我怎样才能将我的JS对象转换为FormData?

我这样做的原因是,我有一个用~100个表单字段值构造的对象。

var item = {
   description: 'Some Item',
   price : '0.00',
   srate : '0.00',
   color : 'red',
   ...
   ...
}

现在我被要求将上传文件功能添加到我的表单,当然,通过JSON是不可能的,所以我计划移动到FormData。那么有什么方法可以将我的JS对象转换为FormData呢?


当前回答

很简单,可以这样做:

var item: { some1: "ajbd" , some2: "dds".. }
let myFormData = new FormData();
      
       const abc = item.some1;
       const xyz = item.some2;

          myFormData.append('field1', abc);
          myFormData.append('field2', xyz);
    
    fetch('http:url', {
      method: 'POST',
      headers: {
        'Content-Type': false,
      },
      body: myFormData,
    }).
do promise ..

其他回答

我可能有点晚了,但这就是我创建的将单个对象转换为FormData的方法。

function formData(formData, filesIgnore = []) {
  let data = new FormData();

  let files = filesIgnore;

  Object.entries(formData).forEach(([key, value]) => {
    if (typeof value === 'object' && !files.includes(key)) {
      data.append(key, JSON.stringify(value) || null);
    } else if (files.includes(key)) {
      data.append(key, value[0] || null);
    } else {
      data.append(key, value || null);
    }
  })

  return data;
}

它是如何工作的? 它将转换并返回所有属性,除了您在忽略列表中设置的File对象(第二个参数)。如果有人能告诉我一个更好的方法来确定这将有帮助!)变成一个json字符串使用json .stringify。然后在您的服务器上,您只需要将其转换回JSON对象。

例子:

let form = {
  first_name: 'John',
  last_name: 'Doe',
  details: {
    phone_number: 1234 5678 910,
    address: '123 Some Street',
  },
  profile_picture: [object FileList] // set by your form file input. Currently only support 1 file per property.
}

function submit() {
  let data = formData(form, ['profile_picture']);

  axios.post('/url', data).then(res => {
    console.log('object uploaded');
  })
}

我仍然有点新的Http请求和JavaScript,所以任何反馈将高度赞赏!

使用ES6和更函数式的编程方法@adeneo的答案可能是这样的:

function getFormData(object) {
    const formData = new FormData();
    Object.keys(object).forEach(key => formData.append(key, object[key]));
    return formData;
}

或者使用.reduce()和箭头函数:

const getFormData = object => Object.keys(object).reduce((formData, key) => {
    formData.append(key, object[key]);
    return formData;
}, new FormData());

很简单,可以这样做:

var item: { some1: "ajbd" , some2: "dds".. }
let myFormData = new FormData();
      
       const abc = item.some1;
       const xyz = item.some2;

          myFormData.append('field1', abc);
          myFormData.append('field2', xyz);
    
    fetch('http:url', {
      method: 'POST',
      headers: {
        'Content-Type': false,
      },
      body: myFormData,
    }).
do promise ..

该函数将object中的所有数据添加到FormData中

ES6版本来自@developer033:

function buildFormData(formData, data, parentKey) {
  if (data && typeof data === 'object' && !(data instanceof Date) && !(data instanceof File)) {
    Object.keys(data).forEach(key => {
      buildFormData(formData, data[key], parentKey ? `${parentKey}[${key}]` : key);
    });
  } else {
    const value = data == null ? '' : data;

    formData.append(parentKey, value);
  }
}

function jsonToFormData(data) {
  const formData = new FormData();
  
  buildFormData(formData, data);
  
  return formData;
}

const my_data = {
  num: 1,
  falseBool: false,
  trueBool: true,
  empty: '',
  und: undefined,
  nullable: null,
  date: new Date(),
  name: 'str',
  another_object: {
    name: 'my_name',
    value: 'whatever'
  },
  array: [
    {
      key1: {
        name: 'key1'
      }
    }
  ]
};

jsonToFormData(my_data)

jQuery版本:

function appendFormdata(FormData, data, name){
    name = name || '';
    if (typeof data === 'object'){
        $.each(data, function(index, value){
            if (name == ''){
                appendFormdata(FormData, value, index);
            } else {
                appendFormdata(FormData, value, name + '['+index+']');
            }
        })
    } else {
        FormData.append(name, data);
    }
}


var formData = new FormData(),
    your_object = {
        name: 'test object',
        another_object: {
            name: 'and other objects',
            value: 'whatever'
        }
    };
appendFormdata(formData, your_object); 

尝试JSON。函数如下所示

var postData = JSON.stringify(item);
var formData = new FormData();
formData.append("postData",postData );