我有一个这样的字符串:
abc=foo&def=%5Basf%5D&xyz=5
如何将其转换为这样的JavaScript对象?
{
abc: 'foo',
def: '[asf]',
xyz: 5
}
当前回答
另一种基于URLSearchParams最新标准的解决方案(https://developer.mozilla.org/en-US/docs/Web/API/URLSearchParams)
function getQueryParamsObject() {
const searchParams = new URLSearchParams(location.search.slice(1));
return searchParams
? _.fromPairs(Array.from(searchParams.entries()))
: {};
}
请注意，这个解决方案是利用
Array.from (https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/from)
和lodash的_. fropairs (https://lodash.com/docs#fromPairs)，以便简单。
因为您可以访问searchParams.entries()迭代器，所以创建一个更兼容的解决方案应该很容易。
其他回答
这是一个简单的版本，显然你需要添加一些错误检查:
var obj = {};
var pairs = queryString.split('&');
for(i in pairs){
var split = pairs[i].split('=');
obj[decodeURIComponent(split[0])] = decodeURIComponent(split[1]);
}
//under ES6
const getUrlParamAsObject = (url = window.location.href) => {
let searchParams = url.split('?')[1];
const result = {};
//in case the queryString is empty
if (searchParams!==undefined) {
const paramParts = searchParams.split('&');
for(let part of paramParts) {
let paramValuePair = part.split('=');
//exclude the case when the param has no value
if(paramValuePair.length===2) {
result[paramValuePair[0]] = decodeURIComponent(paramValuePair[1]);
}
}
}
return result;
}
ES6有一个非常简单而不正确的答案:
console.log(
Object.fromEntries(new URLSearchParams(`abc=foo&def=%5Basf%5D&xyz=5`))
);
但是这一行代码不包括多个相同的键，你必须使用更复杂的东西:
function parseParams(params) {
const output = [];
const searchParams = new URLSearchParams(params);
// Set will return only unique keys()
new Set([...searchParams.keys()])
.forEach(key => {
output[key] = searchParams.getAll(key).length > 1 ?
searchParams.getAll(key) : // get multiple values
searchParams.get(key); // get single value
});
return output;
}
console.log(
parseParams('abc=foo&cars=Ford&cars=BMW&cars=Skoda&cars=Mercedes')
)
代码将生成如下结构:
[
abc: "foo"
cars: ["Ford", "BMW", "Skoda", "Mercedes"]
]
使用URLSearchParams JavaScript Web API非常简单，
var paramsString = "abc=foo&def=%5Basf%5D&xyz=5"; //returns an iterator object var searchParams = new URLSearchParams(paramsString); //Usage for (let p of searchParams) { console.log(p); } //Get the query strings console.log(searchParams.toString()); //You can also pass in objects var paramsObject = {abc:"forum",def:"%5Basf%5D",xyz:"5"} //returns an iterator object var searchParams = new URLSearchParams(paramsObject); //Usage for (let p of searchParams) { console.log(p); } //Get the query strings console.log(searchParams.toString());
# #的有用链接
URLSearchParams - Web api | MDN 简单的URL操作与URLSearchParams | Web |谷歌开发者
注意:IE不支持
我发现$. string .deparam是最完整的预构建解决方案(可以做嵌套对象等)。查看文档。
