我有对象数组person (int age;字符串名称;)。
我如何按名字的字母顺序排序这个数组,然后按年龄?
你会用哪种算法呢?
我有对象数组person (int age;字符串名称;)。
我如何按名字的字母顺序排序这个数组,然后按年龄?
你会用哪种算法呢?
当前回答
使用Java 8 Streams方法,在getter上引用方法…
// Create a stream...
var sortedList = persons.stream()
// sort it (does not sort the original list)...
.sorted(Comparator.comparing(Person::getName)
.thenComparing(Person::getAge));
// and collect to a new list
.collect(Collectors.toList());
集合到数组ist也可以:
persons.stream()
.sorted(Comparator.comparing(Person::getName)
.thenComparing(Person::getAge));
.toArray(String[]::new);
Java 8 Lambda方法……
//Sorts the original list Lambda style
persons.sort((p1, p2) -> {
if (p1.getName().compareTo(p2.getName()) == 0) {
return p1.getAge().compareTo(p2.getAge());
} else {
return p1.getName().compareTo(p2.getName());
}
});
最后……
// This syntax is similar to the Streams example above, but sorts the original list!!!
persons.sort(Comparator.comparing(Person::getName).thenComparing(Person::getAge));
其他回答
Guava的ComparisonChain提供了一种干净的方法。参考这个链接。
用于执行链式比较语句的实用程序。例如:
public int compareTo(Foo that) {
return ComparisonChain.start()
.compare(this.aString, that.aString)
.compare(this.anInt, that.anInt)
.compare(this.anEnum, that.anEnum, Ordering.natural().nullsLast())
.result();
}
对于那些能够使用Java 8流API的人来说,这里有一个更整洁的方法: lambda和排序
我正在寻找相当于c# LINQ:
.ThenBy(...)
我在Comparator上找到了Java 8的机制:
.thenComparing(...)
下面是演示算法的代码片段。
Comparator<Person> comparator = Comparator.comparing(person -> person.name);
comparator = comparator.thenComparing(Comparator.comparing(person -> person.age));
请查看上面的链接,以获得更简洁的方法,并解释Java的类型推断如何使其与LINQ相比定义起来更笨拙。
下面是完整的单元测试供参考:
@Test
public void testChainedSorting()
{
// Create the collection of people:
ArrayList<Person> people = new ArrayList<>();
people.add(new Person("Dan", 4));
people.add(new Person("Andi", 2));
people.add(new Person("Bob", 42));
people.add(new Person("Debby", 3));
people.add(new Person("Bob", 72));
people.add(new Person("Barry", 20));
people.add(new Person("Cathy", 40));
people.add(new Person("Bob", 40));
people.add(new Person("Barry", 50));
// Define chained comparators:
// Great article explaining this and how to make it even neater:
// http://blog.jooq.org/2014/01/31/java-8-friday-goodies-lambdas-and-sorting/
Comparator<Person> comparator = Comparator.comparing(person -> person.name);
comparator = comparator.thenComparing(Comparator.comparing(person -> person.age));
// Sort the stream:
Stream<Person> personStream = people.stream().sorted(comparator);
// Make sure that the output is as expected:
List<Person> sortedPeople = personStream.collect(Collectors.toList());
Assert.assertEquals("Andi", sortedPeople.get(0).name); Assert.assertEquals(2, sortedPeople.get(0).age);
Assert.assertEquals("Barry", sortedPeople.get(1).name); Assert.assertEquals(20, sortedPeople.get(1).age);
Assert.assertEquals("Barry", sortedPeople.get(2).name); Assert.assertEquals(50, sortedPeople.get(2).age);
Assert.assertEquals("Bob", sortedPeople.get(3).name); Assert.assertEquals(40, sortedPeople.get(3).age);
Assert.assertEquals("Bob", sortedPeople.get(4).name); Assert.assertEquals(42, sortedPeople.get(4).age);
Assert.assertEquals("Bob", sortedPeople.get(5).name); Assert.assertEquals(72, sortedPeople.get(5).age);
Assert.assertEquals("Cathy", sortedPeople.get(6).name); Assert.assertEquals(40, sortedPeople.get(6).age);
Assert.assertEquals("Dan", sortedPeople.get(7).name); Assert.assertEquals(4, sortedPeople.get(7).age);
Assert.assertEquals("Debby", sortedPeople.get(8).name); Assert.assertEquals(3, sortedPeople.get(8).age);
// Andi : 2
// Barry : 20
// Barry : 50
// Bob : 40
// Bob : 42
// Bob : 72
// Cathy : 40
// Dan : 4
// Debby : 3
}
/**
* A person in our system.
*/
public static class Person
{
/**
* Creates a new person.
* @param name The name of the person.
* @param age The age of the person.
*/
public Person(String name, int age)
{
this.age = age;
this.name = name;
}
/**
* The name of the person.
*/
public String name;
/**
* The age of the person.
*/
public int age;
@Override
public String toString()
{
if (name == null) return super.toString();
else return String.format("%s : %d", this.name, this.age);
}
}
使用Comparator,然后将对象放入Collection,然后Collections.sort();
class Person {
String fname;
String lname;
int age;
public Person() {
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
public String getFname() {
return fname;
}
public void setFname(String fname) {
this.fname = fname;
}
public String getLname() {
return lname;
}
public void setLname(String lname) {
this.lname = lname;
}
public Person(String fname, String lname, int age) {
this.fname = fname;
this.lname = lname;
this.age = age;
}
@Override
public String toString() {
return fname + "," + lname + "," + age;
}
}
public class Main{
public static void main(String[] args) {
List<Person> persons = new java.util.ArrayList<Person>();
persons.add(new Person("abc3", "def3", 10));
persons.add(new Person("abc2", "def2", 32));
persons.add(new Person("abc1", "def1", 65));
persons.add(new Person("abc4", "def4", 10));
System.out.println(persons);
Collections.sort(persons, new Comparator<Person>() {
@Override
public int compare(Person t, Person t1) {
return t.getAge() - t1.getAge();
}
});
System.out.println(persons);
}
}
你可以这样做:
List<User> users = Lists.newArrayList(
new User("Pedro", 12),
new User("Maria", 10),
new User("Rafael",12)
);
users.sort(
Comparator.comparing(User::getName).thenComparing(User::getAge)
);
使用Java 8 Streams方法,在getter上引用方法…
// Create a stream...
var sortedList = persons.stream()
// sort it (does not sort the original list)...
.sorted(Comparator.comparing(Person::getName)
.thenComparing(Person::getAge));
// and collect to a new list
.collect(Collectors.toList());
集合到数组ist也可以:
persons.stream()
.sorted(Comparator.comparing(Person::getName)
.thenComparing(Person::getAge));
.toArray(String[]::new);
Java 8 Lambda方法……
//Sorts the original list Lambda style
persons.sort((p1, p2) -> {
if (p1.getName().compareTo(p2.getName()) == 0) {
return p1.getAge().compareTo(p2.getAge());
} else {
return p1.getName().compareTo(p2.getName());
}
});
最后……
// This syntax is similar to the Streams example above, but sorts the original list!!!
persons.sort(Comparator.comparing(Person::getName).thenComparing(Person::getAge));