVJSONString)
- (NSString *)bv_jsonStringWithPrettyPrint:(BOOL)prettyPrint;
@end
.
@implementation NSArray (BVJSONString)
-(NSString*) bv_jsonStringWithPrettyPrint:(BOOL) prettyPrint {
NSError *error;
NSData *jsonData = [NSJSONSerialization dataWithJSONObject:self
options:(NSJSONWritingOptions) (prettyPrint ? NSJSONWritingPrettyPrinted : 0)
error:&error];
if (! jsonData) {
NSLog(@"%s: error: %@", __func__, error.localizedDescription);
return @"[]";
} else {
return [[NSString alloc] initWithData:jsonData encoding:NSUTF8StringEncoding];
}
}
@end
其他回答
您也可以通过在调试器中输入以下内容即时执行此操作
po [[NSString alloc] initWithData:[NSJSONSerialization dataWithJSONObject:yourDictionary options:1 error:nil] encoding:4];
在Swift中,我创建了以下helper函数:
class func nsobjectToJSON(swiftObject: NSObject) {
var jsonCreationError: NSError?
let jsonData: NSData = NSJSONSerialization.dataWithJSONObject(swiftObject, options: NSJSONWritingOptions.PrettyPrinted, error: &jsonCreationError)!
if jsonCreationError != nil {
println("Errors: \(jsonCreationError)")
}
else {
// everything is fine and we have our json stored as an NSData object. We can convert into NSString
let strJSON : NSString = NSString(data: jsonData, encoding: NSUTF8StringEncoding)!
println("\(strJSON)")
}
}
将NSDictionary转换为NSString:
NSError * err;
NSData * jsonData = [NSJSONSerialization dataWithJSONObject:myDictionary options:0 error:&err];
NSString * myString = [[NSString alloc] initWithData:jsonData encoding:NSUTF8StringEncoding];
在Swift 2.0版本中:
class func jsonStringWithJSONObject(jsonObject: AnyObject) throws -> String? {
let data: NSData? = try? NSJSONSerialization.dataWithJSONObject(jsonObject, options: NSJSONWritingOptions.PrettyPrinted)
var jsonStr: String?
if data != nil {
jsonStr = String(data: data!, encoding: NSUTF8StringEncoding)
}
return jsonStr
}
注:这个答案是在iOS 5发布之前给出的。
获取json-framework并执行以下操作:
#import "SBJsonWriter.h"
...
SBJsonWriter *jsonWriter = [[SBJsonWriter alloc] init];
NSString *jsonString = [jsonWriter stringWithObject:myDictionary];
[jsonWriter release];
myDictionary就是你的字典。